Chapter 7: Problem 57
The solubility of a salt of weak acid \((A B)\) at \(\mathrm{pH} 3\) is \(\boldsymbol{Y} \times 10^{-3} \mathrm{~mol} \mathrm{~L}^{-1}\). The value of \(\boldsymbol{Y}\) is (Given that the value of solubility product of \(\boldsymbol{A B}\) \(\left(K_{s p}\right)=2 \times 10^{-10}\) and the value of ionization constant of \(\left.\boldsymbol{H B}\left(K_{a}\right)=1 \times 10^{-8}\right)\)
Short Answer
Step by step solution
Understand the Solubility Equilibrium
Write the Expression for Ksp
Write the Expression for Ka
Calculate [B^-] in Equilibrium with the Acid
Calculate the Total Solubility
Calculate Y
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Solubility Product
Ionization Constant
Weak Acid
- The behavior of weak acids is crucial for calculating total solubility, particularly when the acid's dissociation overlaps with a salt's solubility.
- In this exercise, understanding the weak acid's dynamics assists in determining how much \( B^- \) ions stem from each source — both the salt and the acid.
- By evaluating the weak acid's contribution, we ensure that we do not overestimate ion concentrations in solution.