/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 40 Consider the production of flowe... [FREE SOLUTION] | 91Ó°ÊÓ

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Consider the production of flower color in the Japanese morning glory (Pharbitis nil). Dominant alleles of either of two separate genes \((A /-\cdot b / b \text { or } a / a \cdot B /-)\) produce purple petals. \(A /-\cdot B /-\) produces blue petals, and \(a / a \cdot b / b\) produces scarlet petals. Deduce the genotypes of parents and progeny in the following crosses: $$\begin{array}{cll} \text { Cross } & \text { Parents } & \text { Progeny } \\ \hline 1 & \text { blue } \times \text { scarlet } & \frac{1}{4} \text { blue }: \frac{1}{2} \text { purple : } \frac{1}{4} \text { scarlet } \\ 2 & \text { purple } \times \text { purple } & \frac{1}{4} \text { blue }: \frac{1}{2} \text { purple }: \frac{1}{4} \text { scarlet } \\ 3 & \text { blue } \times \text { blue } & \frac{3}{4} \text { blue }: \frac{1}{4} \text { purple } \\ 4 & \text { blue } \times \text { purple } & \frac{3}{8} \text { blue }: \frac{4}{8} \text { purple }: \frac{1}{8} \text { scarlet } \\ 5 & \text { purple } \times \text { scarlet } & \frac{1}{2} \text { purple }: \frac{1}{2} \text { scarlet } \\ \hline \end{array}$$

Short Answer

Expert verified
Cross 1: Aa/Bb x aa/bb, Cross 2: Aa/bb x aa/Bb, Cross 3: Aa/Bb x Aa/Bb, Cross 4: Aa/Bb x Aa/bb or aa/Bb, Cross 5: Aa/bb x aa/bb or aa/Bb x aa/bb.

Step by step solution

01

Understanding Gene Expression

The phenotypic expression of flower color is determined by combinations of two distinct genes. A dominant allele in either one of the two gene pairs (A or B) results in purple petals unless both are dominant, which results in blue petals. A recessive combination in both gene pairs results in scarlet petals.
02

Analyzing Cross 1

The cross is blue (A-/B-) x scarlet (aa/bb). The blue parent's genotype must be heterozygous at both loci to produce the 1/4 blue, 1/2 purple, and 1/4 scarlet progenies. Thus, the genotype is Aa/Bb for blue and aa/bb for scarlet.
03

Analyzing Cross 2

The cross is purple x purple producing 1/4 blue, 1/2 purple, and 1/4 scarlet offspring. Thus, each parent must be heterozygous for one gene and homozygous recessive for the other: Aa/bb x aa/Bb.
04

Analyzing Cross 3

The cross is blue (A-/B-) x blue (A-/B-) resulting in 3/4 blue and 1/4 purple offspring. This indicates both parents are heterozygous Aa/Bb to allow for a small number of purple individuals due to the combination Aa/BB or AA/Bb.
05

Analyzing Cross 4

The cross is blue x purple, producing 3/8 blue, 1/2 purple, and 1/8 scarlet progenies. This indicates one parent (blue) is Aa/Bb and the purple parent is either Aa/bb or aa/Bb.
06

Analyzing Cross 5

The cross is purple x scarlet producing 1/2 purple, 1/2 scarlet. This is consistent with a heterozygous purple parent (Aa/bb or aa/Bb) crossed with a homozygous scarlet parent (aa/bb).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Dominant Alleles
In Mendelian genetics, **dominant alleles** play a crucial role in determining traits, such as flower color. Each gene can exist in different forms known as alleles. When you have two different alleles for a specific gene, the dominant allele is the one that will be expressed in the phenotype. For instance, in the Japanese morning glory, a flower with either the dominant allele for gene A or gene B will have purple petals. This means if one carries even one copy of the dominant allele, it will mask the expression of any recessive alleles and result in the dominant phenotype.

Dominant alleles ensure that certain traits appear even if only one of the two alleles in a gene pair is dominant. Imagine you are mixing paint; the dominant color, like bright purple, will overshadow lighter or more muted colors, just like a dominant allele overshadows recessive counterparts.
Phenotypic Expression
The **phenotypic expression** of a trait is the visible or measurable manifestation of a genetic characteristic. In the context of flower color in Japanese morning glories, phenotypic expression comes in different hues such as blue, purple, or scarlet. Each color corresponds to a specific genetic combination.

Phenotypes are influenced by the genotypes that produce them. However, some alleles, specifically dominant ones, have a greater influence on what we see. For example, both blue and purple flowers result from the presence of dominant alleles, but blue petals only emerge when both the dominant alleles A and B are present. On the other hand, if neither the genes express a dominant allele, we see a recessive phenotype, such as scarlet.
Genotypes
The **genotype** is the genetic makeup of an organism, comprising all the various alleles it carries. Think of genotype as the genetic instructions that dictate the possible outcomes of a trait. In the case of flower color, for example, we look at combinations like Aa/Bb or aa/bb to determine the visible color of the petals.

Understanding genotypes is crucial when predicting the outcomes of crosses between parents. Each parent can pass down different versions of their genes based on their genotype. For Japanese morning glories, knowing whether the genotype is homozygous (same alleles) or heterozygous (different alleles) can help determine whether their offspring will have blue, purple, or scarlet petals.
Flower Color Inheritance
Inheritance of **flower color** in Japanese morning glories follows Mendelian principles. This concept involves understanding how alleles are passed from parent to offspring and how they interact to produce observable traits.

In flowers, color is determined by the combination of alleles from two parents. A typical example is the cross between blue and scarlet flowers. Each of these colors results from specific genotypic combinations of alleles A and B. During reproduction, these alleles segregate independently according to Mendel's first law of inheritance. This segregation results in a variety of color outcomes in the offspring, ranging from blue to purple to scarlet.

The fascinating thing about flower color inheritance is how complex and yet predictable it can be, with punnett squares often used to forecast potential genetic outcomes based on parental genotypes. With careful analysis, we can deduce parental genotypes just from observing the resulting flower colors in their progeny.

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Most popular questions from this chapter

In Drosophila, an autosomal gene determines the shape of the hair, with \(B\) giving straight and \(b\) giving bent hairs. On another autosome, there is a gene of which a dominant allele \(I\) inhibits hair formation so that the fly is hairless ( \(i\) has no known phenotypic effect). a. If a straight-haired fly from a pure line is crossed with a fly from a pure-breeding hairless line known to be an inhibited bent genotype, what will the genotypes and phenotypes of the \(\mathrm{F}_{1}\) and the \(\mathrm{F}_{2}\) be? b. What cross would give the ratio 4 hairless: 3 straight: 1 bent?

A woman who owned a purebred albino poodle (an autosomal recessive phenotype) wanted white puppies; so she took the dog to a breeder, who said he would mate the female with an albino stud male, also from a pure stock. When six puppies were born, all of them were black; so the woman sued the breeder, claiming that he replaced the stud male with a black dog, giving her six unwanted puppies. You are called in as an expert witness, and the defense asks you if it is possible to produce black offspring from two pure-breeding recessive albino parents. What testimony do you give?

Many kinds of wild animals have the agouti coloring pattern, in which each hair has a yellow band around it. a. Black mice and other black animals do not have the yellow band; each of their hairs is all black. This absence of wild agouti pattern is called nonagouti. When mice of a true-breeding agouti line are crossed with nonagoutis, the \(F_{1}\) is all agouti and the \(F_{2}\) has a 3: 1 ratio of agoutis to nonagoutis. Diagram this cross, letting \(A\) represent the allele responsible for the agouti phenotype and \(a\) nonagouti. Show the phenotypes and genotypes of the parents, their gametes, the \(F_{1}\), their gametes, and the \(F_{2}\) b. Another inherited color deviation in mice substitutes brown for the black color in the wild-type hair. Such brown-agouti mice are called cinnamons. When wildtype mice are crossed with cinnamons, all of the \(\mathrm{F}_{1}\) are wild type and the \(\mathrm{F}_{2}\) has a 3: 1 ratio of wild type to cinnamon. Diagram this cross as in part \(a\), letting \(B\) stand for the wild-type black allele and \(b\) stand for the cinnamon brown allele. c. When mice of a true-breeding cinnamon line are crossed with mice of a true- breeding nonagouti (black) line, all of the \(F_{1}\) are wild type. Use a genetic diagram to explain this result. d. In the \(F_{2}\) of the cross in part \(c,\) a fourth color called chocolate appears in addition to the parental cinnamon and nonagouti and the wild type of the \(\mathrm{F}_{1}\). Chocolate mice have a solid, rich brown color. What is the genetic constitution of the chocolates? e. Assuming that the \(A / a\) and \(B / b\) allelic pairs assort independently of each other, what do you expect to be the relative frequencies of the four color types in the \(\mathrm{F}_{2}\) described in part \(d ?\) Diagram the cross of parts \(c\) and \(d\) showing phenotypes and genotypes (including gametes). f. What phenotypes would be observed in what proportions in the progeny of a backcross of \(\mathrm{F}_{1}\) mice from part \(c\) with the cinnamon parental stock? With the nonagouti (black) parental stock? Diagram these backcrosses. g. Diagram a testcross for the \(\mathrm{F}_{1}\) of part \(c .\) What colors would result and in what proportions? h. Albino (pink-eyed white) mice are homozygous for the recessive member of an allelic pair \(C / c,\) which assorts independently of the \(A / a\) and \(B / b\) pairs. Suppose that you have four different highly inbred (and therefore presumably homozygous) albino lines. You cross each of these lines with a true-breeding wild-type line, and you raise a large \(\mathrm{F}_{2}\) progeny from each cross. What genotypes for the albino lines can you deduce from the following \(\mathrm{F}_{2}\) phenotypes? $$\begin{array}{cccccc} & {4}{c} {\text {Phenotypes of progeny}} \\ { 2 - 5 } \mathrm{F}_{2} \text { of } \text { line } & \begin{array}{c} \text { Wild } \\ \text { type } \end{array} & \text { Black } & \begin{array}{c} \text { Cinna- } \\ \text { mon } \end{array} & \begin{array}{c} \text { Choco- } \\ \text { late } \end{array} & \text { Albino } \\ \hline 1 & 87 & 0 & 32 & 0 & 39 \\ 2 & 62 & 0 & 0 & 0 & 18 \\ 3 & 96 & 30 & 0 & 0 & 41 \\ 4 & 287 & 86 & 92 & 29 & 164 \\ \hline \end{array}$$ (Adapted from A. M. Srb, R. D. Owen, and R. S. Edgar General Genetics, 2nd ed. W. H. Freeman and Company, 1965.)

In corn, three dominant alleles, called \(A, C,\) and \(R\) must be present to produce colored seeds. Genotype \(A /-; C /-; R /-\) is colored; all others are colorless. A colored plant is crossed with three tester plants of known genotype. With tester \(a / a ; c / c ; R / R,\) the colored plant produces 50 percent colored seeds; with \(a / a\) \(\mathrm{C} / \mathrm{C} ; \mathrm{r} / \mathrm{r},\) it produces 25 percent colored; and with \(A / A ; c / c ; r / r,\) it produces 50 percent colored. What is the genotype of the colored plant?

The frizzle fowl is much admired by poultry fanciers. It gets its name from the unusual way that its feathers curl up, giving the impression that it has been (in the memorable words of animal geneticist \(\mathrm{F}\) B. Hutt) "pulled backwards through a knothole." Unfortunately, frizzle fowl do not breed true: when two frizzles are intercrossed, they always produce 50 percent frizzles, 25 percent normal, and 25 percent with peculiar woolly feathers that soon fall out, leaving the birds naked. a. Give a genetic explanation for these results, showing genotypes of all phenotypes, and provide a statement of how your explanation works. b. If you wanted to mass-produce frizzle fowl for sale, which types would be best to use as a breeding pair?

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