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In Drosophila, a recessive mutation called chocolate (c) causes the eyes to be darkly pigmented. The mutant phenotype is indistinguishable from that of an autosomal recessive mutation called brown ( \(b w\) ). A cross of chocolateeyed females to homozygous brown males yielded wildtype \(\mathrm{F}_{1}\) females and darkly pigmented \(\mathrm{F}_{1}\) males. If the \(\mathrm{F}\) flies are intercrossed, what types of progeny are expected, and in what proportions? (Assume the double mutant combination has the same phenotype as either of the \(\sin\) gle mutants alone.)

Short Answer

Expert verified
Expect darkly pigmented: wildtype flies in a 5:3 ratio.

Step by step solution

01

Interpret the Problem

In this problem, you're given two recessive mutations in Drosophila: chocolate (c) and brown (bw). Chocolate is X-linked, while brown is autosomal. Females cross chocolate-eyed with brown-eyed males. We need to predict offspring types and ratios from this genetic cross.
02

Analyze Parent Genotypes

The chocolate-eyed females have the genotype \( X^cX^c bw^+bw^+ \), where \( X^c \) is the recessive chocolate allele, and the brown-eyed males have the genotype \( X^+Y bwbw \), where \( bw \) is the recessive brown allele. The X-linked nature of chocolate means \( Y \) does not carry an allele for eye color.
03

Deduce F1 Generation

The cross results in progeny: F1 females with genotype \( X^cX^+ bw^+bw \), showing wildtype phenotype since both chocolate and brown are recessive, and F1 males with genotype \( X^cY bw^+bw \), showing dark pigment due to the recessive x-linked chocolate.
04

Perform F1 Intercross

Wildtype F1 females \( X^cX^+ bw^+bw \) are crossed with darkly pigmented F1 males \( X^cY bw^+bw \). Construct a Punnett square considering these genotypes to find expected F2 progeny combinations.
05

Determine Punnett Square Results

Crossing the F1 genotypes, we expect the following F2 possibilities:1. Females: \( X^cX^c bwbw^+ \) (darkly pigmented), \( X^cX^+ bw^+bw \) (wildtype), \( X^cX^+ bwbw \) (darkly pigmented), \( X^+X^+ bw^+bw \) (wildtype).2. Males: \( X^cY bw^+bw \) (darkly pigmented), \( X^cY bwbw \) (darkly pigmented), \( X^+Y bw^+bw \) (wildtype), \( X^+Y bwbw \) (darkly pigmented).
06

Calculate Ratios and Proportions

Count all the genotype occurrences from the Punnett Square: - Homozygous and hemizygous dark-eyed flies appear in 5/8 of the cases. - Wildtype flies appear in 3/8 of the cases. So the expected phenotypic ratio of darkly pigmented to wildtype is 5:3.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Recessive Mutation
In genetics, a recessive mutation occurs when an allele must be present in two copies (homozygous) to exhibit a specific phenotype. If only one copy is present, as in a heterozygous arrangement, the dominant allele will mask the effects of the recessive one. Recessive mutations are often denoted with lowercase letters.

In the given Drosophila problem, we have two recessive mutations. The chocolate mutation is recessive and X-linked, while the brown mutation is recessive and autosomal. This means that for the chocolate mutation to show, it has to be present on both of the female's X chromosomes or the single X chromosome in males. Similarly, the brown mutation needs to be present on both alleles of an autosome pair for its phenotype to be expressed.

These recessive traits primarily affect the progeny's phenotype when two carriers mate, as seen with the two Drosophila mutations in this exercise. Understanding these concepts helps in predicting the outcome of genetic crosses, especially when using tools like Punnett squares.
Punnett Square
The Punnett square is a valuable tool in genetics used to visualize and predict the results of a genetic cross. It displays all possible genotypes that can result from combining the alleles of each parent. By setting up the Punnett square with one parent's alleles across the top and the other's down the side, we can fill in potential gamete combinations and observe the resulting offspring genotypes and phenotypes.

In the exercise, we cross chocolate-eyed females and brown-eyed males. The Punnett square helps us predict the offspring's genotypes from different combinations of these recessive alleles. It shows:
  • If both chocolate and brown mutations are present, the phenotype reflects dark pigmentation.
  • Other combinations may result in wildtype phenotypes depending on the presence of dominant alleles.
The end result is the phenotypic ratio of 5:3 for darkly pigmented to wildtype flies. Understanding how to set up and interpret a Punnett square is essential for visualizing genetic crosses.
X-linked Inheritance
X-linked inheritance is a pattern of genetic transmission that involves genes located on the X chromosome. This form of inheritance displays unique patterns, particularly because the X chromosome is one of the two sex chromosomes in many organisms, including Drosophila.

Differences in expression between males and females often occur because males have one X and one Y chromosome, while females have two X chromosomes. This makes males more susceptible to X-linked recessive mutations since they only have one copy of the X chromosome. In our exercise, the chocolate mutation is X-linked, meaning that all males who inherit this allele from their mothers will express the trait if it is recessive.

Females would need to inherit the allele from both parents to express the trait due to their two X chromosomes. This creates different expectations for progeny in terms of both genotype and phenotype. Recognizing and applying the principles of X-linked inheritance can help explain why certain traits appear more often in one sex or show distinct behavioral patterns across generations.

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Most popular questions from this chapter

In Drosophila, vermilion eye color is due to a recessive allele \((v)\) located on the \(\mathrm{X}\) chromosome. Curved wings is due to a recessive allele ( \(c u\) ) located on one autosome, and ebony body is due to a recessive allele ( \(e\) ) located on another autosome. A vermilion male is mated to a curved, ebony female, and the \(\mathrm{F}_{1}\) males are phenotypically wild-type. If these males were backcrossed to curved, ebony females, what proportion of the \(\mathrm{F}_{2}\) offspring will be wild-type males?

A Drosophila female heterozygous for the recessive X-linked mutation \(w\) (for white eyes) and its wild-type allele \(w^{+}\) is mated to a wild-type male with red eyes. Among the sons, half have white eyes and half have red eyes. Among the daughters, nearly all have red eyes; however, a few have white eyes. Explain the origin of these white-eyed daughters.

Suppose that a mutation occurred in the \(S R Y\) gene on the human Y chromosome, knocking out its ability to produce the testis-determining factor. Predict the phenotype of an individual who carried this mutation and a normal X chromosome.

What are the genetic differences between male- and female-determining sperm in animals with heterogametic males?

In 1908 F. M. Durham and D. C. E. Marryat reported the results of breeding experiments with canaries. Cinnamon canaries have pink eyes when they first hatch, whereas green canaries have black eyes. Durham and Marryat crossed cinnamon females with green males and observed that all the \(\mathrm{F}_{1}\) progeny had black eyes, just like those of the green strain. When the \(\mathrm{F}_{1}\) males were crossed to green females, all the male progeny had black eyes, whereas all the female progeny had either black or pink eyes, in about equal proportions. When the \(\mathrm{F}_{1}\) males were crossed to cinnamon females, four classes of progeny were obtained: females with black eyes, females with pink eyes, males with black eyes, and males with pink eyes- all in approximately equal proportions. Propose an explanation for these findings.

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