/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 2 compute the standard error of \(... [FREE SOLUTION] | 91Ó°ÊÓ

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compute the standard error of \(\left(\bar{Y}_{1}-\bar{Y}_{2}\right)\) for the following data: $$ \begin{array}{|lcc|} \hline & \text { Sample 1 } & \text { Sample 2 } \\ \hline n & 10 & 10 \\ \bar{y} & 125 & 217 \\ s & 44.2 & 28.7 \\ \hline \end{array} $$

Short Answer

Expert verified
The standard error of the difference between the means \(\bar{Y}_{1} - \bar{Y}_{2}\) is approximately 16.66.

Step by step solution

01

Understand the Standard Error of the Difference in Sample Means

The standard error of the difference between two sample means, \(\bar{Y}_{1} - \bar{Y}_{2}\), is calculated using the standard errors of both samples. The formula is \(SE_{\bar{Y}_{1} - \bar{Y}_{2}} = \sqrt{{SE_{\bar{Y}_{1}}^2 + SE_{\bar{Y}_{2}}^2}}\), where \(SE_{\bar{Y}_{i}} = \frac{s_i}{\sqrt{n_i}}\) for \(i = 1, 2\).
02

Calculate the Standard Error of Each Sample Mean

The standard error for each sample mean is given by the formula \(SE_{\bar{Y}_{i}} = \frac{s_i}{\sqrt{n_i}}\). For Sample 1, the standard error is \(SE_{\bar{Y}_{1}} = \frac{44.2}{\sqrt{10}}\). For Sample 2, it is \(SE_{\bar{Y}_{2}} = \frac{28.7}{\sqrt{10}}\).
03

Compute the Standard Errors for Both Samples

Compute \(SE_{\bar{Y}_{1}}\) and \(SE_{\bar{Y}_{2}}\) using the values from Step 2. For Sample 1: \(SE_{\bar{Y}_{1}} = \frac{44.2}{3.162} \approx 13.97\). For Sample 2: \(SE_{\bar{Y}_{2}} = \frac{28.7}{3.162} \approx 9.07\).
04

Calculate the Standard Error of the Difference Between Sample Means

Use the computed standard errors of the individual sample means to find the standard error of the difference: \(SE_{\bar{Y}_{1} - \bar{Y}_{2}} = \sqrt{SE_{\bar{Y}_{1}}^2 + SE_{\bar{Y}_{2}}^2}\). Substitute the values to get \(SE_{\bar{Y}_{1} - \bar{Y}_{2}} = \sqrt{(13.97)^2 + (9.07)^2}\).
05

Final Calculation

Carry out the arithmetic to find the standard error of the difference: \(SE_{\bar{Y}_{1} - \bar{Y}_{2}} = \sqrt{(13.97)^2 + (9.07)^2} \approx \sqrt{195.2 + 82.3} \approx \sqrt{277.5} \approx 16.66\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Mean
The sample mean is a fundamental statistic that represents the average of a set of individual data points from a sample of a larger population. It is denoted by \( \bar{Y} \), where \( Y \) signifies the data points and the bar symbol indicates an average. The sample mean is calculated by summing all the observations in the sample and then dividing by the number of observations, expressed as \( \bar{Y} = \frac{1}{n}\sum_{i=1}^{n} Y_i \). In the given exercise, we have two sample means, \( \bar{Y}_{1} \) and \( \bar{Y}_{2} \), with respective values of 125 and 217.

Understanding the concept of the sample mean is essential because it provides a measure of the central tendency of the data and serves as a point of comparison for further statistical analysis. It is particularly important in estimating the true mean of the population from which the sample is drawn. When comparing two sample means, as in the exercise, we can gain insights into the differences that may exist between two populations or groups.
Standard Error Calculation
The standard error measures the precision of the sample mean as an estimate of the population mean. It is the standard deviation of the sampling distribution of the sample mean. The calculation of standard error helps in understanding the variability within the samples, taking into account the sample size. Larger samples tend to have smaller standard errors, as they provide more reliable estimates of the population mean.

The standard error of the sample mean (SE) is computed using the formula \( SE_{\bar{Y}} = \frac{s}{\sqrt{n}} \), where \( s \) is the sample standard deviation and \( n \) is the sample size. In our exercise, the standard errors for Sample 1 and Sample 2 are calculated using their respective standard deviations (44.2 and 28.7) and sample sizes (10 for both).

The resulting standard errors, 13.97 for Sample 1 and 9.07 for Sample 2, indicate the variability of each sample mean estimate. When we investigate the difference between two sample means, we are essentially exploring whether this observed difference could be due to random variation alone or if it reflects a true difference in the underlying populations.
Statistical Inference
Statistical inference involves using data from a sample to make estimates or test hypotheses about the characteristics of a larger population. A key part of statistical inference is determining the likelihood that any observed differences in sample statistics, such as sample means, are not due to chance alone.

The standard error of the difference between two sample means plays a crucial role in this process. By calculating the standard error of the difference, as detailed in the exercise, which turns out to be approximately 16.66, we can assess the precision of the estimate of the difference in population means. This value allows us to construct confidence intervals or perform hypothesis tests, such as a t-test, to evaluate whether the difference between the sample means is statistically significant.

Statistical inference, therefore, extends beyond simple comparisons and provides a methodological framework for making informed decisions about the populations from which the samples are drawn, based on sample data. Interpreting standard errors and using them to infer population characteristics is a key skill in many fields, including economics, psychology, and medicine.

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Most popular questions from this chapter

Data from two samples gave the following results: $$\begin{array}{|lcc|}\hline & \text { Sample 1 } & \text { Sample 2 } \\\\\hline n & 22 & 21 \\\\\bar{y} & 1.7 & 2.4 \\\\\text { SE } & 0.5 & 0.7 \\\\\hline \end{array}$$ Compute the standard error of \(\left(\bar{Y}_{1}-\bar{Y}_{2}\right)\).

In a study of larval development in the tufted apple budmoth (Platynota idaeusalis), an entomologist measured the head widths of 50 larvae. All 50 larvae had been reared under identical conditions and had moulted six times. The mean head width was \(1.20 \mathrm{~mm}\) and the standard deviation was \(0.14 \mathrm{~mm}\). Construct a \(90 \%\) confidence interval for the population mean. \(^{17}\)

In an experiment on soybean varieties, individually potted soybean plants were grown in a greenhouse, with 10 plants of each variety used in the experiment. From the harvest of each plant, five seeds were chosen at random and individually analyzed for their percentage of oil. This gave a total of 50 measurements for each variety. To calculate the standard error of the mean for a variety, the experimenter calculated the standard deviation of the 50 observations and divided by \(\sqrt{50}\). Why would this calculation be of doubtful validity?

A group of 101 patients with end-stage renal disease were given the drug epoetin. \({ }^{19}\) The mean hemoglobin level of the patients was \(10.3(\mathrm{~g} / \mathrm{dl})\), with an \(\mathrm{SD}\) of 0.9 . Construct a \(95 \%\) confidence interval for the population mean.

For the 28 lamb birthweights of Example \(6.2 .2,\) the mean is \(5.1679 \mathrm{~kg},\) the \(\mathrm{SD}\) is \(0.6544 \mathrm{~kg},\) and the \(\mathrm{SE}\) is \(0.1237 \mathrm{~kg}\) (a) Construct a \(95 \%\) confidence interval for the population mean. (b) Construct a \(99 \%\) confidence interval for the population mean. (c) Interpret the confidence interval you found in part (a). That is, explain what the numbers in the interval mean. (Hint: See Examples 6.3 .4 and \(6.3 .5 .)\) (d) Often researchers will summarize their data in reports and articles by writing \(\bar{y} \pm \mathrm{SD}(5.17 \pm 0.65)\) or \(\bar{y} \pm \mathrm{SE}(5.17 \pm 0.12) .\) If the researcher of this study is planning to compare the mean birthweight of these Rambouillet lambs to another breed, Booroolas, which style of presentation should she use?

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