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An aqueous solution contains \(\mathrm{Hg}^{2+}, \mathrm{Hg}_{2}^{2+}, \mathrm{Pb}^{2+}\) and \(\mathrm{Cd}^{2+} .\) The addition of \(\mathrm{HCl}(6 \mathrm{~N})\) will precipitate : (a) \(\mathrm{Hg}_{2} \mathrm{Cl}_{2}\) only (b) \(\mathrm{PbCl}_{2}\) only (c) \(\mathrm{PbCl}_{2}\) and \(\mathrm{Hg}_{2} \mathrm{Cl}_{2}\) (d) \(\mathrm{PbCl}_{2}\) and \(\mathrm{HgCl}_{2}\)

Short Answer

Expert verified
(c) \(\text{PbCl}_2\) and \(\text{Hg}_2\text{Cl}_2\) precipitate.

Step by step solution

01

Initial Analysis

To solve this problem, we need to know the solubility of the chlorides of each ion present in the solution. Chlorides that are not soluble will precipitate.
02

Ion and Chloride Properties

Mercury(I) chloride, \(\text{Hg}_2\text{Cl}_2\), is insoluble in water and will precipitate immediately upon the addition of \(\mathrm{HCl}\). Lead(II) chloride, \(\text{PbCl}_2\), is sparingly soluble in water at low temperature. Cadmium(II) chloride, \(\text{CdCl}_2\), is soluble. Mercury(II) chloride, \(\text{HgCl}_2\), is also soluble.
03

Effect of Adding HCl

On adding \(6 \text{ N}\) \(\text{HCl} \), only \(\text{Hg}_2\text{Cl}_2\) and \(\text{PbCl}_2\) will precipitate because they have low solubilities. \(\text{CdCl}_2\) and \(\text{HgCl}_2\) remain soluble in the solution.
04

Conclusion

The only ions which form chlorides precipitating in \(\text{HCl}\) are \(\text{Hg}_2^{2+}\) and \(\text{Pb}^{2+}\), leading to the formation of \(\text{Hg}_2\text{Cl}_2\) and \(\text{PbCl}_2\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Solubility
Solubility is a concept that describes the ability of a substance to dissolve in a solvent, such as water. It is a key factor in solution chemistry that helps determine whether a compound will remain dissolved or form a precipitate when mixed with another substance. For chloride ions, solubility plays a crucial role in understanding which metal chlorides can form precipitates from aqueous solutions.
In the context of this exercise, understanding solubility helps predict that \(\text{Hg}_2\text{Cl}_2\) and \(\text{PbCl}_2\) will end up as solids due to their low solubility when \(\text{HCl}\) is added. The solubility product constant, commonly known as \(K_{sp}\), is often used to quantify solubility; however, for qualitative analyses, we rely on relative solubility information.
Chlorides such as \(\text{CdCl}_2\) and \(\text{HgCl}_2\), having higher solubility, remain dissolved in the solution. Being aware of the solubility rules, which include exceptions for chlorides, aids in predicting whether a precipitate will form in any given reaction.
Chloride Precipitation
Precipitation reactions occur when two solutions combine and produce an insoluble solid known as a precipitate. In this problem, we analyze the behavior of chloride ions, which help form precipitates when mixed with certain metal ions.
Mercury(I) chloride \(\text{Hg}_2\text{Cl}_2\) and lead(II) chloride \(\text{PbCl}_2\) are examples of precipitates formed upon the addition of hydrochloric acid \(\text{HCl}\). Mercury(I) chloride is typically insoluble and quickly forms a solid. Lead(II) chloride is sparingly soluble but still readily precipitates from cold solutions.
Adding \(6 \, \text{N} \, \text{HCl}\) enhances the chloride concentration, favoring the formation of solid chlorides for metal ions of low solubility. This results in the observed precipitation. Chloride precipitation is essential in many applications including qualitative analysis, where it helps isolate and identify metal ions.
Aqueous Solution Chemistry
Aqueous solution chemistry involves the study of reactions and properties of substances in water. It's a fundamental aspect of chemistry that explains both solubility and precipitation behavior. Solutions containing metal ions react with other substances based on their chemical properties, influenced by the ionic and molecular interactions in water.
In this particular exercise, the presence of ions like \(\mathrm{Hg}^{2+}, \mathrm{Pb}^{2+},\) and others, shows how they behave in an aqueous medium. When \(\text{HCl}\) is added, \(\text{Cl}^-\) ions interact with these metal cations, affecting equilibrium positions and solubility.
For example, \(\text{Hg}_2^{2+}\) and \(\text{Pb}^{2+}\) bond with chloride to form precipitates. Meanwhile \(\text{CdCl}_2\) and \(\text{HgCl}_2\) stay dissolved as their solubility is higher. Aqueous chemistry is rich and varied, requiring understanding of concepts like solubility rules, ion charges, and concentrations, which govern the behavior of these solutions.

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Most popular questions from this chapter

When a white crystalline compound \(\mathbf{X}\) is heated with \(\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}\) and concentrated \(\mathrm{H}_{2} \mathrm{SO}_{4}\), a reddish brown gas \(\mathbf{A}\) is evolved. On passing A into caustic soda solution, a yellow coloured solution of \(\mathbf{B}\) is obtained. Neutralizing the solution \(\mathbf{B}\) with acetic acid and on subsequent addition of lead acetate, a yellow precipitate \(\mathbf{C}\) is obtained. When \(\mathbf{X}\) is heated with NaOH solution, a colourless gas is evolved and on passing this gas into \(\mathrm{K}_{2} \mathrm{HgI}_{4}\) solution, a reddish brown precipitate \(\mathbf{D}\) is formed. Identify \(\mathbf{A}, \mathbf{B}, \mathbf{C}, \mathbf{D}\) and \(\mathbf{X}\). Write the equations of reactions involved.

A hydrated metallic salt \(A\), light green in colour, on careful heating gives a white anhydrous residue \(B . B\) is soluble in water and its aqueous solution reacts with NO to give a dark brown compound \(C . B\) on strong heating gives a brown residue \(D\) and a mixture of two gases \(E\) and \(F\). The gaseous mixture when passed through acidified permanganate, discharges the pink colour and when passed through acidified \(\mathrm{BaCl}_{2}\) solution, gave a white precipitate. Identify \(A, B, C, D\), \(E\) and \(F\).

Read the following statement and explanation and answer as per the options given below : Assertion : Sulphate is estimated as \(\mathrm{BaSO}_{4}\) and not as \(\mathrm{MgSO}_{4}\). Reason : Ionic radius of \(\mathrm{Mg}^{2+}\) is smaller than that of \(\mathrm{Ba}^{2+}\). (a) If both assertion and reason are correct, and reason is the correct explanation of the assertion. (b) If both assertion and reason are correct, but reason is not the correct explanation of the assertion. (c) If assertion is correct but reason is incorrect. (d) If assertion is incorrect but reason is correct.

A light bluish green crystalline compound responds to the following tests : (i) Its aqueous solution gives a brown precipitate or colour with alkaline \(\mathrm{K}_{2}\left[\mathrm{HgI}_{4}\right]\) solution. (ii) Its aqueous solution gives a blue colour with \(\mathrm{K}_{3}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]\) solution. (iii) Its solution in hydrochloric acid gives a white precipitate with \(\mathrm{BaCl}_{2}\) solution. Identify the ions present and suggest the formula of the compound.

Passing \(\mathrm{H}_{2} \mathrm{~S}\) gas into a mixture of \(\mathrm{Mn}^{2+}, \mathrm{Ni}^{2+}, \mathrm{Cu}^{2+}\) and \(\mathrm{Hg}^{2+}\) ions in an acidified aqueous solution precipitates (a) \(\mathrm{CuS}\) and \(\mathrm{HgS}\) (b) \(\mathrm{MnS}\) and \(\mathrm{CuS}\) (c) \(\mathrm{MnS}\) and \(\mathrm{NiS}\) (d) NiS and \(\mathrm{HgS}\)

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