Chapter 13: Problem 143
According to molecular orbital theory which of the following statement about the magnetic character and bond order is correct regarding \(\mathrm{O}_{2}^{1}\) ? (a) paramagnetic and bond order \(<\mathrm{O}_{2}\) (b) paramagnetic and bond order \(>\mathrm{O}_{2}\) (c) diamagnetic and bond order \(<\mathrm{O}_{2}\) (d) diamagnetic and bond order \(>\mathrm{O}_{2}\)
Short Answer
Step by step solution
Understanding the Molecular Formula
Determine the Electronic Configuration for \(\mathrm{O}_2\)
Determine the Electronic Configuration for \(\mathrm{O}_2^{+1}\)
Calculate Bond Order of \(\mathrm{O}_2\)
Calculate Bond Order of \(\mathrm{O}_2^{+1}\)
Choose the Correct Statement
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Paramagnetism
For example,
- In the molecule \(O_2\), the presence of two unpaired electrons in the antibonding \(\pi^*_{2p}\) orbitals renders it paramagnetic.
- Similarly, when \(O_2\) loses an electron to become \(O_2^{1+}\), it still retains one unpaired electron, maintaining its paramagnetic character.
Bond Order
The formula for bond order is given by: \[ \text{Bond Order} = \frac{1}{2}(\text{number of bonding electrons} - \text{number of antibonding electrons}). \]
- For example, in neutral \(O_2\), with 10 bonding electrons and 6 antibonding electrons, the bond order is calculated as 2. This indicates a double bond.
- However, for \(O_2^{1+}\), after removing one antibonding electron, the bond order increases to 2.5. A higher bond order in \(O_2^{1+}\) indicates a more stable and stronger bond than that in \(O_2\).
Electron Configuration
Using molecular orbital theory, the electron configuration for a molecule like \(O_2\) is specified based on its occupied orbitals: \[ \sigma_{2s}^2, \sigma^*_{2s}^2, \sigma_{2p_z}^2, \pi_{2p_x}^2, \pi_{2p_y}^2, \pi^*_{2p_x}^1, \pi^*_{2p_y}^1. \]
- In molecular form \(O_2^{1+}\), losing an electron results in the change of configuration: \[ \sigma_{2s}^2, \sigma^*_{2s}^2, \sigma_{2p_z}^2, \pi_{2p_x}^2, \pi_{2p_y}^2, \pi^*_{2p_x}^1. \]
- This reduced number of electrons in the antibonding \(\pi^*_{2p}\) orbitals accounts for its increased bond order and paramagnetic property.