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\(\left(\mathrm{CH}_{3}\right)_{3} \mathrm{CMgCl}\) on reaction with \(\mathrm{D}_{2} \mathrm{O}\) produces : (a) \(\left(\mathrm{CH}_{3}\right)_{3} \mathrm{CD}\) (b) \(\left(\mathrm{CH}_{3}\right)_{3} \mathrm{OD}\) (c) \(\left(\mathrm{CD}_{3}\right)_{3} \mathrm{CD}\) (d) \(\left(\mathrm{CD}_{3}\right)_{3} \mathrm{OD}\)

Short Answer

Expert verified
The product is \((\mathrm{CH}_{3})_{3} \mathrm{CD}\), option (a).

Step by step solution

01

Understanding the Grignard Reagent

The compound \(\left(\mathrm{CH}_{3}\right)_{3} \mathrm{CMgCl}\) is a type of Grignard reagent. Grignard reagents contain a carbon-metal bond that is highly polarized, where the carbon has a partial negative charge. This makes the carbon an excellent nucleophile.
02

Identify the Reactant Interaction

Determine how the Grignard reagent will react with \(\mathrm{D}_{2} \mathrm{O}\). The \(\mathrm{MgCl}\) group is bound to a carbon, and when it reacts with \(\mathrm{D}_{2} \mathrm{O}\), the \(\mathrm{MgCl}\) is removed, and a deuterium (from \(\mathrm{D}_{2} \mathrm{O}\)) is attached to the carbon.
03

Substitution of Deuterium

When \(\left(\mathrm{CH}_{3}\right)_{3} \mathrm{CMgCl}\) reacts with \(\mathrm{D}_{2} \mathrm{O}\), \(\mathrm{D}^-\) from the \(\mathrm{D}_{2} \mathrm{O}\) replaces the \(\mathrm{MgCl}\) group to form a C-D bond. The result is \(\left(\mathrm{CH}_{3}\right)_{3} \mathrm{CD}\).
04

Determine the Product

After considering the substitution reaction, the final compound formed is \(\left(\mathrm{CH}_{3}\right)_{3} \mathrm{CD}\), which is the result of the original Grignard reagent losing \(\mathrm{MgCl}\) and gaining a deuterium atom instead.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Nucleophilic Substitution
Nucleophilic substitution is a key reaction mechanism in organic chemistry. In these reactions, a nucleophile—an atom or molecule with a pair of electrons ready to form a bond—attacks and replaces a leaving group in a compound. The Grignard reaction involves such a nucleophilic substitution. Here, the Grignard reagent, represented as \(\left(\mathrm{CH}_3\right)_3 \mathrm{CMgCl}\), contains a carbon with a partial negative charge. This carbon acts as the nucleophile.

When the Grignard reagent comes in contact with \(\mathrm{D}_2 \mathrm{O}\) (deuterium oxide), the nucleophilic carbon attacks the deuterium atoms (\(\mathrm{D}\)), substituting them for the \(\mathrm{MgCl}\) group. This results in the formation of a C-D bond, since deuterium acts as the new part of the organic structure.

Understanding nucleophilic substitution allows you to predict how different reagents will interact and what products will result.
Deuterium Exchange
Deuterium exchange involves the replacement of hydrogen atoms in a molecule with deuterium atoms. Deuterium is a hydrogen isotope that has one neutron, making it heavier than the usual hydrogen atom. This exchange is crucial for labeling experiments that help trace molecular mechanisms.

In the context of the Grignard reaction with \(\mathrm{D}_2 \mathrm{O}\), a deuterium exchange occurs when the hydrogen from the Grignard reagent is replaced with deuterium from \(\mathrm{D}_2 \mathrm{O}\). The process leads to deuterium being incorporated into the organic structure, resulting in \(\left(\mathrm{CH}_3\right)_3 \mathrm{CD}\).

This exchange is efficiently facilitated due to the highly reactive nature of Grignard reagents, allowing them to react readily with isotopes like deuterium.
Organomagnesium Compounds
Organomagnesium compounds are central in the Grignard reaction. They are characterized by a direct carbon-magnesium bond. This bond is highly polarized, which makes the carbon atom act as a strong nucleophile eager to bond with electropositive atoms. The Grignard reagent \((\mathrm{CH}_3)_3 \mathrm{CMgCl}\) is a typical example of an organomagnesium compound.

These reagents are named after Victor Grignard, who won a Nobel Prize for discovering the reaction they undergo. The unique reactivity of organomagnesium compounds with water or other proton donors like \(\mathrm{D}_2 \mathrm{O}\) utilizes the difference in electronegativity between carbon and magnesium. During the reaction, the \(\mathrm{MgCl}\) group in the Grignard reagent is replaced with a deuterium atom, showing the versatility and importance of organomagnesium compounds in synthetic chemistry.

Grignard reagents are indispensable for forming carbon-carbon bonds, thus playing a crucial role in constructing complex molecules in laboratory syntheses.

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Most popular questions from this chapter

Aryl fluoride may be prepared from arene diazonium chloride using : (a) \(\mathrm{HBF}_{4} / \Delta\) (b) \(\mathrm{HBF}_{4} / \mathrm{NaNO}_{2}, \mathrm{Cu}, \Delta\) (c) \(\mathrm{CuF} / \mathrm{HF}\) (d) \(\mathrm{Cu} / \mathrm{HF}\)

Given below are certain matching type questions, where two columns (each having 4 items) are given. Immediately after the columns the matching grid is given, where each item of Column I has to be matched with the items of Column II, by encircling the correct match(es). Note that an item of Column I can match with more than one item of Column II. All the items of Column II must be matched. Match the following : Column I (A) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}_{2} \mathrm{CD}_{2} \mathrm{Br}\) on reaction with (B) \(\mathrm{PhCHBrCH}_{3}\) and \(\mathrm{PhCHBrCD}_{3}\), (C) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{Br}\) on treatment with \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{O}^{-}\)and \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OD}\) gives \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CD}=\mathrm{CH}_{2}\) (D) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{Br}\) reacts faster than \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CD}_{2} \mathrm{CH}_{2} \mathrm{Br}\) on reaction with \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{O}^{-} \quad\) in ethanol Column II (p) E1 reaction \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{O}^{-}\)gives \(\mathrm{C}_{6} \mathrm{H}_{5}-\) \(\mathrm{CH}=\mathrm{CD}_{2}\) (q) E2 reaction both react with the same rate (r) E1cB reaction (s) First order reaction

Arrange the following in: Increasing reactivity in nucleophilic substitution reactions \(\mathrm{CH}_{3} \mathrm{~F}, \mathrm{CH}_{3} \mathrm{I}, \mathrm{CH}_{3} \mathrm{Br}, \mathrm{CH}_{3} \mathrm{Cl}\)

Compound (A), \(\mathrm{C}_{8} \mathrm{H}_{9} \mathrm{Br}\), gives a yellow precipitate when warmed with alcoholic \(\mathrm{AgNO}_{3}\). Oxidation of (A) gives an acid (B), \(\mathrm{C}_{8} \mathrm{H}_{6} \mathrm{O}_{4}\). (B) easily forms anhydride on heating. Identify the compound (A).

Cyclobutyl bromide on treatment with magnesium in dry ether forms an organometallic (A). The organometallic reacts with ethanal to give an alcohol (B) after mild acidification. Prolonged treatment of alcohol (B) with an equivalent amount of HBr gives 1 -bromo-1methylcyclopentane (C). Write the structures of (A), (B) and explain how \((\mathrm{C})\) is obtained from (B).

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