Chapter 18: Problem 18
The number of molecules with energy greater than the threshold energy for a reaction increases five fold by a rise of temperature from \(27^{\circ} \mathrm{C}\) to \(42^{\circ} \mathrm{C}\). Its energy of activation in \(\mathrm{J} / \mathrm{mol}\) is (Take \(\left.\ln 5=1.6094 ; \mathrm{R}=8.314 \mathrm{~J} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}\right)\)
Short Answer
Step by step solution
Convert Temperatures to Kelvin
Setup the Arrhenius Equation for Both Temperatures
Solve for Activation Energy \(E_a\)
Final Answer and Interpretation
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Arrhenius Equation
- \( k \) is the rate constant, indicating how fast a reaction proceeds.
- \( A \) is the pre-exponential factor, relating to the frequency of collisions with the correct orientation.
- \( E_a \) represents the activation energy, the crucial energetic barrier that reactants must overcome.
- \( R \) is the universal gas constant (8.314 \( J \ mol^{-1} \ K^{-1} \)).
- \( T \) stands for temperature, measured in Kelvin.