Chapter 13: Problem 115
The correct order of increasing \(\mathrm{C}-\mathrm{O}\) bond length of \(\mathrm{CO}, \mathrm{CO}_{3}^{2-}, \mathrm{CO}_{2}\) is (a) \(\mathrm{CO}_{3}^{2-}<\mathrm{CO}_{2}<\mathrm{CO}\) (b) \(\mathrm{CO}_{2}<\mathrm{CO}_{3}^{2^{2}}<\mathrm{CO}\) (c) \(\mathrm{CO}<\mathrm{CO}_{3}^{2-}<\mathrm{CO}_{2}\) (d) \(\mathrm{CO}<\mathrm{CO}_{2}<\mathrm{CO}_{2}^{2-}\)
Short Answer
Step by step solution
Understand Bond Orders
Determine Bond Order of CO
Determine Bond Order of CO2
Determine Bond Order of CO3^{2-}
Arrange Bond Orders
Identify Correct Option
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
C-O Bond
- Molecules can have single, double, or triple bonds.
- Higher bond orders usually result in shorter bond lengths.
Bond Order
- In carbon monoxide (\(CO\)), the C-O bond has a bond order of 3, indicating a triple bond.
- In carbon dioxide (\(CO_2\)), it features two double bonds, giving each C-O bond a bond order of 2.
- In the carbonate ion (\(CO_3^{2-}\)), the situation is more complex due to resonance, resulting in a calculated bond order of approximately 1.33.
Resonance Structures
- This ion can be represented by several structures with equivalent energy.
- These structures differ only in the position of electrons, not in the position of nuclei.
- Resonance structures imply that electrons are delocalized, meaning the actual bonding is a hybrid of all possible structures.
Triple Bond
- This high bond order means that the bond is particularly strong and short.
- Triple bonds are shorter and stronger than both single and double bonds.
- The presence of a triple bond implies a high degree of overlap between the orbitals of the bonded atoms.
Double Bond
- The double bond in \(CO_2\) consists of one sigma bond and one pi bond.
- Double bonds are stronger and shorter than single bonds but longer and weaker than triple bonds.
- In \(CO_2\), each C-O bond has a bond order of 2, which sets a moderate strength and intermediate bond length.