Chapter 4: Problem 5
The bond order and the magnetic characteristics of \(\mathrm{CN}^{-}\)are: [Main Jan. 07, 2020 (II)] (a) \(2 \frac{1}{2}\), diamagnetic (b) 3 , diamagnetic (c) 3, paramagnetic (d) \(2 \frac{1}{2}\), paramagnetic
Short Answer
Expert verified
The bond order of \(\mathrm{CN}^{-}\) is 3 and it is diamagnetic.
Step by step solution
01
Write the electron configuration of CN-
Determine the total number of electrons in the \(\mathrm{CN}^{-}\) ion. Carbon has 6 electrons, nitrogen has 7 electrons, and the negative charge adds 1 more, giving a total of 14 electrons. Use the molecular orbital theory to write the electron configuration for \(\mathrm{CN}^{-}\).
02
Determine the electron configuration order
The electron configuration of \(\mathrm{CN}^{-}\) follows the order: \(\sigma_{1s}^{2}\), \(\sigma_{1s}^{*2}\), \(\sigma_{2s}^{2}\), \(\sigma_{2s}^{*2}\), \(\pi_{2p_x}^{2}\), \(\pi_{2p_y}^{2}\), \(\sigma_{2p_z}^{2}\), \(\pi_{2p_x}^{*0}\). This is for 14 electrons.
03
Calculate the bond order
The bond order is calculated using the formula: \[ \text{Bond Order} = \frac{\text{Number of bonding electrons} - \text{Number of antibonding electrons}}{2} \]. In \(\mathrm{CN}^{-}\), there are 10 bonding electrons and 4 antibonding electrons, so the bond order \[ = \frac{10 - 4}{2} = 3 \].
04
Determine the magnetic characteristics
To determine if \(\mathrm{CN}^{-}\) is diamagnetic or paramagnetic, check for unpaired electrons in the electron configuration. Since all electrons are paired in \(\mathrm{CN}^{-}\), it is diamagnetic.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Bond Order
In chemistry, bond order refers to the number of chemical bonds between a pair of atoms. It's an important concept in molecular orbital theory, which is used to understand how electrons are distributed in a molecule. The bond order can tell us how strong or stable a bond might be.
To find the bond order of \({\mathrm{CN}}^{-}\), you use the formula: \[ \text{Bond Order} = \frac{\text{Number of bonding electrons} - \text{Number of antibonding electrons}}{2} \] In the case of \({\mathrm{CN}}^{-}\), there are 10 bonding electrons and 4 antibonding electrons. This brings us to:
To find the bond order of \({\mathrm{CN}}^{-}\), you use the formula: \[ \text{Bond Order} = \frac{\text{Number of bonding electrons} - \text{Number of antibonding electrons}}{2} \] In the case of \({\mathrm{CN}}^{-}\), there are 10 bonding electrons and 4 antibonding electrons. This brings us to:
- 10 bonding electrons - 4 antibonding electrons = 6
- \[\frac{6}{2} = 3\] This means that the bond order for \({\mathrm{CN}}^{-}\) is 3, indicating a strong triple bond. A higher bond order generally means a stronger and shorter bond, making the molecule more stable.
Electron Configuration
Electron configuration is like a map that shows where electrons reside in an atom or molecule. It's crucial to understand electron configurations to predict molecular behavior, such as bond formation and chemical reactivity.
For \({\mathrm{CN}}^{-}\), we first calculate the total number of electrons. \({\mathrm{CN}}^{-}\) is made up of a carbon atom and a nitrogen atom, with a negative charge adding an extra electron:
For \({\mathrm{CN}}^{-}\), we first calculate the total number of electrons. \({\mathrm{CN}}^{-}\) is made up of a carbon atom and a nitrogen atom, with a negative charge adding an extra electron:
- Carbon: 6 electrons
- Nitrogen: 7 electrons
- Extra electron due to negative charge: 1 electron
- Total: 14 electrons
- \(\sigma_{1s}^{2}\)
- \(\sigma_{1s}^{*2}\)
- \(\sigma_{2s}^{2}\)
- \(\sigma_{2s}^{*2}\)
- \(\pi_{2p_x}^{2}\)
- \(\pi_{2p_y}^{2}\)
- \(\sigma_{2p_z}^{2}\)
- \(\pi_{2p_x}^{*0}\)
Magnetic Characteristics
Determining the magnetic characteristics of a molecule is crucial for understanding its behavior in a magnetic field. The molecule can be either diamagnetic or paramagnetic based on electron configuration.
- **Diamagnetic molecules** have all paired electrons and do not get attracted to magnetic fields.- **Paramagnetic molecules** contain unpaired electrons, which causes them to be attracted to magnetic fields.When looking at \({\mathrm{CN}}^{-}\), its electron configuration reveals all electrons are paired. This indicates that \({\mathrm{CN}}^{-}\) is **diamagnetic**.Check the orbitals for paired and unpaired electrons:
- **Diamagnetic molecules** have all paired electrons and do not get attracted to magnetic fields.- **Paramagnetic molecules** contain unpaired electrons, which causes them to be attracted to magnetic fields.When looking at \({\mathrm{CN}}^{-}\), its electron configuration reveals all electrons are paired. This indicates that \({\mathrm{CN}}^{-}\) is **diamagnetic**.Check the orbitals for paired and unpaired electrons:
- \(\sigma_{1s}^{2}\) – both electrons are paired
- \(\sigma_{1s}^{*2}\) – both electrons are paired
- \(\sigma_{2s}^{2}\) – both electrons are paired
- \(\sigma_{2s}^{*2}\) – both electrons are paired
- \(\pi_{2p_x}^{2}\) – both electrons are paired
- \(\pi_{2p_y}^{2}\) – both electrons are paired
- \(\sigma_{2p_z}^{2}\) – both electrons are paired