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How will you prepare \(m\)-bromoiodobenzene from benzene (in not more than \(5-7\) steps)?

Short Answer

Expert verified
Synthesize m-bromoiodobenzene from benzene by nitration, bromination, reduction, diazotization, and Sandmeyer reaction.

Step by step solution

01

Nitration of Benzene

Start by conducting a nitration reaction on benzene to form nitrobenzene. This is done by treating benzene with a mixture of concentrated nitric acid (HNO3) and concentrated sulfuric acid (H2SO4) at a temperature of around 50-55°C. The electrophilic substitution reaction introduces a nitro group (-NO2) to the benzene ring, leading to the formation of nitrobenzene.
02

Bromination of Nitrobenzene

Introduce a bromine atom to the benzene ring by treating nitrobenzene with bromine (Br2) in the presence of a catalyst like iron(III) bromide (FeBr3). The nitro group is a meta-directing group, which means the bromine will be added to the meta position relative to the nitro group, forming m-bromonitrobenzene.
03

Reduction of the Nitro Group

Convert the nitro group to an amino group by reducing the nitrobenzene. This can be done using tin (Sn) and hydrochloric acid (HCl), or alternatively by catalytic hydrogenation. This reaction will yield m-bromoaniline, where the amino group is now in place of the nitro group.
04

Diazotization of Aniline

Convert m-bromoaniline into a diazonium salt by treating it with sodium nitrite (NaNO2) and hydrochloric acid (HCl) at 0-5°C. This reaction forms m-bromobenzenediazonium chloride.
05

Sandmeyer Reaction

Finally, perform the Sandmeyer reaction by treating the diazonium salt with potassium iodide (KI). The diazonium group will be replaced by an iodine atom to form m-bromoiodobenzene, completing the synthesis of the required compound.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Nitration of Benzene
The process of nitrating benzene is an important foundation for many chemical synthesis reactions. During nitration, a nitro group (-NO2) is introduced into the benzene ring. This is achieved using a mixture of concentrated nitric acid (HNO3) and sulfuric acid (H2SO4). The sulfuric acid acts as a catalyst, helping to generate the nitronium ion (NO2+), which is the active electrophile in this reaction. Under controlled conditions, typically at temperatures around 50-55°C, this nitronium ion attacks the benzene, resulting in the substitution of a hydrogen atom with a nitro group. This forms nitrobenzene. This substitution is possible due to the electron-rich nature of benzene which can stabilize positively charged intermediates.
Bromination
Bromination involves the introduction of a bromine atom to an aromatic ring such as benzene. In the context of nitrobenzene, the bromination reaction is specifically directed to form m-bromonitrobenzene. This regioselectivity is guided by the nitro group, which is a deactivating and meta-directing group. The bromination process requires a catalyst, often iron(III) bromide (FeBr3), to generate the bromine cation (Br+). This cation then serves as the electrophile that attacks the benzene ring's electron-rich sites, ultimately adding the bromine atom at the meta position relative to the nitro group.
Reduction of Nitro Group
The reduction of the nitro group is a key transformation in organic chemistry, typically converting the nitro (-NO2) functionality to an amine (-NH2). For m-bromonitrobenzene, this reduction is accomplished by using reducing agents such as tin (Sn) and hydrochloric acid (HCl), or alternatively, catalytic hydrogenation can be used. This step transforms m-bromonitrobenzene into m-bromoaniline. The reduction alters the electronic properties of the molecule, changing its reactivity and paving the way for further synthetic transformations.
Diazotization
Diazotization is a process of converting an amine group into a diazonium salt, which is exceptionally useful in synthetic organic chemistry. For m-bromoaniline, this transformation involves treating the compound with sodium nitrite (NaNO2) and hydrochloric acid (HCl) at low temperatures (typically 0-5°C). This careful control of temperature is essential to maintain the stability of the diazonium salt. The reaction yields m-bromobenzenediazonium chloride, which is a versatile intermediate that can further participate in various substitution reactions.
Sandmeyer Reaction
The Sandmeyer Reaction is a classical method for replacing an amine group in an aromatic ring with other substituents using a diazonium salt as an intermediate. In this specific pathway, m-bromobenzenediazonium chloride reacts with potassium iodide (KI) to form m-bromoiodobenzene. The reaction proceeds through a radical mechanism, where the diazonium group is replaced by an iodine atom. This reaction provides an efficient route to synthesize aromatic halides and is particularly valuable for introducing iodine into aromatic systems.

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