Chapter 12: Problem 155
The increasing order of the first ionization enthalpies of the element B, P, S and F (lowest first) is (a) \(\mathrm{F}<\mathrm{S}<\mathrm{P}<\mathrm{B}\) (b) \(\mathrm{P}<\mathrm{S}<\mathrm{B}<\mathrm{F}\) (c) \(\mathrm{B}<\mathrm{P}<\mathrm{S}<\mathrm{F}\) (d) \(\mathrm{B}<\mathrm{S}<\mathrm{P}<\mathrm{F}\)
Short Answer
Step by step solution
Understanding Ionization Enthalpy
Locate Elements in Periodic Table
Identify General Ionization Trends
Comparison Across Periods
Order the Elements by Ionization Enthalpy
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Periodic Table Trends
So, in summary:
- Across a period: Ionization enthalpy increases.
- Down a group: Ionization enthalpy decreases.
Nuclear Charge
When the nuclear charge increases, the pull on the electrons is stronger, resulting in higher ionization enthalpy. As you add more protons by moving across a period, electrons are pulled more tightly, which means it requires more energy to remove an electron.
Nuclear charge does the following:
- Increases from left to right across a period.
- Results in increased attraction between the nucleus and electron cloud.
Electron Removal Energy
- Atomic size: Larger atoms have electrons further from the nucleus, needing less energy for removal.
- Nuclear charge: A higher charge increases removal energy due to a stronger electron-nucleus attraction.
Tying back to periodic trends, note that as atomic size increases down a group, ionization energy reduces. Conversely, across a period, both atomic size and ionization energy trends point to increased electron removal energy as the relative nuclear charge dominates the scene.
Group and Period Comparison
Key considerations include:
- Comparison within a period: Look at position from left to right.
- Comparison within a group: Consider the influence of atomic size as you move down.