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Among the following the state function(s) is (are) (a) Internal energy (b) Irreversible expansion work (c) Reversible expansion work (d) Molar enthalpy

Short Answer

Expert verified
Internal energy and molar enthalpy are state functions.

Step by step solution

01

Define a State Function

A state function is a property whose value does not depend on the path taken to reach that specific value. It depends only on the state of the system, described by variables such as temperature, pressure, and volume.
02

Identify Internal Energy

Internal energy is a state function because it depends only on the current state of the system and not on how the system arrived at that state. Changes in internal energy can be determined by initial and final states.
03

Evaluate Irreversible Expansion Work

Irreversible work done during expansion or compression is not a state function. It depends on the specific pathway taken during the process, so its value varies with different paths.
04

Examine Reversible Expansion Work

Reversible work is also not a state function. While it can be calculated precisely for certain pathways, it is path-dependent since different pathways would yield different amounts of work done.
05

Identify Molar Enthalpy

Molar enthalpy is a state function as it is defined by the formula \( H = U + PV \), where \( U \) is internal energy, \( P \) is pressure, and \( V \) is volume. Since these are all state functions, enthalpy is also a state function.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Internal Energy
Internal energy is a fundamental concept in thermodynamics. It represents the total energy contained within a system, arising from all the microscopic motions and interactions of the particles within it. Internal energy is an example of a **state function**, which means it is determined only by the current state of the system and not by the process by which the system reached that state.

For instance, if a gas is compressed in a container causing its temperature to increase, the internal energy changes based on the initial and final temperature states, not on how the compression was carried out.
Internal energy is often depicted with the symbol \( U \) and can include kinetic energies of particles, potential energies depending on particle arrangements, and other intrinsic properties at the microscopic level.
  • State Function: Relies on present state, not path.
  • Changes: Determined by initial and final states.
  • Components: Kinetic and potential energies within the system.
Irreversible Expansion Work
Irreversible expansion work occurs when a system, such as gas expanding against external pressure, does not go through a perfectly controlled process. It's a common concept in real-world applications where conditions are not ideally maintained.

This type of expansion work is not a state function. Contrary to state functions, it depends on the path taken, meaning it varies depending on how the process is carried out. For example, how quickly or slowly the expansion occurs can affect the work done.
In reality, most processes are irreversible because they involve spontaneous changes that cannot be reversed without adding energy to the system.
  • Path-Dependent: Amount of work changes with different paths.
  • Real-World Process: Often involves rapid or unsteady changes.
  • Non-ideal Conditions: True in most practical scenarios.
Reversible Expansion Work
Reversible expansion work, unlike its irreversible counterpart, assumes a process can be reversed by infinitesimal changes in conditions. It's a theoretical concept illustrating maximum possible work that could be performed by a system.

However, even though it allows precise calculations in defined pathways, reversible expansion work is not a state function because it is still path-dependent. The work is computed based on an ideal path where equilibrium is maintained at every step.
In practice, truly reversible processes are nearly impossible. They represent an "ideal" scenario, useful for understanding maximum achievable efficiency.
  • Ideal Path: Assumes infinitesimally small changes to maintain equilibrium.
  • Not State Function: Still path-dependent despite controlled conditions.
  • Maximum Efficiency: Represents theoretical limits rather than practical norms.
Molar Enthalpy
Molar enthalpy, or simply enthalpy, refers to the measure of total energy in a thermodynamic system per mole of substance subject to constant pressure. It is denoted by the symbol \( H \) and is defined by the equation \( H = U + PV \), where \( U \) is internal energy, \( P \) is pressure, and \( V \) is volume of the system.

Importantly, molar enthalpy is a state function. This means its value is determined solely by the current conditions (temperature, pressure, volume) of the system, not the path taken to reach those conditions.
This concept is crucial in understanding heat exchanges in chemical reactions and phase changes, given its property that can be directly calculated from these state variables.
  • State Function: Calculated from present state conditions.
  • Formula: \( H = U + PV \).
  • Importance: Vital for assessing energy changes during reactions.

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Most popular questions from this chapter

In order to get maximum calorific output, a burner should have an optimum fuel to oxygen ratio which corresponds to 3 times as much oxygen as is required theoretically for complete combustion of the fuel. A burner which has been adjusted for methane as fuel (with \(x\) litre/hour of \(\mathrm{CH}_{4}\) and \(6 x\) litre/hour of \(\mathrm{O}_{2}\) ) is to be readjusted for butane, \(\mathrm{C}_{4} \mathrm{H}_{10}\). In order to get the same calorific output, what should be the rate of supply of butane and oxygen ? Assume that losses due to incomplete combustion, \(e t c\), are the same for both the fuels and the gases behave ideally. Heats of combustion : $$ \mathrm{CH}_{4}=809 \mathrm{~kJ} / \mathrm{mol} ; \mathrm{C}_{4} \mathrm{H}_{10}=2878 \mathrm{~kJ} / \mathrm{mol} $$

For which of the following processes, \(\Delta \mathrm{S}\) is negative?(a) \(\mathrm{C}\) (diamond \() \rightarrow \mathrm{C}\) (graphite) (b) \(\mathrm{N}_{2}(\mathrm{~g}\), latm \() \rightarrow \mathrm{N}_{2}(\mathrm{~g}, 5 \mathrm{~atm})\) (c) \(\mathrm{N}_{2}(\mathrm{~g}, 273 \mathrm{~K}) \rightarrow \mathrm{N}_{2}(\mathrm{~g}, 300 \mathrm{~K})\) (d) \(\mathrm{H}_{2}(\mathrm{~g}) \rightarrow 2 \mathrm{H}(\mathrm{g})\)

Lattice enthalpy and enthalpy of solution of \(\mathrm{NaCl}\) are \(788 \mathrm{~kJ} \mathrm{~mol}^{-1}\) and \(4 \mathrm{~kJ} \mathrm{~mol}^{-1}\), respectively. The hydration enthalpy of \(\mathrm{NaCl}\) is : [Main Sep. 05, 2020 (II)] (a) \(-780 \mathrm{~kJ} \mathrm{~mol}^{-1}\) (b) \(780 \mathrm{~kJ} \mathrm{~mol}^{-1}\) (c) \(-784 \mathrm{~kJ} \mathrm{~mol}^{-1}\) (d) \(784 \mathrm{~kJ} \mathrm{~mol}^{-1}\)

For the process \(\mathrm{H}_{2} \mathrm{O}(1)(1 \mathrm{bar}, 373 \mathrm{~K}) \rightarrow \mathrm{H}_{2} \mathrm{O}(\mathrm{g})(1 \mathrm{bar}, 373 \mathrm{~K})\), the correct set of thermodynamic parameters is [2007] (a) \(\Delta G=0, \Delta S=+\mathrm{ve}\) (b) \(\Delta G=0, \Delta S=-\mathrm{ve}\) (c) \(\Delta G=+\) ve, \(\Delta S=0\) (d) \(\Delta G=-\mathrm{ve}, \Delta S=+\mathrm{ve}\)

The true statement amongst the following is : [Main Jan. 09, 2020 (II)] (a) Both \(\Delta \mathrm{S}\) and \(\mathrm{S}\) are functions of temperature. (b) Both \(\mathrm{S}\) and \(\Delta \mathrm{S}\) are not functions of temperature. (c) \(\mathrm{S}\) is not a function of temperature but \(\Delta \mathrm{S}\) is a function of temperature. (d) \(\mathrm{S}\) is a function of temperature but \(\Delta \mathrm{S}\) is not a function of temperature.

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