Chapter 10: Problem 115
For the reaction \(\mathrm{A} \longrightarrow\) Products, it is found that the rate of reaction increases by a factor of \(6.25\), when the concentration of \(\mathrm{A}\) is increased by a factor of \(2.5 .\) The order of reaction with respect to \(\mathrm{A}\) is (a) \(0.5\) (b) 1 (c) 2 (d) 3
Short Answer
Expert verified
The order of the reaction with respect to \( \mathrm{A} \) is 2.
Step by step solution
01
Understand the Rate Law Expression
The rate law for a reaction can be expressed as \( \text{rate} = k[A]^n \) where \( k \) is the rate constant, \([A]\) is the concentration of the reactant \( A \), and \( n \) is the order of the reaction with respect to \( A \). We need to find the value of \( n \).
02
Set Up the Initial and Final Rate Equations
Let the initial concentration of \( A \) be \([A]_1\) and the initial rate be \( \text{rate}_1 = k[A]_1^n \). After the concentration of \( A \) increases by a factor of 2.5, it becomes \( 2.5[A]_1 \). The new rate is \( \text{rate}_2 = k(2.5[A]_1)^n \).
03
Relate the Rate Change to the Concentration Change
We are told that the rate increases by a factor of 6.25, so \( \text{rate}_2 = 6.25 \times \text{rate}_1 \). Substitute the expressions from Step 2 to get:\[ k(2.5[A]_1)^n = 6.25 \times k[A]_1^n \].
04
Simplify the Equation
Cancel \( k \) and \([A]_1^n \) from both sides:\[ (2.5)^n = 6.25 \].
05
Solve for the Order \( n \)
Express 6.25 as a power of 2.5:\( 6.25 = (2.5)^2 \).Thus, the equation becomes:\[ (2.5)^n = (2.5)^2 \].Equating the exponents gives \( n = 2 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Rate Law Expression
The rate law expression is a fundamental concept in chemical kinetics, helping chemists understand how the concentration of reactants affects the rate of a chemical reaction. It typically takes the form \( \text{rate} = k[A]^n \), where \( k \) represents the rate constant, \([A]\) is the concentration of reactant \( A \), and \( n \) denotes the order of the reaction with respect to \( A \). Understanding this equation is crucial because it allows prediction of how different reactant concentrations impact reaction velocity.
- **Rate Constant \( k \)**: A unique value for every reaction at a given temperature, it remains unchanged during the reaction unless the temperature varies.
- **Concentration \([A]\)**: The amount of reactant present in the solution, usually measured in moles per liter.
- **Order of Reaction \( n \)**: Determines how sensitive the rate is to concentration changes.
Order of Reaction
The order of reaction with respect to a given reactant conveys how variations in reactant concentration influence the rate of a chemical reaction. The order, represented by \( n \) in the rate law equation, can be an integer or a fraction and is not necessarily equal to the stoichiometric coefficient of the reactant in the balanced chemical equation.
- If \( n = 0 \): The reaction rate is independent of the concentration of that reactant.
- If \( n = 1 \): The rate is directly proportional to the concentration of the reactant.
- If \( n = 2 \): The rate is proportional to the square of the concentration, meaning it is highly sensitive to concentration changes.
- If \( n = 2 \), as in our problem: Doubling the concentration of the reactant increases the reaction rate fourfold.
Concentration Change Effect
The concentration change effect refers to how the alteration in the concentration of a reactant impacts the speed at which a reaction proceeds. This is a direct consequence of the reaction order, and it illustrates the kinetic nature of chemical processes.
In the given problem, increasing the concentration of reactant \( A \) by a factor of 2.5 resulted in the rate of reaction increasing by a factor of 6.25. Such a relationship is pivotal in demonstrating the reaction's sensitivity to concentration changes and provides a clear example of a second-order reaction.
In the given problem, increasing the concentration of reactant \( A \) by a factor of 2.5 resulted in the rate of reaction increasing by a factor of 6.25. Such a relationship is pivotal in demonstrating the reaction's sensitivity to concentration changes and provides a clear example of a second-order reaction.
- **Small Changes, Big Effect**: Even modest increases in concentration can lead to significant rate enhancements, especially in higher-order reactions.
- **Predictive Power**: Understanding these effects is essential for predicting how a reaction will behave under different concentrations, essential for scaling up in industrial processes.
- **Illustrated by Experimentation**: Such effects are often examined through experiments where variables are carefully manipulated and observed.