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When phenol is reacted with \(\mathrm{CHCl}_{3}\) and \(\mathrm{NaOH}\) followed by acidification, salicyladehyde is obtained. Which of the following species are involved in the above mentioned reaction as intermediate?

Short Answer

Expert verified
The key intermediate is dichlorocarbene ( \(:CCl_2\)).

Step by step solution

01

Understand the Reaction

This reaction is known as the Reimer-Tiemann reaction. In this process, phenol reacts with chloroform (\(\mathrm{CHCl}_3\)) and sodium hydroxide (\(\mathrm{NaOH}\)) to form salicylaldehyde.
02

Identify Initial Reaction

Initially, chloroform reacts with sodium hydroxide, leading to the formation of dichlorocarbene (\(:CCl_2\)) as an intermediate product.
03

Intermediate Formation

The intermediate dichlorocarbene (\(:CCl_2\)) then reacts with the phenoxide ion, which is generated when phenol is deprotonated by \(\mathrm{NaOH}\).
04

Rearrangement to Form the Desired Product

The reaction continues with the dichlorocarbene adding to the ortho position of the phenoxide ion. Further hydrolysis leads to the formation of salicylaldehyde after acidification.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

dichlorocarbene intermediate
The Reimer-Tiemann reaction is a fascinating chemical process that involves the transformation of phenol into salicylaldehyde. One of the key intermediates in this reaction is dichlorocarbene. Dichlorocarbene ( : CCl_2 ) is a reactive species that plays a crucial role in this mechanism. It is generated from chloroform ( CHCl_3 ) when treated with a strong base like sodium hydroxide ( NaOH ). This reaction causes one hydrogen atom from chloroform to be removed, resulting in the formation of dichlorocarbene. This intermediate is highly unstable and reactive because it possesses a vacant p-orbital, leading to its rapid participation in chemical transformations.
  • The intermediate is generated from chloroform and sodium hydroxide.
  • Dichlorocarbene is characterized by its instability and high reactivity.
  • Its formation is a crucial initial step in the Reimer-Tiemann reaction.
An interesting aspect of dichlorocarbene is its ability to insert into C-H bonds, but in the Reimer-Tiemann reaction, its role is to react with a phenoxide ion, leading to the subsequent formation of salicylaldehyde.
phenoxide ion
In the Reimer-Tiemann reaction, the phenoxide ion plays a vital role in the mechanisms that lead to the target compound, salicylaldehyde. The phenoxide ion is generated when phenol ( C_6H_5OH ) is deprotonated by the strong base sodium hydroxide ( NaOH ). This deprotonation is crucial because it transforms phenol into a more reactive species capable of further interacting with other intermediates.
  • The phenol loses a hydrogen ion (proton) to form the phenoxide ion.
  • The phenoxide ion has increased nucleophilicity compared to phenol itself.
  • It enables the crucial electrophilic attack by the dichlorocarbene intermediate.
The phenoxide ion's enhanced nucleophilic property makes it more suitable for attacking the electrophilic dichlorocarbene intermediate. This step is a cornerstone in the sequence that converts the original phenol starting material into the aromatic aldehyde product.
salicylaldehyde formation
The ultimate goal of the Reimer-Tiemann reaction is to synthesize salicylaldehyde, which is an aromatic aldehyde with valuable applications in perfumery and pharmaceuticals. The formation of salicylaldehyde begins with the reaction of dichlorocarbene with the phenoxide ion. The electrophilic dichlorocarbene attacks the nucleophilic ortho-carbon (the nearest carbon to the OH group) of the phenoxide ion.
  • The dichlorocarbene adds to the ortho position of the phenoxide ion.
  • This step leads to the formation of an intermediate compound.
  • Acidification subsequent to the reaction helps in achieving the final product, salicylaldehyde.
Following this addition, further rearrangement and hydrolytic steps occur, leading to the release of chlorine atoms and transformation into salicylaldehyde. The final acidification step not only stabilizes the product but also helps in precipitating it out of the solution. Understanding this formation process highlights the elegant interplay between chemical reactivity and structural transformation in organic chemistry, specifically in the Reimer-Tiemann reaction.

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Most popular questions from this chapter

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