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How many different kinds of \(\mathrm{F}_{1}\) gametes, \(\mathrm{F}_{2}\) genotypes, and \(\mathrm{F}_{2}\) phenotypes would be expected from the following crosses: (a) \(A A \times a a\) (b) \(A A B B \times a a b b\) (c) \(A A B B C C \times a a b b c c\) (d) What general formulas are suggested by these answers?

Short Answer

Expert verified
1 type of F1 gamete. \(3^n\) F2 genotypes, \(2^n\) F2 phenotypes. General formulas: \(F_2\) genotypes \(= 3^n\), \(F_2\) phenotypes \(= 2^n\).

Step by step solution

01

Determine F1 Gametes for Cross (a)

In cross (a), both parents are homozygous for a single gene: \(A A \times a a\). The \(F_1\) generation inherits one allele from each parent. Thus, the \(F_1\) gametes produced will be of genotype \(A a\). There is only 1 type of \(F_1\) gamete.
02

Determine F2 Genotypes for Cross (a)

From the \(F_1\) generation \(A a\), self-crossing (\(A a \times A a\)) will produce \(F_2\) genotypes: \(A A\), \(A a\), and \(a a\). According to Mendelian inheritance, the ratio is 1:2:1, so there are 3 different genotypes.
03

Determine F2 Phenotypes for Cross (a)

In \(F_2\), the phenotypes are determined by the dominant and recessive alleles: \(A\) is dominant over \(a\). The possible phenotypes are 'A' phenotype and 'a' phenotype, resulting in 2 different phenotypes.
04

Determine F1 Gametes for Cross (b)

In cross (b), we have parents with genotypes \(A A B B \times a a b b\). The \(F_1\) gametes produced will be \(A a B b\). There is only 1 type of \(F_1\) gamete for this dihybrid cross.
05

Determine F2 Genotypes for Cross (b)

From the \(F_1\) generation \(A a B b\), self-crossing (\(A a B b \times A a B b\)) yields 9 different genotypes: \(AABB, AABb, AAbb, AaBB, AaBb, Aabb, aaBB, aaBb, aabb\).
06

Determine F2 Phenotypes for Cross (b)

Each gene pair (\(A\) with \(a\) and \(B\) with \(b\)) shows 2 phenotypes: dominant and recessive. Therefore, the combination \(A a B b \times A a B b\) results in 4 different phenotypes: both dominant, one dominant (A) & one recessive (b), one recessive (a) & one dominant (B), both recessive.
07

Determine F1 Gametes for Cross (c)

In cross (c), the parents are \(A A B B C C \times a a b b c c\). The \(F_1\) gametes will be \(A a B b C c\), with 1 type of \(F_1\) gamete.
08

Determine F2 Genotypes for Cross (c)

From the \(F_1\) generation \(A a B b C c\), self-crossing \((A a B b C c \times A a B b C c)\) yields \(3^3 = 27\) different genotypes.
09

Determine F2 Phenotypes for Cross (c)

For the \(F_2\) phenotypes from \(A a B b C c\), each gene results in 2 phenotypes (dominant and recessive), leading to \(2^3 = 8\) different phenotypes.
10

Formulate General Rule

For each gene, an \(F_1\) gamete has 1 type. The number of \(F_2\) genotypes \(= 3^n\) and the number of \(F_2\) phenotypes \(= 2^n\), where \(n\) is the number of genes involved in the cross.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

F1 Generation
The F1 generation, or the first filial generation, is the immediate offspring resulting from a cross between two parent organisms. In Mendelian genetics, this generation is crucial because it establishes which traits are dominant and which are recessive.

Consider a simple Mendelian cross, such as in case (a) where we have a cross between two homozygous individuals: \(AA\) \(\times\) \(aa\). All F1 offspring inherit one allele from each parent, resulting in heterozygous individuals \(Aa\). - *Single gene cross*: All gametes are \(Aa\), showing only the dominant trait.- *Dihybrid cross* (as in case (b)): From \(AABB\) \(\times\) \(aabb\), the F1 generation gametes will be \(AaBb\), showing both dominant traits.- *Trihybrid cross* (as in case (c)): From \(AABBCC\) \(\times\) \(aabbcc\), the F1 generation results in gametes \(AaBbCc\), showing a mix of all dominant traits.In each of these scenarios, the number of different F1 gametes remains the same: only one type, because each gene's outcome in the F1 generation is heterozygous, displaying only the dominant phenotype. This stage sets the genetic foundation for further generations.
F2 Generation
The F2 generation, or the second filial generation, is produced by self-pollinating or crossing F1 individuals with each other. This step helps to reveal the genetic variation concealed in the F1 generation.

In Mendelian inheritance, the F2 generation allows us to observe the segregating traits and their ratios, which is fundamental to understanding Mendelian ratios.- In the monohybrid cross (a), the genotypes achieved are \(AA\), \(Aa\), and \(aa\), resulting in a 1:2:1 ratio. This highlights the classic Mendelian pattern of inheritance.- In the dihybrid cross (b), \(AaBb\) \(\times\) \(AaBb\) leads to 9 distinct genotypes: \(AABB, AABb, AAbb, AaBB, AaBb, Aabb, aaBB, aaBb, aabb\). These genotype results are due to the interaction of two separate gene pairs.- For the trihybrid cross (c), the genotypic combinations increase significantly, with \(3^3 = 27\) different genotypes possible as each gene independently segregates.The expansion of genetic variation in the F2 generation underscores the principles of independent assortment and segregation, pivotal components of Mendel's laws.
Dominant and Recessive Alleles
Understanding dominant and recessive alleles is essential to predicting offspring phenotypes. Dominant alleles mask the effect of recessive alleles in heterozygous pairings. In a Mendelian cross, this concept is key to determining what traits will appear in the phenotypes.

In the simplest scenario such as cross (a), where \(AA\) is crossed with \(aa\), we observe the classic dominant-recessive relationship:- If \(A\) (dominant allele) is present alongside \(a\) (recessive allele), the dominant trait manifests in the offspring.- Recessive traits, represented by \(aa\), will only express themselves when no dominant allele is present.In more complex crosses such as (b) or (c), each gene independently adheres to the laws of dominance and recessiveness, impacting the combinations of phenotypes:- The F2 generations in dihybrid and trihybrid crosses allow us to witness how dominant and recessive alleles from multiple genes interact.- For a dihybrid cross like (b), there are four phenotypes: both dominant, one dominant and one recessive from each trait pair, and both recessive.By understanding how dominant and recessive alleles influence organism traits, we can predict the appearance and genetic diversity in offspring predicated upon allele composition.

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Most popular questions from this chapter

Albinism in humans is caused by a recessive allele \(a\). From marriages between people known to be carriers \((A a)\) and people with albinism (aa), what proportion of the children would be expected to have albinism? Among three children, what is the chance of one without albinism and two with albinism?

Seed capsules of the Shepherd's purse are either triangular or ovoid. A cross between a plant with triangular seed capsules and a plant with ovoid seed capsules yielded \(\mathrm{F}_{1}\), hybrids that all had triangular seed capsules. When these \(F_{1}\) hybrids were intercrossed, they produced \(80 \mathrm{F}_{2}\) plants, 72 of which had triangular seed capsules and 8 of which had ovoid seed capsules. Are these results consistent with the hypothesis that capsule shape is determined by a single gene with two alleles?

A researcher studied six independently assorting genes in a plant. Each gene has a dominant and a recessive allele: \(R\) black stem, \(r\) red stem; \(D\) tall plant, \(d\) dwarf plant; \(C\) full pods, \(c\) constricted pods; \(O\) round fruit, \(o\) oval fruit; \(H\) hairless leaves, \(b\) hairy leaves; \(W\) purple flower, w white flower. From the cross \((\mathrm{P} 1) R r D d c C O H b W w \times(\mathrm{P} 2) R r d d C c o o H b w w\),.(a) How many kinds of gametes can be formed by P1? (b) How many genotypes are possible among the progeny of this cross? (c) How many phenotypes are possible among the progeny? (d) What is the probability of obtaining the \(R r D d \propto O o b b w w\) genotype in the progeny? (e) What is the probability of obtaining a black, dwarf, constricted, oval, hairy, purple phenotype in the progeny?

Peas heterozygous for three independently assorting genes were intercrossed. (a) What proportion of the offspring will be homozygous for all three recessive alleles? (b) What proportion of the offspring will be homozygous for all three genes? (c) What proportion of the offspring will be homozygous for one gene and heterozygous for the other two? (d) What proportion of the offspring will be homozygous for the recessive allele of at least one gene?

Mendel testcrossed pea plants grown from yellow, round \(\mathrm{F}_{1}\) seeds to plants grown from green, wrinkled seeds and obtained the following results: 31 yellow, round; 26 green, round; 27 yellow, wrinkled; and 26 green, wrinkled. Are these results consistent with the hypothesis that seed color and seed texture are controlled by independently assorting genes, each segregating two alleles?

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