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91Ó°ÊÓ

If the dominant allele \(A\) is necessary for hearing in humans, and another allele, \(B\), located on a different chromosome, results in deafness no matter what other genes are present, what percentage of the offspring of the marriage of \(a a B b \times A a b b\) will be deaf?

Short Answer

Expert verified
50% of the offspring will be deaf.

Step by step solution

01

Understanding the Cross

We need to determine the genetic cross between two parents: parent 1 with genotype \(aaBb\) and parent 2 with genotype \(Aabb\). The dominant allele \(A\) is necessary for hearing, but allele \(B\) causes deafness regardless of the presence of \(A\).
02

Determine Possible Gametes for Parent 1

The first parent \(aaBb\) can produce the following gametes: \(aB\) and \(ab\), as allele \(a\) occurs with either allele \(B\) or \(b\).
03

Determine Possible Gametes for Parent 2

The second parent \(Aabb\) can produce these gametes: \(Ab\) and \(ab\), as the allele \(A\) pairs only with \(b\) and allele \(a\) also pairs with \(b\).
04

Create the Punnett Square

Using the gametes formed, create a Punnett Square to determine the offspring genotypes:- Top: \(aB\), \(ab\)- Side: \(Ab\), \(ab\)This results in offspring genotypes: \(AaBb, Aabb, aaBb, aabb\).
05

Identify Deafness-causing Offspring

Recall the allele \(B\) causes deafness. From the Punnett Square, check the genotypes:- \(AaBb\) (deaf due to \(B\)),- \(Aabb\) (not deaf),- \(aaBb\) (deaf due to \(B\)),- \(aabb\) (not deaf as no \(B\) is present).
06

Calculate Percentage of Deaf Offspring

Out of 4 possible genotypes, 2 have the \(B\) allele causing deafness (\(AaBb\) and \(aaBb\)). Thus, 50% of the offspring will be deaf.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Punnett square
When trying to predict the outcome of genetic crosses, a Punnett square is a helpful tool. It's a grid that allows you to visualize and organize all the possible combinations of alleles that offspring can inherit from their parents.
The Punnett square consists of two axes: one representing the possible gametes (sex cells) from one parent, and the other representing the possible gametes from the other parent. Each square within the grid shows a potential genotype for an offspring.
For example, in our exercise, Parent 1 (genotype: \(aaBb\)) can produce gametes \(aB\) and \(ab\). Parent 2 (genotype: \(Aabb\)) can produce gametes \(Ab\) and \(ab\). By filling in the grid, we get different combinations of genotypes: \(AaBb\), \(Aabb\), \(aaBb\), and \(aabb\).
From this final Punnett square, you can easily see and calculate the percentage of certain traits—such as deafness in this case—by identifying which genotypes carry specific alleles, like allele \(B\), responsible for certain characteristics.
alleles
Alleles are different versions of a gene that can exist at a specific spot on a chromosome. Each individual has two alleles for each gene, one inherited from each parent. These alleles can be either dominant or recessive, which affects how traits and characteristics are expressed in an individual.
In the given exercise, we deal with two different traits controlled by alleles at two separate loci: one allele (\(A\)) is dominant and necessary for hearing, while the other allele (\(B\)) is dominant and can cause deafness regardless of the presence of allele \(A\). This explains why offspring with the genotype involving \(B\) (like \(AaBb\) or \(aaBb\)) will be deaf.
Using this understanding of alleles, it's possible to calculate the likelihood of any combination of traits appearing in offspring. The exercise demonstrates the power of specific dominant alleles (like \(B\)) to overrule other genetic factors.
Mendelian inheritance
Mendelian inheritance is the set of primary principles of genetics first described by Gregor Mendel in the 19th century. These principles explain how traits are passed from parents to offspring through generations. The key ideas include the existence of dominant and recessive alleles, how they segregate, and how they independently assort during gamete formation.
In this exercise, we witness Mendel's law of independent assortment in action. Alleles \(A\) and \(a\), and \(B\) and \(b\) are on different chromosomes, so they assort independently of each other. This means the inheritance of one pair of alleles (like \(A\) or \(a\)) doesn't affect the inheritance of another pair (like \(B\) or \(b\)).
The combination of these alleles in the offspring, as calculated by our Punnett square, leads to a variety of genotypes predicting the traits based on Mendel's laws. Understanding these basic principles helps you understand more complex genetic scenarios, such as those that might involve multiple genes contributing to a single trait.

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Most popular questions from this chapter

In Drosophila the recessive allele \(p\), when homozygous, determines pink eyes. \(P p\) or \(P P\) results in wild-type eye color. Another gene on a different chromosome has a recessive allele, \(s w,\) that produces short wings when homozygous. Consider a cross between females of genotype \(P P S w S w\) and males of genotype \(p p\)swsw. Describe the phenotypes and genotypes of the \(\mathrm{F}_{1}\) generation and of the \(\mathrm{F}_{2}\) generation, produced by allowing the \(F_{1}\) progeny to mate with one another.

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The disease Leber's optic neuropathy is caused by a mutation in a gene carried on mitochondrial DNA. What would be the phenotype of their first child if a man with this disease married a woman who did not have the disease? What would be the result if the wife had the disease and the husband did not?

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The genetic sex of a human is determined by a. ploidy, with the male being haploid. b. the Y chromosome. c. \(X\) and \(Y\) chromosomes, the male being \(X X\) d. the number of \(X\) chromosomes, the male being \(X O\) e. \(Z\) and \(W\) chromosomes, the male being \(Z Z\).

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