/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 47 Amongst the following, the total... [FREE SOLUTION] | 91影视

91影视

Amongst the following, the total number of compounds whose aqueous solution turns red litmus paper blue is \(\mathrm{KCN}, \mathrm{K}_{2} \mathrm{SO}_{4},\left(\mathrm{NH}_{4}\right)_{2} \mathrm{C}_{2} \mathrm{O}_{4}, \mathrm{NaCl}, \mathrm{Zn}\left(\mathrm{NO}_{3}\right)_{2}, \mathrm{FeCl}_{3}, \mathrm{~K}_{2} \mathrm{CO}_{3}, \mathrm{NH}_{4} \mathrm{NO}_{3}\) and \(\mathrm{LiCN}\)

Short Answer

Expert verified
3 compounds turn red litmus paper blue: KCN, K鈧侰O鈧, and LiCN.

Step by step solution

01

Understand the Problem

We need to identify which of the given compounds will turn red litmus paper blue when dissolved in water. This indicates that the solution is basic (alkaline).
02

Analyze Each Compound's Nature

- **KCN (Potassium cyanide):** CN鈦 is a strong base, so KCN turns red litmus blue. - **K鈧係O鈧 (Potassium sulfate):** Neutral compound, does not change litmus color. - **(NH鈧)鈧侰鈧侽鈧 (Ammonium oxalate):** Weakly acidic; does not turn red litmus blue. - **NaCl (Sodium chloride):** Neutral solution, does not change litmus color. - **Zn(NO鈧)鈧 (Zinc nitrate):** Acidic due to hydrolysis; does not turn red litmus blue. - **FeCl鈧 (Ferric chloride):** Acidic due to hydrolysis; does not turn red litmus blue. - **K鈧侰O鈧 (Potassium carbonate):** CO鈧兟测伝 is a strong base, turns red litmus blue. - **NH鈧凬O鈧 (Ammonium nitrate):** Acidic solution; does not change litmus color. - **LiCN (Lithium cyanide):** CN鈦 is a strong base, so LiCN turns red litmus blue.
03

Count the Basic Solutions

From the analysis, the compounds that turn red litmus paper blue are KCN, K鈧侰O鈧, and LiCN. Thus, the number of such basic compounds is 3.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Litmus Paper Test
A litmus paper test is a simple yet effective way to determine the acidity or basicity of a solution. Litmus paper is made from specially treated paper that changes color when exposed to different pH levels. When you immerse litmus paper in a solution:
  • Red litmus paper will turn blue if the solution is basic (alkaline).
  • Blue litmus paper turns red in the presence of an acidic solution.

These color changes occur because dyes in the litmus paper react with the hydrogen or hydroxide ions in the solution. For example, in our exercise, red litmus paper turned blue when exposed to basic solutions like those of KCN, K鈧侰O鈧, and LiCN. This change indicated that these solutions were indeed basic because they produced more hydroxide ions in water. The litmus test is very helpful in quickly identifying the nature of a solution without needing elaborate equipment.
Aqueous Solutions
An aqueous solution is simply a solution where water is the solvent. This is the most common type of solution in chemistry because water is an excellent solvent due to its ability to dissolve many substances. In aqueous solutions:
  • The solute is the substance that is dissolved (e.g., KCN, NaCl).
  • The solvent is water, which facilitates the dissolution process.

When compounds like KCN, K鈧係O鈧, and NaCl dissolve in water, they dissociate into their respective ions. These ions interact with water, and the nature of this interaction determines if the solution will be acidic, neutral, or basic. For instance, if a compound releases hydroxide ions (OH鈦), the solution becomes basic, as seen with KCN and LiCN in our exercise. On the other hand, substances that release hydrogen ions (H鈦) tend to create acidic solutions, although that wasn't the focus here.
Basic Compounds
Basic compounds are substances that, when dissolved in water, increase the concentration of hydroxide ions (OH鈦) in the solution. This increase results in a pH greater than 7, indicating basicity. Such compounds often contain ions known to be bases, such as carbonate ( ext{CO}_3^{2-}) and cyanide ( ext{CN}^-).
  • Compounds like KCN and LiCN dissociate to form cyanide ions, which strongly attract protons and create hydroxide ions.
  • K鈧侰O鈧, or potassium carbonate, dissociates to form carbonate ions, which also results in a basic solution.

In practical scenarios, these basic solutions can turn red litmus paper blue, which is a clear visual indication of their basic nature. Understanding the properties of basic compounds helps predict their behavior in various chemical reactions and solutions, just like in our exercise where we identified the basic characteristics of certain compounds.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The following acids have been arranged in the order of decreasing acid strength. Identify the correct order. \(\mathrm{ClOH}\) (I), \(\mathrm{BrOH}(\mathrm{II}), \mathrm{IOH}(\mathrm{III})\) (a) \(\mathrm{I}>\mathrm{II}>\mathrm{III}\) (b) \(\mathrm{II}>\mathrm{I}>\mathrm{III}\) (c) \(\mathrm{III}>\mathrm{II}>\mathrm{I}\) (d) \(\mathrm{I}>\mathrm{III}>\mathrm{II}\)

The \(\mathrm{pH}\) of \(0.1 \mathrm{M}\) solution of the following salts increases in the order. (a) \(\mathrm{NaCl}<\mathrm{NH}_{4} \mathrm{Cl}<\mathrm{NaCN}<\mathrm{HCl}\) (b) \(\mathrm{HCl}<\mathrm{NH}_{4} \mathrm{Cl}<\mathrm{NaCl}<\mathrm{NaCN}\) (c) \(\mathrm{NaCN}<\mathrm{NH}_{4} \mathrm{Cl}<\mathrm{NaCl}<\mathrm{HCl}\) (d) \(\mathrm{HCl}<\mathrm{NaCl}<\mathrm{NaCN}<\mathrm{NH}_{4} \mathrm{Cl}\)

The value of \(\mathrm{Kc}\) is 64 at \(800 \mathrm{~K}\) for the reaction \(\mathrm{N}_{2}(\mathrm{~g})+3 \mathrm{H}_{2}(\mathrm{~g}) \rightleftharpoons 2 \mathrm{NH}_{3}(\mathrm{~g}) .\) The value of \(K_{\mathrm{c}}\) for the following reaction is : \(\mathrm{NH}_{3}(\mathrm{~g}) \rightleftharpoons \frac{1}{2} \mathrm{~N}_{2}(\mathrm{~g})+\frac{3}{2} \mathrm{H}_{2}(\mathrm{~g})\) (a) \(1 / 64\) (b) 8 (c) \(1 / 4\) (d) \(1 / 8\)

For the reversible reaction, \(\mathrm{N}_{2}(\mathrm{~g})+3 \mathrm{H}_{2}(\mathrm{~g}) \rightleftharpoons 2 \mathrm{NH}_{3}(\mathrm{~g})\) at \(500^{\circ} \mathrm{C}\), the value of \(K_{p}\) is \(1.44 \times 10^{-5}\) when partial pressure is measured in atmospheres. The corresponding value of \(K_{c}\), with concentration in mole litre \(^{-1}\), is (a) \(\frac{1.44 \times 10^{-5}}{(0.082 \times 500)^{-2}}\) (b) \(\frac{1.44 \times 10^{-5}}{(8.314 \times 773)^{-2}}\) (c) \(\frac{1.44 \times 10^{-5}}{(0.082 \times 773)^{2}}\) (d) \(\frac{1.44 \times 10^{-5}}{(0.082 \times 773)^{-2}}\)

Given : \(\mathrm{Ag}\left(\mathrm{NH}_{3}\right)_{2}^{+} \rightleftharpoons \mathrm{Ag}^{+}+2 \mathrm{NH}_{3}, K_{c}=6.2 \times 10^{-8}\) and \(K_{s p}\) of \(\mathrm{AgCl}=1.8 \times 10^{-10}\) at \(298 \mathrm{~K}\). If ammonia is added to a water solution containing excess of \(\mathrm{AgCl}(\mathrm{s})\) only, calculate the concentration of the complex in \(1.0 \mathrm{M}\) aqueous ammonia.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.