Chapter 17: Problem 27
The molar conductivity of a solution of a weak acid \(\mathrm{H} X(0.01 \mathrm{M})\) is 10 times smaller than the molar conductivity of a solution of a weak acid \(\mathrm{H} Y(0.10 \mathrm{M})\). If \(\lambda_{\mathrm{X}^{-}}^{0} \approx \lambda_{\mathrm{Y}}^{0}\) the difference in their \(\mathrm{p} K_{a}\) values, \(\mathrm{p} K_{a}(\mathrm{H} X)\) \(-\mathrm{p} K_{a}(\mathrm{H} Y)\), is (consider degree of ionization of both acids to be \(<<1\) )
Short Answer
Step by step solution
Understanding Molar Conductivity
Relating Concentration and Conductivity
Calculating the Degree of Ionization
Equating and Solving for \(pK_a\) Difference
Determining \(pK_a\) Difference
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