/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 36 Allele \(B\) is a deleterious au... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Allele \(B\) is a deleterious autosomal dominant. The frequency of affected individuals is \(4.0 \times 10^{-6}\). The reproductive capacity of these individuals is about 30 percent that of normal individuals. Estimate \(\mu\), the rate at which \(b\) mutates to its deleterious allele \(B\). Assume that the frequencies of the alleles are at their equilibrium values.

Short Answer

Expert verified
The mutation rate \( \mu \) is approximately \( 2.8 \times 10^{-6} \).

Step by step solution

01

Understanding the Problem

The problem asks us to estimate the mutation rate, \( \mu \), at which allele \( b \) mutates to its deleterious form \( B \). It provides that \( B \) is an autosomal dominant allele and that the frequency of affected individuals is \( 4.0 \times 10^{-6} \). Affected individuals have a reproductive capacity at 30% of normal individuals. We assume the population is at genetic equilibrium.
02

Applying Mutation-Selection Balance

In a mutation-selection balance for a dominant deleterious allele, the mutation rate \( \mu \) can be approximated using the equation: \[ \mu = s \times q \], where \( s \) is the selection coefficient against the allele and \( q \) is the frequency of the allele in the population, which equals the frequency of affected individuals (since the trait is dominant).
03

Determine the Selection Coefficient

The selection coefficient \( s \) can be calculated as \( s = 1 - w \), where \( w \) is the relative fitness of the affected individuals. Given that affected individuals have 30% of the normal reproductive capacity, \( w = 0.3 \). Thus, \( s = 1 - 0.3 = 0.7 \).
04

Calculate the Mutation Rate \( \mu \)

Substitute the values into the mutation-selection balance equation: \[ \mu = 0.7 \times 4.0 \times 10^{-6} \]. Calculate \( \mu \): \[ \mu = 2.8 \times 10^{-6} \].
05

Conclusion

The mutation rate at which allele \( b \) mutates to its deleterious allele \( B \) is approximately \( 2.8 \times 10^{-6} \).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Autosomal Dominant
An autosomal dominant allele is one where just a single copy of the allele in the genotype causes the individual to express a particular trait. This is in contrast to autosomal recessive traits that require both alleles to be of the mutant type to be expressed. With autosomal dominance, even if an individual has one healthy allele, the dominant trait will still manifest. This can result in the trait appearing in every generation of a family, since it only takes one affected allele to pass on the condition.
Where you see this happening is often in traits or diseases that do not skip generations and can be found equally in men and women, because these alleles are located on non-sex chromosomes (autosomes). Examples include conditions like Huntington's disease and Marfan syndrome. Remember, autosomal dominant alleles have a 50% chance of being passed on to the next generation each time an affected individual has offspring.
Selection Coefficient
The selection coefficient, often denoted as \( s \), is a measure of the relative disadvantage of having a certain genotype compared to another. It quantifies how much less likely individuals with a certain allele are to pass their genes to the next generation compared to those without it.
For instance, if the normal reproductive fitness of the population is represented as 1, and the fitness of individuals with a deleterious allele is 0.3, then the selection coefficient is calculated as \( s = 1 - 0.3 = 0.7 \). This means these individuals are significantly disadvantaged; they have a 70% reduction in fitness. The selection coefficient plays a crucial role in determining whether harmful genes are maintained in a population through mutation-selection balance, as selection works against deleterious alleles, attempting to reduce their frequency.
Mutation-Selection Balance
Mutation-selection balance is a concept explaining how deleterious alleles can persist in a population. Mutations introduce new alleles, while selection removes deleterious ones. Equilibrium is reached when these opposing forces balance each other out, maintaining a stable frequency of the detrimental allele in the population.
The equation \( \mu = s \times q \) helps estimate this balance. Here, \( \mu \) is the mutation rate, \( s \) is the selection coefficient against the allele, and \( q \) is the frequency of the allele. In populations at mutation-selection balance, deleterious alleles are continually reintroduced by mutation and constantly being removed by selection, maintaining a constant allele frequency despite the negative selective pressure against them.
Genetic Equilibrium
Genetic equilibrium refers to a state in a population where allele frequencies remain constant from generation to generation, unless one or more evolutionary influences (e.g., mutation, natural selection, genetic drift, or gene flow) act upon the population. This concept relies on the principle that allele frequencies in a large, random-mating population will remain constant in the absence of evolutionary pressures.
In exercises like this, assuming genetic equilibrium implies that the forces of mutation and selection have reached a balance, and the allele frequencies are not changing over time. In real-world populations, complete equilibrium is rare due to the ongoing influence of various evolutionary processes. However, understanding genetic equilibrium is crucial for predicting how allele frequencies might change under different evolutionary pressures.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Cystic fibrosis (CF) is an autosomal recessive disorder that occurs relatively frequently among people of European descent. In an Amish community in Ohio, medical researchers reported the occurrence of cystic fibrosis (CF) as being \(1 / 569\) live births. Using the Hardy-Weinberg rule, estimate the frequency of carriers of the disease allele in this Amish population.

In a population of a beetle species, you notice that there is a 3: 1 ratio of shiny to dull wing covers. Does this ratio prove that the shiny allele is dominant? (Assume that the two states are caused by two alleles of one gene.) If not, what does it prove? How would you elucidate the situation?

If we define the total selection cost to a population of deleterious recessive genes as the loss of fitness per individual affected (s) multiplied by the frequency of affected individuals \(\left(q^{2}\right),\) then selection cost \(=s q^{2}\) a. Suppose that a population is at equilibrium between mutation and selection for a deleterious recessive allele, where \(s=0.5\) and \(\mu=10^{-5} .\) What is the equilibrium frequency of the allele? What is the selection cost? b. Suppose that we start irradiating individual members of the population so that the mutation rate doubles. What is the new equilibrium frequency of the allele? What is the new selection cost? c. If we do not change the mutation rate but we lower the selection coefficient to 0.3 instead, what happens to the equilibrium frequency and the selection cost?

In a randomly mating laboratory population of Drosophila, 4 percent of the flies have black bodies (encoded by the autosomal recessive \(b\) ), and 96 percent have brown bodies (the wild type, encoded by \(B\) ). If this population is assumed to be in Hardy-Weinberg equilibri\(\mathrm{um},\) what are the allele frequencies of \(B\) and \(b\) and the genotypic frequencies of \(B / B\) and \(B / b ?\)

Red-green color blindness is an X-linked recessive disorder in humans caused by mutations in one of the genes that encodes the light-sensitive protein, opsin. If the mutant allele has a frequency of 0.08 in the population, what proportion of females will be carriers? Assume that the population is 50: 50 male: female.

See all solutions

Recommended explanations on Biology Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.