Chapter 31: Problem 34
The reagent(s) that can selectively precipitate \(\mathrm{S}^{2-}\) from a mixture of \(\mathrm{S}^{2-}\) and \(\mathrm{SO}_{4}^{2-}\) in aqueous solution is (are) (a) \(\mathrm{CuCl}_{2}\) (b) \(\mathrm{BaCl}_{2}\) (c) \(\mathrm{Pb}\left(\mathrm{OOCCH}_{3}\right)_{2}\) (d) \(\mathrm{Na}_{2}\left[\mathrm{Fe}(\mathrm{CN})_{5} \mathrm{NO}\right]\)
Short Answer
Step by step solution
Identifying Selective Precipitation Concept
Analyzing Each Option
Evaluating the Selectivity of Reagents
Conclusion
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Sulfide Ion Precipitation
The selective precipitation process hinges on finding a reagent that:
- Forms an insoluble compound with sulfide ions.
- Does not react, or reacts very minimally, with sulfate ions.
Sodium Nitroprusside Reaction
- The resulting precipitate's color is starkly different from the original solution, facilitating easy visualization.
- Sodium nitroprusside does not interfere with other common anions like sulfates, making it extraordinarily selective.
Solubility of Sulfide and Sulfate
In general:
- Sulfides tend to form highly insoluble compounds with metal cations. Examples include copper(II) sulfide (\( \mathrm{CuS} \)) and lead sulfide (\( \mathrm{PbS} \)).
- Sulfates are usually more soluble, though there are exceptions such as barium sulfate (\( \mathrm{BaSO}_{4} \)), which is very insoluble.