/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 3 Many animal populations have dec... [FREE SOLUTION] | 91Ó°ÊÓ

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Many animal populations have decreasing per-capita birth rates when the population density increases, as well as increasing per-capita death rates. Suppose the density dependent per-capita birth rate \(B(X)\) and density dependent death rate \(A(X)\) is given by $$ B(X)=\beta-(\beta-\alpha) \delta \frac{X}{K}, \quad A(X)=\alpha+(\beta-\alpha)(1-\delta) \frac{X}{K} $$ where \(K\) is the population carrying capacity, \(\beta\) is the intrinsic per- capita birth rate, \(\alpha\) is the intrinsic per-capita death rate and \(\delta\), where \(0 \leq \delta \leq 1\), is a parameter describing the extent that density dependence is expressed in births or deaths. Show that this still gives rise to the standard logistic differential equation $$ \frac{d X}{d t}=r X\left(1-\frac{X}{K}\right) $$

Short Answer

Expert verified
The given expressions reduce to the logistic equation \( \frac{dX}{dt} = rX\left(1 - \frac{X}{K}\right) \).

Step by step solution

01

Understand the Equations

Identify that we have expressions for the density-dependent birth rate \(B(X)\) and death rate \(A(X)\) which vary with population \(X\) and introduce terms for density dependence given by the carrying capacity \(K\), intrinsic rates \(\alpha\) and \(\beta\), and parameter \(\delta\).
02

Define Net Growth Rate

The net growth rate \(dX/dt\) is given by the difference between the per-capita birth rate and death rate, expressed as: \( \frac{dX}{dt} = X(B(X) - A(X)) \). This implies \( \frac{dX}{dt} = X\left(\beta-(\beta-\alpha) \delta \frac{X}{K} - \left(\alpha+(\beta-\alpha)(1-\delta) \frac{X}{K}\right)\right) \).
03

Simplify the Expression

Combine terms in the expression from Step 2. This gives: \( \frac{dX}{dt} = X\left( \beta - \alpha - (\beta - \alpha) \frac{X}{K} \right) \).
04

Identify Logistic Growth

Recognize that the simplified form from Step 3, \( \frac{dX}{dt} = rX\left(1 - \frac{X}{K}\right) \), matches the standard logistic differential equation where \( r = \beta - \alpha \) is the net intrinsic rate of population growth.
05

Conclude

Conclude that density-dependent birth and death rates modified by the parameter \(\delta\) still form the standard logistic differential equation, demonstrating the role of intrinsic rates and carrying capacity in limiting growth.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Population Dynamics
Population dynamics is the study of how populations of living organisms change over time and space. It explores various factors that influence the size and composition of populations. In this context, population refers to a group of individuals of the same species living in a specific area. Understanding how populations grow and shrink helps in ecosystem management and conservation efforts. This dynamic process can be impacted by several factors, including birth rates, death rates, immigration, and emigration.

In the logistic growth model, population dynamics are influenced by both the intrinsic factors, such as birth and death rates, and extrinsic factors, like the availability of resources. As a population approaches its carrying capacity, the growth rate slows down, leading to a balanced ecosystem. Identifying these factors and understanding their interactions is crucial for managing populations effectively. It also helps in predicting changes in the population size in response to different environmental pressures.
Density Dependent Rates
Density dependent rates are factors in population dynamics that change based on the population density. When a population is small, resources like food, water, and space are typically more abundant, leading to higher per-capita birth rates and lower death rates. However, as the population grows, these resources become limited, affecting the birth and death rates.

The logistic growth model incorporates density dependent factors to show how they impact population changes. The birth rate, noted as \(B(X)\), decreases as population density increases, while the death rate, \(A(X)\), increases. This adjustment ensures that populations do not grow indefinitely and stabilize around the carrying capacity \(K\). Essentially, density dependent rates act as a natural check, preventing overpopulation and the depletion of resources.
Carrying Capacity
Carrying capacity, denoted as \(K\), refers to the maximum number of individuals that an environment can support sustainably. It is a crucial concept in population dynamics and the logistic growth model. Carrying capacity is determined by the availability of resources such as food, water, and shelter, as well as the rate at which these resources can regenerate.

Once a population reaches its carrying capacity, its growth levels off, resulting in an equilibrium state where birth rates equal death rates. This ensures that the population size remains stable over time. In the mathematical expression of the logistic growth model, carrying capacity is what keeps the population from growing unrestricted, acting as a balancing point for the population. An understanding of carrying capacity allows for the prediction of how a population can support itself and maintain balance within its ecosystem.
Differential Equations
Differential equations are mathematical tools used to describe the relationship between a function and its derivatives. In the context of population dynamics, differential equations help model changes in population size over time. They are particularly useful for representing continuous growth processes, such as those seen in the logistic growth model.

The logistic differential equation used in this context is \( \frac{dX}{dt} = r X \left(1 - \frac{X}{K}\right) \). Here, \(\frac{dX}{dt}\) represents the change in population size over time, \(r\) represents the net intrinsic growth rate (the difference between birth and death rates), and \(X\) is the population size. The equation shows how population growth slows as it approaches carrying capacity \(K\). By using differential equations, researchers can forecast how populations grow, make decisions on conservation strategies, and anticipate the possible effects of environmental changes.

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Most popular questions from this chapter

Stability of 2-cycles. Consider the discrete logistic equation (with \(K=1\) ) $$ X_{n+1}=X_{n}+r X_{n}\left(1-X_{n}\right) $$ (a) Show that every second term in the sequence \(X_{0}, X_{1}, X_{2}, \ldots\) satisfies the difference equation $$ \begin{gathered} X_{n+2}=\left(1+2 r+r^{2}\right) X_{n}-\left(2 r+3 r^{2}+r^{3}\right) X_{n}^{2} \\ +\left(2 r^{2}+2 r^{3}\right) X_{n}^{3}-r^{3} X_{n}^{4} \end{gathered} $$ (b) For equilibrium solutions, let \(S=X_{n+2}=X_{n}\) and obtain a quartic equation (that is, an equation with the unknown raised to the fourth power, at most). Explain why \(S=0\) and \(S=1\) must be solutions of this quartic equation. Hence show that the other two solutions are $$ S=\frac{(2+r) \pm \sqrt{r^{2}-4}}{2 r} $$ [Note: Comparing with Figure \(3.10(r=2.2)\) we see that these two values of the two non-zero equilibrium solutions are the values between which the population oscillates in a two-cucle. Furthermore, when \(r\) increases to where these two equilibrium solutions become unstable this corresponds to where the two-cycle changes to a four-cycle.]

A chemostat is used by microbiologists and ecologists to model aquatic environments, or waste treatment plants. It consists of a tank filled with a mixture of some medium and nutrients, which microorganisms require to grow and multiply. A fresh nutrient-medium mixture is pumped into the tank at a constant rate \(F\) and the tank mixture is pumped from the tank at the same rate. In this way the volume of liquid in the tank remains constant. Let \(S(t)\) denote the concentration of the nutrient in the tank at time \(t\), and assume the mixture in the tank is well stirred. Let \(x(t)\) denote the concentration of the microorganism in the tank at time \(t .\) (a) Draw a compartmental diagram for the system. (b) In the absence of the organism, suggest a model for the rate of change of \(S(t)\). (c) If the microorganisms' per-capita uptake of the nutrient is dependent on the amount of nutrient present and is given by \(p(S)\), and the per-capita reproduction rate of the microorganism is directly proportional to \(p(S)\), extend the model equation above to include the effect of the organism. (The per-capita uptake function measures the rate at which the organism is able to absorb the nutrient when the nutrient's concentration level is \(S .)\) (d) Now develop an equation describing the rate of change of the concentration of the live organism \(\left(x^{\prime}\right)\) in the tank to derive the second equation for the system. (e) The nutrient uptake function \(p(S)\) can be shown experimentally to be a monotonically increasing function bounded above. Show that a Michaelis-Menten type function $$ p(S)=\frac{m S}{a+S} $$ with \(m\) and a positive, non-zero constants, satisfies these requirements. What is the maximum absorption rate? And why is a called the half-saturation constant? (Hint: The maximum absorption rate is the maximum reached by \(p(S)\). For the second part consider \(p(a) .)\) This system of equations is known as the Monod Model for single species growth and was developed by Jaques Monod in \(1950 .\)

In view of the potentially disastrous effects of overfishing causing a population to become extinct, some governments impose quotas which vary depending on estimates of the population at the current time. One harvesting model that takes this into account is $$ \frac{d X}{d t}=r X\left(1-\frac{X}{K}\right)-h_{0} X $$ (a) Show that the only non-zero equilibrium population is $$ X_{e}=K\left(1-\frac{h}{r}\right) $$ (b) At what critical harvesting rate can extinction occur? Although extinction can occur with this model, as the harvesting parameter \(h\) increases towards the critical value the equilibrium population tends to zero. This contrasts with the constant harvesting model in Section \(3.3\) and Question 5 , where a sudden population crash (from a large population to extinction) can occur as the harvesting rate increases beyond a critical value.

Investigating parameter change. Using Maple or MATLAB examine the effect of increasing the parameter \(r\) on the solution to the equation $$ X_{n+1}=X_{n} e^{a\left(1-X_{n} / K\right)}, \quad \text { where } \quad a=\ell \mathrm{n}(r+1) $$ Establish (roughly) for what values of \(r\) the system undergoes its first two bifurcations. (Code can be adapted from that in Section 3.6.)

A population, initially consisting of 1000 mice, has a per-capita birth rate of 8 mice per month (per mouse) and a per-capita death rate of 2 mice per month (per mouse). Also, 20 mouse traps are set each week and they are always filled. Write down a word equation describing the rate of change in the number of mice and hence write down a differential equation for the population.

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