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In a haploid fungus, the genes \(a l-2\) and \(a r g-6\) ar apart on chromosome \(1,\) and the genes \(l y s-5\) \(a l-2+;+m e t-1 \times+\arg -6 ; l y s-5+\) what proportion of progeny would be prototrophic \(++\) \(++?\)

Short Answer

Expert verified
The proportion of progeny that are prototrophic \(++++\) is approximately \(\frac{1}{16}\).

Step by step solution

01

Understand Genetic Cross

We are dealing with a cross in a haploid fungus involving genes on chromosome 1. The parental genotypes are \(al-2^+; +; met-1\) and \(+; arg-6; lys-5^+\). The question asks for the proportion of progeny that are prototrophic \(++++\). This means offspring that are wild type for all genes: \(al-2^+, arg-6^+, met-1^+, lys-5^+\).
02

Identify Possible Recombinants

In order to obtain prototrophic \(++++\) progeny, recombination events must occur between alleles in the parents. The possibilities are \(al-2^+/arg-6^+\) and \(met-1^+/lys-5^+\). To be prototrophic, offspring must receive wild-type alleles from each chromosome pair.
03

Determine Proportion of Progeny

If there are no recombination events (assuming independent assortment and random segregation), the proportion of any specific combination can be estimated by multiplying the probabilities of each needed recombination. If recombination frequencies within the pairs are given or assumed (e.g., 50% for unlinked genes), we calculate accordingly. For simplicity here, we'll estimate it assuming independent assortment.
04

Apply Genetic Principles

Assuming the simplest model where genes assort independently, and you want the outcome \(++++\), calculate the proportion. With independent assortment, any single gamete combination occurs at frequency \(\frac{1}{2} \times \frac{1}{2} = \frac{1}{4}\) for each parental set, and thus \(\left(\frac{1}{4}\right)^2 = \frac{1}{16}\) for each combined genotype.
05

Conclusion

Hence, the proportion of progeny that are \(++++\) prototrophic is \(\frac{1}{16}\) in this simple independent assortment scenario. Adjustments would be made if linkage data or recombination frequencies were precisely known.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

haploid fungus
Haploid fungi are organisms with a single set of chromosomes, meaning they have only one allele for each gene. Unlike diploid organisms, which contain two sets of chromosomes (one from each parent), haploid fungi are simpler to study for genetic experiments. Their single set of chromosomes means any genetic change is directly visible in the phenotype.
Genetic studies in haploid fungi, such as experiments involving genetic crosses, help scientists understand basic principles of inheritance. Because there is no second allele to mask mutations, any change, be it beneficial or deleterious, manifests clearly.
Research using haploid fungi can reveal interesting aspects of genetics, such as how mutations affect function and the way genetic interactions may lead to specific traits. This simplified genetic background is invaluable for observing direct results of genetic recombination and mutation.
independent assortment
Independent assortment is a fundamental principle of classical genetics that describes how genes independently separate from one another when reproductive cells develop. This concept was first formulated by Gregor Mendel in his law of independent assortment, which states that alleles of different genes are distributed independently of one another.
When dealing with genetic crosses, such as those in a haploid fungus, independent assortment allows us to predict the distribution of alleles in the progeny. Each mixture of genes can be calculated as a product of various separate probabilities.
For example, if you consider two parental haploid cells each containing different alleles for specific genes, the alleles sort into gametes independently. This results in combinations that mirror diversity seen in the progeny. The math behind independent assortment in genetics confirms that each combination is equally likely, explaining the genetic variation seen in sexually reproducing populations.
recombination frequencies
Recombination frequencies refer to the likelihood of crossover events occurring between different loci on homologous chromosomes during meiosis. This process is crucial for creating variation within a species, as it results in new combinations of genes. The frequency of recombination between any two genes provides insights into their physical distance on a chromosome. If no recombination occurs, the genes are closely linked. In the context of haploid fungi, recombination allows for the generation of new genotype combinations, as different sections of chromosomes exchange segments. Calculating recombination frequencies can help in mapping genes onto chromosomes, giving scientists a 'genetic map', which aids in understanding the genetic architecture of organisms. In practice, recombination frequencies are estimated by observing genetic outcomes in the progeny of various crosses, contributing crucial insights into genetic linkage and evolution.
prototrophic progeny
Prototrophic progeny are offspring that have retained the ability to synthesize all compounds needed for growth. This term is often encountered when discussing genetic crosses, especially in contexts where one wishes to identify individuals who inherit a 'wild-type' or ancestral set of functional genes. In genetic experiments, especially those involving microorganisms like haploid fungi, creating prototrophic individuals is a key aim. The original exercise involved determining the fraction of progeny that contained wild-type alleles across several genes. Prototrophy is a marker of genetic health and vitality, providing a benchmark for genetic recombination success. Identifying prototrophic progeny enables scientists to learn more about the inheritance patterns of certain genes. It also serves as a foundation for understanding genetic resilience and adaptability, important traits for survival in varying environmental conditions.

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Most popular questions from this chapter

In the model plant Arabidopsis thaliana, the following alleles were used in a cross: \(\begin{array}{ll}T=\text { presence of trichomes } & t=\text { absence of trichomes } \\ D=\text { tall plants } & d=\text { dwarf plants } \\ W=\text { waxy cuticle } & w=\text { nonwaxy } \\ A=\text { presence of purple } & a=\text { absence (white) } \\ & \text { anthocyanin pigment }\end{array}\) The \(T / t\) and \(D / d\) loci are linked 26 m.u. apart on chromosome 1 , whereas the \(W / w\) and \(A / a\) loci are linked 8 m.u. apart on chromosome 2 A pure-breeding double-homozygous recessive trichomeless nonwaxy plant is crossed with another pure-breeding double-homozygous recessive dwarf white plant. a. What will be the appearance of the \(\mathrm{F}_{1}\) ? b. Sketch the chromosomes 1 and 2 of the parents and the \(F_{1},\) showing the arrangement of the alleles. c. If the \(\mathrm{F}_{1}\) is testcrossed, what proportion of the progeny will have all four recessive phenotypes?

A strain of Neurospora with the genotype \(H \cdot I\) is crossed with a strain with the genotype \(h \cdot i\). Half the progeny are \(H \cdot I,\) and the other half are \(h \cdot i .\) Explain how this outcome is possible.

A corn geneticist wants to obtain a corn plant that has the three dominant phenotypes: anthocyanin (A), long tassels \((\mathrm{L}),\) and dwarf plant \((\mathrm{D}) .\) In her collection of pure lines, the only lines that bear these alleles are \(A A\) \(L L d d\) and aa \(l l D D .\) She also has the fully recessive line aa ll dd. She decides to intercross the first two and testcross the resulting hybrid to obtain in the progeny a plant of the desired phenotype (which would have to be Aa Ll \(D d\) in this case). She knows that the three genes are linked in the order written, that the distance between the \(A / a\) and the \(L / l\) loci is \(16 \mathrm{m} . \mathrm{u} .,\) and that the distance between the \(L / l\) and the \(D / d\) loci is \(24 \mathrm{m}\).u. a. Draw a diagram of the chromosomes of the parents, the hybrid, and the tester. b. Draw a diagram of the crossover(s) necessary to produce the desired genotype. c. What percentage of the testcross progeny will be of the phenotype that she needs? d. What assumptions did you make (if any)?

The five sets of data given in the following table represent the results of testcrosses using parents with the same alleles but in different combinations. Determine the order of genes by inspection-that is, without calculating recombination values. Recessive phenotypes are symbolized by lowercase letters and dominant phenotypes by pluses.

For a certain chromosomal region, the mean number of crossovers at meiosis is calculated to be two per meiosis. In that region, what proportion of meioses are predicted to have (a) no crossovers? (b) one crossover? (c) two crossovers?

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