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Mice of the genotypes \(A / A ; B / B ; C / C ; D / D ; S / S\) and \(a / a ; b / b ; c / c ; d / d ; s / s\) are crossed. The progeny are intercrossed. What phenotypes will be produced in the \(\mathrm{F}_{2}\) and in what proportions? [The allele symbols stand for the following: \(A=\) agouti, \(a=\) solid (nonagouti); \(B=\) black pigment, \(b=\) brown; \(C=\) pigmented, \(c=\) albino; \(D=\) nondilution, \(d=\) dilution (milky color); \(S=\) unspotted \(s=\) pigmented spots on white background.

Short Answer

Expert verified
32 phenotypes, with dominants (A,B,C,D,S) mostly seen in 243/1024 proportion.

Step by step solution

01

Determine Allele Types in F1

The parents are of genotypes \(A/A; B/B; C/C; D/D; S/S\) and \(a/a; b/b; c/c; d/d; s/s\). Crossing these parents results in F1 offspring each with genotype \(A/a; B/b; C/c; D/d; S/s\). The progeny are heterozygous for all traits.
02

Understand F2 Generation Probability for a Single Trait

When F1 heterozygotes (e.g., \(A/a\)) are crossed, each resultant trait in F2 follows a Mendelian ratio of 3:1 (dominant:recessive). This applies separately to each trait: AGOUTI (\(A\)), BLACK (\(B\)), PIGMENTED (\(C\)), NONDILUTION (\(D\)), and UNSPOTTED (\(S\)).
03

Calculate Total Phenotype Possibilities

Multiply phenotype ratios for each individual trait: - Agouti vs. nonagouti is 3:1. - Black vs. brown is 3:1. - Pigmented vs. albino is 3:1. - Nondilution vs. dilution is 3:1. - Unspotted vs. spotted is 3:1.\( ext{Thus, the combined phenotypic ratio is } 3^5 : 1^5. \)
04

Break Down Phenotype Proportions in F2

Calculate the specific ratios:- Agouti, Black, Pigmented, Nondiluted, Unspotted (All Dominant) - \(3^5 = 243\) \(- Any combination with at least one recessive trait has lower occurrence based on the number of recessive traits present.\) Total phenotypes are \(2^5 = 32\), and calculate specific proportions based on \(32\)-component table.
05

List Expected Phenotypes with Proportions

Given the crossing of alleles, you'll have 32 unique phenotypes with varying proportions: 1. All dominant (respective fractions): agouti/black/pigmented/nondilution/unspotted.2. Combinations of dominants and recessives (e.g., agouti/brown, solid/albino...) each aspect corresponds to its trait's 3:1, the culmination follows a binomial expansion of \((3+1)^5 = 1024\). Simplifying, dominance phenotype is around \(243/1024\), showing frequent occurrences.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Genotype Ratios
In Mendelian inheritance, understanding genotype ratios forms the foundation for predicting the outcomes of genetic crosses. When we cross parent organisms with different pairs of alleles, such as in the exercise where the genotypes are \(A/A\), \(B/B\), \(C/C\), \(D/D\), \(S/S\), and \(a/a\), \(b/b\), \(c/c\), \(d/d\), \(s/s\), their offspring will receive one allele from each parent for every gene.

This results in the first filial generation, referred to as \(F_1\), with heterozygous genotypes like \(A/a; B/b; C/c; D/d; S/s\). When these \(F_1\) progenies intercross, they form the \(F_2\) generation. Each trait now follows the Mendelian principle of inheritance for a genotype ratio of 3:1 for dominant to recessive traits.
  • Agouti with nonagouti (3:1 ratio)
  • Black with brown (3:1 ratio)
  • Pigmented with albino (3:1 ratio)
  • Nondilution with dilution (3:1 ratio)
  • Unspotted with spotted (3:1 ratio)
Combining these for all five independent traits, creating a 243:81 ratio for five dominant trait combinations in \(F_2\). This is because each trait independently follows the inheritance rule, leading to an overall genotype ratio.
Phenotype Proportions
Moving from genotype ratios to phenotype proportions involves understanding how these genetic combinations manifest as observable characteristics. In the \(F_2\) generation, each gene independently adheres to a phenotypic ratio of 3:1 between dominant and recessive traits. This results in various combinations of phenotypic expressions.

For any single gene pair reduced in detail, as observed in the Mendelian cross, the dominant trait appears in 75% of the offspring, while the recessive trait appears in 25%. Because five traits segregate independently, you multiply the individual phenotypic ratios:
  • Agouti/nonagouti (3:1)
  • Black/brown (3:1)
  • Pigmented/albino (3:1)
  • Nondilution/dilution (3:1)
  • Unspotted/spotted (3:1)

When these ratios multiply for each trait, the predicted number of dominant phenotype traits being all present is \(3^5 = 243\) outcomes while recessive combinations appear less due to having one or more recessive traits. Calculating all 32 possible phenotypic combinations gives a comprehensive understanding of proportions.
Dominant and Recessive Traits
Dominant and recessive traits define how genes express themselves in offspring, an essential concept in Mendelian genetics. A dominant trait, such as agouti, black, pigmented, nondilution, and unspotted, will appear in the offspring if at least one dominant allele is present.

Conversely, a recessive trait, such as solid, brown, albino, dilution, and spotted, will only manifest if both alleles are recessive in the genotype. This means that while dominant traits are expressed when an organism has one or two copies of the allele, recessive traits require both alleles to be recessive.
  • Dominant alleles mask the effects of recessive alleles.
  • Recessive traits require homozygosity to be expressed.
  • For example, if a mouse inherits 'agouti', the dominant trait is visible, whereas 'solid', the recessive trait, will only be seen if both alleles are 'a'.
Understanding how these traits interact gives a deeper insight into predicting phenotype expressions from a given genotype, allowing predictions like those in the given exercise involving multiple traits to be accurately forecasted based on the global 3:1 mechanism.

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Most popular questions from this chapter

After irradiating wild-type cells of Neurospora (a haploid fungus), a geneticist finds two leucine-requiring auxotrophic mutants. He combines the two mutants in a heterokaryon and discovers that the heterokaryon is prototrophic. a. Were the mutations in the two auxotrophs in the same gene in the pathway for synthesizing leucine or in two different genes in that pathway? Explain. b. Write the genotype of the two strains according to your model. c. What progeny and in what proportions would you predict from crossing the two auxotrophic mutants? (Assume independent assortment.)

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If a man of blood-group AB marries a woman of bloodgroup A whose father was of blood-group \(\mathrm{O}\), to what different blood groups can this man and woman expect their children to belong?

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