Chapter 8: Problem 165
What is the minimum \(\mathrm{pH}\) required to prevent the precipitation of \(\mathrm{ZnS}\) in a solution that is \(0.01 \mathrm{M} \mathrm{ZnCl}_{2}\) and saturated with \(0.10 \mathrm{M} \mathrm{H}_{2} \mathrm{~S} ?\) [Given: \(\mathrm{K}_{\mathrm{sp}}\) of \(\mathrm{ZnS}=10^{-21}, \mathrm{~K}_{2_{1}} \times \mathrm{K}_{\mathrm{a}_{2}}\) of \(\left.\mathrm{H}_{2} \mathrm{~S}=10^{-20}\right]\) (a) 4 (b) 3 (c) 2 (d) 1
Short Answer
Step by step solution
Write the equilibrium expressions
Express [S2-] in terms of pH
Set up the equation for precipitation prevention
Solve for [H+]
Calculate the pH
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Ksp (Solubility Product Constant)
For example, in the dissolution of zinc sulfide \( (\mathrm{ZnS}) \), the equilibrium expression can be written as:
- \( \mathrm{ZnS} \rightleftharpoons \mathrm{Zn}^{2+} + \mathrm{S}^{2-} \)
- The \( K_{sp} = [\mathrm{Zn}^{2+}][\mathrm{S}^{2-}] \)
Equilibrium Expressions
For our problem with zinc sulfide and hydrogen sulfide, equilibrium expressions are used to show how different substances dissociate and how their ions relate:
- \( \mathrm{ZnS} \rightleftharpoons \mathrm{Zn}^{2+} + \mathrm{S}^{2-} \)
- \( \mathrm{H}_2\mathrm{S} \rightleftharpoons \mathrm{H}^+ + \mathrm{HS}^- \)
- \( \mathrm{HS}^- \rightleftharpoons \mathrm{H}^+ + \mathrm{S}^{2-} \)
Chemical Precipitation
In our scenario with \( \mathrm{ZnS} \), we aim to avoid precipitation by controlling conditions to keep the ion product below the solubility product constant. Here's how that principle guides the solution:
- Ensure \( [\mathrm{Zn}^{2+}][\mathrm{S}^{2-}] < K_{sp} \)
- Leads to \( 0.01 \times \frac{[\mathrm{H}^+]^2}{10^{-20}} < 10^{-21} \)
Dissociation Constant (Ka)
The hydrogen sulfide has two dissociation constants because it can lose two hydrogen ions, each step having its equilibrium:
- \( \mathrm{H}_2\mathrm{S} \rightleftharpoons \mathrm{H}^+ + \mathrm{HS}^- \)
- \( \mathrm{HS}^- \rightleftharpoons \mathrm{H}^+ + \mathrm{S}^{2-} \)
Understanding \( K_a \) allows us to comprehend how much \( \mathrm{H}_2\mathrm{S} \) will dissociate into its ions in a solution, ultimately affecting the solution's acidity and the conditions under which precipitation will occur. By controlling the \( pH \), we manage these dissociations, effectively preventing unwanted precipitation of \( \mathrm{ZnS} \).