Chapter 8: Problem 30
Expand \(|x|\) in the interval \((-1,+1)\) in terms of Legendre polynomials.
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Chapter 8: Problem 30
Expand \(|x|\) in the interval \((-1,+1)\) in terms of Legendre polynomials.
These are the key concepts you need to understand to accurately answer the question.
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Use the generating function for Legendre polynomials to show that \(P_{n}(1)=1, P_{n}(-1)=(-1)^{n}, P_{n}(0)=0\) for odd \(n\), and \(P_{n}^{\prime}(1)=n(n+1) / 2 .\)
Apply the general formalism of the recurrence relations given in the book to find the following two relations for Laguerre polynomials: (a) \(n L_{n}^{v}-(n+v) L_{n-1}^{v}-x \frac{d L_{n}^{v}}{d x}=0 .\) (b) \((n+1) L_{n+1}^{v}-(2 n+v+1-x) L_{n}^{v}+(n+v) L_{n-1}^{v}=0 .\)
Show that \(g(x, t)=g(-x,-t)\) for both Hermite and Legendre polynomials. Now expand \(g(x, t)\) and \(g(-x,-t)\) and compare the coefficients of \(t^{n}\) to obtain the parity relations for these polynomials: $$H_{n}(-x)=(-1)^{n} H_{n}(x) \text { and } P_{n}(-x)=(-1)^{n} P_{n}(x) .$$
Use a recurrence relations for Hermite polynomials to show that $$H_{n}(0)=\left\\{\begin{array}{ll} 0 & \text { if } n \text { is odd } \\\\(-1)^{m} \frac{(2 m) !}{m !} & \text { if } n=2 m . \end{array}\right.$$
Using integration by parts several times, show that $$\int_{-1}^{1}\left(1-x^{2}\right)^{n} d x=\frac{2^{m} n(n-1) \cdots(n-m+1)}{3 \cdot 5 \cdot 7 \cdots(2 m-1)} \int_{-1}^{1} x^{2 m}\left(1-x^{2}\right)^{n-m} d x .$$ Now show that $$\int_{-1}^{1}\left(1-x^{2}\right)^{n} d x=\frac{2 \Gamma\left(\frac{1}{2}\right) n !}{(2 n+1) \Gamma\left(n+\frac{1}{2}\right)}$$
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