Chapter 27: Problem 143
When phenol is treated with \(\mathrm{CHCl}_{3}\) and \(\mathrm{NaOH}\) followed
by acidification, salicylaldehyde is obtained. Which of the following species
are involved in the above mentioned reaction as intermediates?
1 .
Short Answer
Step by step solution
Understand the Reaction
Recognizing Key Intermediates
Identifying the Enolate Ion Formation
Recognizing the Correct Intermediates
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Phenol Chemistry
- Hydrogen bonding: The hydroxyl group can form hydrogen bonds, which affect the solubility and boiling point of phenol.
- Acidity: Phenol is more acidic than alcohols because the phenoxide ion is resonance-stabilized, allowing it to easily lose a proton.
Intermediate Species
One key intermediate in this reaction is the phenoxide ion, formed by deprotonating phenol with NaOH. This anionic species is important because it is highly reactive.
- The phenoxide ion facilitates nucleophilic attacks due to its electron-rich nature.
- It acts as a nucleophile, attacking the dichlorocarbene generated during the reaction, which leads to further transformation of the molecule.
Dichlorocarbene
This makes it seek out electron-rich environments to stabilize itself.
- Dichlorocarbene is generated in situ from chloroform (\( \mathrm{CHCl}_{3} \)) when treated with a strong base like NaOH.
- This generation involves a base-induced elimination of hydrogen chloride, creating this transient carbene.
Organic Chemistry Reactions
- The reaction type: This is a substitution reaction where a substituent on the aromatic ring is replaced with an aldehyde group.
- Key Mechanism: The process showcases the generation of a carbene and its subsequent reactions. This involves generating dichlorocarbene which then adds to the phenoxide ion.