/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 10 According to molecular orbital t... [FREE SOLUTION] | 91影视

91影视

According to molecular orbital theory, which of the following is true with respect to \(\mathrm{Li}_{2}^{+}\)and \(\mathrm{Li}_{2}^{-} ?\) [Main Jan. 9, 2019 (I)] (a) \(\mathrm{Li}_{2}^{+}\)is unstable and \(\mathrm{Li}_{2}^{-}\)is stable (b) \(\mathrm{Li}_{2}^{+}\)is stable and \(\mathrm{Li}_{2}^{-}\)is unstable (c) Both are stable (d) Both are unstable

Short Answer

Expert verified
(b) \(\mathrm{Li}_{2}^{+}\) is stable and \(\mathrm{Li}_{2}^{-}\) is unstable.

Step by step solution

01

Determine the Electron Configuration

According to molecular orbital theory, we assign electrons to molecular orbitals. For lithium, the atomic number is 3, so from the electron configuration of Li: 1s虏 2s鹿, we can determine how many electrons are present. Li鈧傗伜 has one less electron than Li鈧 and Li鈧傗伝 has one more electron than Li鈧. The ground state electronic configuration of Li is in the 2s orbital.
02

Draw MOs for Diatomic Lithium

In the diatomic molecular orbitals for Li, the electrons will fill the bonding orbital ( 饾湈2饾憼 ) before the antibonding orbital ( 饾湈2饾憼* ). For Li鈧: 饾湈1饾憼虏, 饾湈1饾憼*虏, 饾湈2饾憼虏 are filled.
03

Fill Molecular Orbital of Li鈧傗伜 and Li鈧傗伝

For Li鈧傗伜, which has 5 electrons, the filling is: 饾湈1饾憼虏, 饾湈1饾憼*虏, 饾湈2饾憼鹿 . For Li鈧傗伝, which has 7 electrons, the filling is: 饾湈1饾憼虏, 饾湈1饾憼*虏, 饾湈2饾憼虏, 饾湈2饾憼*鹿 .
04

Calculate Bond Order

The bond order is calculated using the formula: Bond order = (Number of electrons in bonding orbitals - Number of electrons in antibonding orbitals) / 2. Li鈧傗伜: (4 bonding - 3 antibonding)/2 = 0.5. Li鈧傗伝: (4 bonding - 4 antibonding)/2 = 0.
05

Interpret Bond Order

A bond order greater than 0 indicates a stable molecule. For Li鈧傗伜 the bond order is 0.5, indicating that it is stable. For Li鈧傗伝 the bond order is 0, indicating that it is unstable.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electron Configuration
Understanding electron configuration is crucial for analyzing molecular stability. In molecular orbital theory, electrons fill molecular orbitals based on their energy levels. For diatomic molecules like lithium, whose atomic number is 3, we start by considering its electron configuration. A regular lithium (Li) atom has the configuration 1s虏 2s鹿. This means Li has a total of 3 electrons: 2 in the 1s orbital and 1 in the 2s orbital.

When considering diatomic lithium ions, such as \(\mathrm{Li}_{2}^{+}\) and \(\mathrm{Li}_{2}^{-}\), it's essential to adjust for the change in electron quantity. \(\mathrm{Li}_{2}^{+}\) loses one electron, reducing its total count to 5, whereas \(\mathrm{Li}_{2}^{-}\) gains an electron, reaching 7. The alteration in electron numbers influences how they fill both bonding and antibonding orbitals within the molecule.
  • Li鈧傗伜: Has 5 electrons configured as \(\sigma 1s^2, \sigma 1s*^2, \sigma 2s^1\).
  • Li鈧傗伝: Contains 7 electrons, filled as \(\sigma 1s^2, \sigma 1s*^2, \sigma 2s^2, \sigma 2s*^1\).
Bond Order
Bond order is a concept used to determine the stability of a molecule. It's derived from the difference between the number of electrons in bonding and antibonding orbitals, divided by two. This signifies the net number of bonds within a molecule.

In the context of molecular orbital theory, a positive bond order indicates that a molecule is stable, while a bond order of zero or less suggests instability. For example, bond order calculations for \(\mathrm{Li}_{2}^{+}\) and \(\mathrm{Li}_{2}^{-}\) would go as follows:
  • **Li鈧傗伜** has a bond order of 0.5: Calculated from \((4 \text{ (bonding electrons)} - 3 \text{ (antibonding electrons)})/2\), suggesting it is a stable compound.
  • **Li鈧傗伝** ends up with a bond order of 0: \((4-4)/2\), indicating that it does not have a net bond, hence it's unstable.

Thus, bond order proves to be a straightforward and effective determination tool for molecular stability.
Diatomic Molecules
Diatomic molecules are entities made of two atoms, whether of the same or different elements. A custom analysis of their stability often revolves around molecular orbital theory, as it plays a pivotal role in understanding interactions between two atomic orbitals.

For lithium (\(\mathrm{Li}_{2}\)), molecular orbitals are formed from the two individual lithium atoms. As these atoms join, their respective s-orbitals interact, creating bonding (\(\sigma\)) and antibonding (\(\sigma^*\)) molecular orbitals. In \(\mathrm{Li}_{2}\) molecules, electrons fill these orbitals in accordance with their respective energy levels, which impacts the stability of the overall molecule.
  • The arrangement consists of occupied bonding and unoccupied antibonding orbitals when stable.
  • Key insights into a diatomic molecule's stability can be gleaned by examining which orbitals have electrons.
For example, \(\mathrm{Li}_{2}^{+}\) and \(\mathrm{Li}_{2}^{-}\) demonstrate how adding or removing electrons affects the electron's placement within these orbitals, ultimately influencing bond order and stability.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.