Chapter 4: Problem 181
A stream of electrons from a heated filament was passed between two charged plates kept at a potential difference \(\mathrm{V}\) esu. If e and \(\mathrm{m}\) are charge and mass of an electron, respectively, then the value of \(\mathrm{h} / \lambda\) (where \(\lambda\) is wavelength associated with electron wave) is given by: \([2016]\) (a) \(2 \mathrm{meV}\) (b) \(\sqrt{\mathrm{meV}}\) (c) \(\sqrt{2 \mathrm{meV}}\) (d) meV
Short Answer
Step by step solution
Understand the problem
Relation between velocity and potential difference
Apply De Broglie's hypothesis
Calculate the value of \( \frac{h}{\lambda} \)
Verify against options
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
De Broglie Wavelength
- \( \lambda \) is the De Broglie wavelength,
- \( h \) is Planck’s constant, and
- \( p \) is the momentum of the particle.
Kinetic Energy
- \( m \) is the mass of the electron, and
- \( v \) is its velocity.
Potential Difference
- \( e \) is the charge of the electron,
- \( V \) is the potential difference in volts.
Electron Velocity
- \( e \) is the charge of the electron,
- \( V \) is the potential difference, and
- \( m \) is the mass.