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Give reason(s) why elemental nitrogen exists as a diatomic molecule whereas elemental phosphorus as a tetraatomic molecule.

Short Answer

Expert verified
Nitrogen forms a strong diatomic N鈧 due to triple bonds; phosphorus forms tetraatomic P鈧 due to single bonds and vacant d-orbitals.

Step by step solution

01

Understanding Nitrogen's Structure

Nitrogen, which has the atomic number 7, has a valence shell electron configuration of 2s虏2p鲁. Due to this configuration, nitrogen atoms tend to share three electrons with another nitrogen atom to achieve a stable octet. This results in a triple bond, denoted as N鈮, forming a diatomic N鈧 molecule known for its strong bond and non-reactive nature.
02

Exploring Phosphorus's Configuration

Phosphorus, having the atomic number 15, has a valence shell electron configuration of 3s虏3p鲁. Unlike nitrogen, phosphorus atoms prefer forming single bonds rather than triple bonds due to available vacant d-orbitals, which are capable of accommodating more electrons. This electronic arrangement allows phosphorus to form a tetraatomic structure (P鈧), where each phosphorus shares a single pair of electrons with three other phosphorus atoms, forming a stable tetrahedral shape.
03

Comparing Molecular Structures

The key difference between nitrogen and phosphorus bonding lies in orbital hybridization and the strength of bonds. Nitrogen forms a strong triple bond that stabilizes the diatomic molecule, while phosphorus, with available d-orbitals, forms weaker single bonds that stabilize the tetrahedral P鈧 molecule. The difference in bond strength and electron availability leads to their distinct molecular forms.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electronic Configuration
Electronic configuration is the arrangement of electrons in an atom's orbitals. For nitrogen, its electronic configuration is
  • 1s虏 2s虏 2p鲁
This shows that nitrogen has five electrons in its outer shell. These five electrons urge the atom to complete an octet, often resulting in sharing three electrons per atom to form elemental nitrogen as a diatomic molecule. This sharing leads to the formation of a strong triple bond, symbolized as N鈮.

In contrast, phosphorus has the electronic configuration
  • 1s虏 2s虏 2p鈦 3s虏 3p鲁
It has more electrons that can participate in bonding, including vacant d-orbitals in its third shell. These orbitals allow phosphorus atoms to expand their valency beyond an octet, leading to the formation of the tetraatomic P鈧 molecule with weaker single bonds.
Molecular Structure
Molecular structure refers to the specific arrangement of atoms within a molecule. For nitrogen, the molecular structure is simplistic yet robust due to the strong triple bond. The shared electrons create a strong, linear diatomic N鈧 molecule. This linear structure is very stable, rendering nitrogen less reactive.

On the other hand, phosphorus opts for a more complex structure. The P鈧 molecule forms a tetrahedral shape. Each phosphorus atom shares its electrons with three other phosphorus atoms, resulting in a 3-dimensional arrangement. This structure is a result of the ability of phosphorus to use its d-orbitals, which nitrogen lacks, to form stable bonds. This tetrahedral formation allows phosphorus atoms to achieve stability in a different way than nitrogen.
Valency
Valency is the number of available bonds an atom can form. It influences how atoms interact and combine to form molecules. Nitrogen displays a valency of three. This means it tends to form three covalent bonds, achieving an octet by sharing electrons, as seen in the formation of N鈧.

Phosphorus, however, can exhibit a valency greater than three due to its ability to make use of d-orbitals. This greater flexibility in bonding allows phosphorus atoms to utilize five electrons for bonding when forming compounds like phosphorus pentachloride (PCl鈧). However, in its elemental state as P鈧, it mainly shows a valency of three, aligning somewhat with sharing single pairs of electrons with neighboring phosphorus atoms in a tetrahedral geometry.

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Most popular questions from this chapter

Give reasons for the following : (i) The experimentally determined \(\mathrm{N}-\mathrm{F}\) bond length in \(\mathrm{NF}_{3}\) is greater than the sum of the single covalent bond radii of \(\mathrm{N}\) and \(\mathrm{F}\). [1995 - 2 Marks] (ii) Ammonium chloride is acidic in liquid ammonia solvent. [1991 - 1 Mark] (iii) Phosphine has lower boiling point than ammonia. [1989-1 Mark] (iv) \(\mathrm{H}_{3} \mathrm{PO}_{3}\) is a dibasic acid. [1989-1 Mark] (v) Orthophosphorus acid is not tribasic acid. [1987-1 Mark] (vi) A bottle of liquor ammonia should be cooled before opening the stopper. [1983-1 Mark] (vii) Orthophosphoric acid, \(\mathrm{H}_{3} \mathrm{PO}_{4}\), is tribasic, but phosphorous acid, \(\mathrm{H}_{3} \mathrm{PO}_{3}\), is dibasic. [1982 - 1 Mark]

Increasing order of extent of hydrolysis:\(\mathrm{CCl}_{4}, \mathrm{MgCl}_{2}, \mathrm{AlCl}_{3}, \mathrm{PCl}_{5}, \mathrm{SiCl}_{4}\)

The basicity of phosphorous acid \(\left(\mathrm{H}_{3} \mathrm{PO}_{3}\right)\) is \(\ldots \ldots \ldots \ldots . . .\) [1990-1 Mark]

Nitrogen dioxide cannot be obtained by heating : [1985-1 Mark] (a) \(\mathrm{KNO}_{3}\) (b) \(\mathrm{Pb}\left(\mathrm{NO}_{3}\right)_{2}\) (c) \(\mathrm{Cu}\left(\mathrm{NO}_{3}\right)_{2}\) (d) \(\mathrm{AgNO}_{3}\)

Arrange the following bonds according to their average bond energies in descending order: \(\mathrm{C}-\mathrm{Cl}, \mathrm{C}-\mathrm{Br}, \mathrm{C}-\mathrm{F}, \mathrm{C}-\mathrm{I}\) [Main Jan. 08, 2020 (II)] (a) \(\mathrm{C}-\mathrm{F}>\mathrm{C}-\mathrm{Cl}>\mathrm{C}-\mathrm{Br}>\mathrm{C}-\mathrm{I}\) (b) \(\mathrm{C}-\mathrm{Br}>\mathrm{C}-\mathrm{I}>\mathrm{C}-\mathrm{C} 1>\mathrm{C}-\mathrm{F}\) (c) \(\mathrm{C}-\mathrm{I}>\mathrm{C}-\mathrm{Br}>\mathrm{C}-\mathrm{Cl}>\mathrm{C}-\mathrm{F}\) (d) \(\mathrm{C}-\mathrm{Cl}>\mathrm{C}-\mathrm{Br}>\mathrm{C}-\mathrm{I}>\mathrm{C}-\mathrm{F}\)

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