Chapter 7: Problem 48
In which of the following case, the value of \(\mathrm{K}_{\mathrm{p}}\) is less than \(\mathrm{K}_{\mathrm{c}} ?\) (a) \(\mathrm{N}_{2}+\mathrm{O}_{2} \rightleftharpoons 2 \mathrm{NO}\) (b) \(\mathrm{H}_{2}+\mathrm{Cl}_{2} \rightleftharpoons 2 \mathrm{HCl}\) (c) \(2 \mathrm{SO}_{2}+\mathrm{O}_{2} \rightleftharpoons 2 \mathrm{SO}_{3}\) (d) \(\mathrm{PCl}_{5} \rightleftharpoons \mathrm{PCl}_{3}+\mathrm{Cl}_{2}\)
Short Answer
Step by step solution
Understanding the Relationship Between Kp and Kc
Evaluate Delta n for Case (a)
Evaluate Delta n for Case (b)
Evaluate Delta n for Case (c)
Evaluate Delta n for Case (d)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Equilibrium Constant
- At equilibrium, the reaction appears to stop, but in reality, it reaches a state where the rates of the forward and reverse reactions are equal.
- For reactions in the gaseous phase, the equilibrium constant can be expressed both in terms of concentration \( K_{c} \) and in terms of pressure \( K_{p} \).
Understanding the equilibrium constant guides chemists in determining how a reaction behaves under different conditions and assists in predicting the outcome of reactions.
Gaseous Reactions
- For gaseous reactions, particularly those happening in closed vessels, the concentration of gases can be expressed as partial pressures, making \( K_{p} \) a valuable expression.
- Unlike solid and liquid reactions, changes in volume or pressure can significantly affect gaseous reactions.
Kp and Kc Relationship
- The relationship is given by the equation:\[K_{p} = K_{c} (RT)^{\Delta n}\]where \( R \) is the universal gas constant, \( T \) is the temperature in Kelvin, and \( \Delta n \) is the change in moles of gas (products minus reactants).
- \( \Delta n \) is crucial since it determines how \( K_{p} \) and \( K_{c} \) are related. When \( \Delta n \) is zero, these two constants are equal, but when it's not, \( K_{p} \) can be either greater or lesser than \( K_{c} \) depending on the sign of \( \Delta n \).
\( 2 SO_2 + O_2 \rightleftharpoons 2 SO_3 \)
The \( \Delta n = -1 \), leading to \( K_{p} = K_{c} (RT)^{-1} \), which results in \( K_{p} < K_{c} \). Comprehending these relationships is key to measuring reaction tendencies and making accurate predictions about the behavior of gaseous systems.