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Hydrogen peroxide: (a) Give silver peroxide with moist silver oxide (b) Turn the mixture of aniline, \(\mathrm{KClO}_{3}\) and dil. \(\mathrm{H}_{2} \mathrm{SO}_{4}\) violet (c) Liberate iodine from \(\mathrm{KI}\) (d) Turn the titanium salt yellow

Short Answer

Expert verified
Hydrogen peroxide can form silver peroxide, a violet dye with aniline mixtures, liberate iodine from KI, and turn titanium salts yellow.

Step by step solution

01

Understanding Hydrogen Peroxide Reactions

The exercise asks us about the different chemical reactions of hydrogen peroxide (Hâ‚‚Oâ‚‚). We need to understand how Hâ‚‚Oâ‚‚ interacts with other compounds in each scenario.
02

Decomposing Silver Peroxide from Silver Oxide

In reaction (a), when moist silver oxide (Agâ‚‚O) reacts with hydrogen peroxide (Hâ‚‚Oâ‚‚), it forms silver peroxide (AgO). Silver peroxide is a higher oxide of silver formed by this reaction.
03

Turning Aniline Mixture Violet

In reaction (b), when hydrogen peroxide is added to a mixture of aniline, potassium chlorate (KClO₃), and dilute sulfuric acid (H₂SO₄), a complex reaction occurs that results in the formation of a violet dye, likely involving oxidation processes.
04

Liberating Iodine from Potassium Iodide

In reaction (c), hydrogen peroxide oxidizes iodide ions in potassium iodide (KI) to iodine (Iâ‚‚). This redox reaction liberates iodine as a result of Hâ‚‚Oâ‚‚'s ability to act as an oxidizing agent.
05

Turning Titanium Salt Yellow

In reaction (d), hydrogen peroxide reacts with titanium salts to form a yellow complex. The yellow color comes from the formation of peroxo-titanium complexes as Hâ‚‚Oâ‚‚ interacts with titanium ions.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Silver Peroxide Formation
The reaction between moist silver oxide and hydrogen peroxide is a fascinating one. When these two compounds react, silver peroxide is formed. Silver oxide is represented by the formula Agâ‚‚O, while hydrogen peroxide is written as Hâ‚‚Oâ‚‚. When they interact, silver peroxide (AgO) is the product.

Silver peroxide is a higher oxide of silver. It displays unique properties compared to regular silver oxide. In terms of appearance, it may seem almost identical to the unreacted silver oxide. Yet, its formation marks a significant change in the chemical nature of the compound, demonstrating the ability of hydrogen peroxide to act as an oxidizing agent.
Aniline Oxidation
Another intriguing reaction involving hydrogen peroxide is its effect on an aniline mixture. When hydrogen peroxide is added to a mixture containing aniline, potassium chlorate (KClO₃), and dilute sulfuric acid (H₂SO₄), a violet color emerges.

This is the result of a complex series of reactions. Aniline, a simple organic compound with the formula C₆H₅NH₂, is susceptible to oxidation. In the presence of potassium chlorate and acid, hydrogen peroxide acts as an oxidizing agent. The precise products formed in these types of reactions can vary. However, the emergence of a violet dye suggests that a significant molecular transformation occurs, indicative of various oxidation processes.
Iodide Oxidation
Hydrogen peroxide's role as an oxidizing agent becomes evident in its reaction with potassium iodide. When hydrogen peroxide is introduced to KI, it transfers oxygen to iodide ions, oxidizing them into iodine ( Iâ‚‚ ).

This type of reaction is often termed a redox reaction—short for reduction-oxidation. In this specific case, hydrogen peroxide serves as the oxidizing agent that liberates iodine from the iodide ion, showcased by the appearance of iodine's characteristic brown color. This reaction further underscores the versatile role of hydrogen peroxide in various chemical processes.
Peroxo-Titanium Complexes
When hydrogen peroxide reacts with titanium salts, it produces a distinct yellow color, signaling the formation of peroxo-titanium complexes. These complexes form when the titanium ions present in the salt interact with the peroxide ions.

The specific shade of yellow is due to the geometrical and electronic arrangement in the complex, which can depend on the particular titanium salt and the conditions under which the reaction occurs. Peroxo-titanium complexes are notable in chemistry for their stability and color, often serving as an indicator of the reaction taking place.

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Most popular questions from this chapter

Which of the following is not correct regarding the electrolytic preparation of \(\mathrm{H}_{2} \mathrm{O}_{2}\) ? (a) sulphuric acid undergoes oxidation (b) hydrogen is liberated at anode (c) \(50 \% \mathrm{H}_{2} \mathrm{SO}_{4}\) is used (d) lead is used as cathode

A commercial sample of hydrogen peroxide is labelled as 10 volume, its percentage strength is (a) \(1 \%\) (b) \(3 \%\) (c) \(10 \%\) (d) \(90 \%\)

Find \([\mathrm{A}],[\mathrm{B}]\) and \([\mathrm{C}]\) respectively in the reaction given below: \([\mathrm{A}]+\mathrm{Na}\left[\mathrm{Cr}(\mathrm{OH})_{4}\right] \stackrel{\mathrm{H}_{2} \mathrm{O}_{2}, \text { boil }}{\longrightarrow}[\mathrm{B}] \stackrel{\mathrm{H}_{2} \mathrm{SO}_{4}}{\longrightarrow}[\mathrm{C}]\) Yellow Orange colour compound (a) \(\mathrm{NaOH}, \mathrm{Na}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}, \mathrm{Na}_{2} \mathrm{CrO}_{4}\) (b) \(\mathrm{NaOH}, \mathrm{Na}_{2} \mathrm{CrO}_{4}, \mathrm{Na}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}\) (c) \(\mathrm{H}_{2} \mathrm{O}, \mathrm{Na}_{2} \mathrm{CrO}_{4}, \mathrm{Na}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}\) (d) \(\mathrm{NaOH}, \mathrm{K}_{2} \mathrm{CrO}_{4}, \mathrm{Na}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}\)

\(\mathrm{N}\) forms \(\mathrm{NCl}_{3}\) whereas \(\mathrm{P}\) can form both \(\mathrm{PCl}_{3}\) and \(\mathrm{PCl}_{5}\). Why? (a) \(\mathrm{N}\) atoms is larger than \(\mathrm{P}\) in size (b) P has low lying \(3 \mathrm{~d}\) orbitals, which can be used for bonding but \(\mathrm{N}\) does not have \(3 \mathrm{~d}\) orbitals in its valence shell (c) \(\mathrm{P}\) is more reactive towards \(\mathrm{Cl}\) than \(\mathrm{N}\) (d) None of these

Which of the following is not correct? (a) Nitric oxide in solid state exhibits diamagnetic property. (b) \(\mathrm{NH}_{3}\) is a weak reducing agent compared to \(\mathrm{PH}_{3}\) (c) Hydrolysis of \(\mathrm{NCl}_{3}\) gives \(\mathrm{NH}_{3}\) and \(\mathrm{HOCl}\) (d) \(\mathrm{NH}_{3}\) is less stable than \(\mathrm{PH}_{3}\)

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