Chapter 3: Problem 160
Two closed bulbs of equal volume ( \(V\) ) containing an ideal gas initially at pressure \(P_{1}\) and temperature \(T_{1}\) are connected through a narrow tube of negligible volume as shown in the figure below. The temperature of one of the bulbs is then raised to \(T_{2}\). The final pressure \(p_{f}\) is (a) \(2 p_{t}\left(\frac{T_{1}}{T_{1}+T_{2}}\right)\) (b) \(2 p_{t}\left(\frac{T_{2}}{T_{1}+T_{2}}\right)\) (c) \(2 p_{i}\left(\frac{T_{1} T_{2}}{T_{1}+T_{2}}\right)\) (d) \(p_{t}\left(\frac{T_{1} T_{2}}{T_{1}+T_{2}}\right)\)
Short Answer
Step by step solution
Understand Initial Conditions
Apply Ideal Gas Law to Both Bulbs
Consider the Change in Temperature
Apply Conservation of Moles
Solve for Final Pressure \(P_f\)
Select the Correct Answer
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Pressure-Volume-Temperature Relationship
- Pressure of a gas increases if the temperature increases, assuming the volume remains constant.
- A drop in temperature results in decreased pressure if volume remains unchanged.
Conservation of Moles
Thermodynamics
- Energy conservation means the increase in temperature of one bulb must lead to a corresponding increase in energy resulted as pressure changes within the setup.
- Using thermodynamic principles to understand how heat affects molecular movement leading to pressure changes showcases the practical applications of these laws in real-life scenarios.
Gas Laws for JEE
- Boyle's Law: At constant temperature, the pressure of a gas is inversely proportional to its volume.
- Charles' Law: At constant pressure, the volume of a gas is directly proportional to its temperature.
- Avogadro's Law: Equal volumes of gases at the same temperature and pressure contain equal numbers of moles.