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Chapter 9: Problem 6

Draw the structure of a phosphodiester linkage.

Short Answer

Expert verified
The structure of a phosphodiester linkage includes a phosphate group in the middle, with two ester bonds on either side attaching it to adjacent nucleotides.

Step by step solution

01

Understand the components of a phosphodiester linkage

To draw the phosphodiester linkage, first understand that it consists of a phosphate group and two ester bonds. The phosphate group is the element in the middle and the two ester bonds are on each side, attaching the phosphate group to adjacent nucleotides - one to its 5' carbon atom and the other to the 3' carbon atom of the next.
02

Draw the phosphate group

Begin by drawing the phosphate group (PO4) in the center. This consists of a phosphorus (P) atom in the center, surrounded by 4 oxygen (O) atoms. Mark them appropriately.
03

Draw the ester bonds

On either side of the phosphate, draw the ester bonds. These are formed between the oxygen on the phosphate group and the carbon atoms of the nucleotides. Draw two lines coming out of two of the oxygens on your phosphate, showing their link to the rest of the molecule.
04

Indicate the 5' and 3' ends

Lastly, denote the 5' and 3' ends. The ester bond linked to the 5' carbon atom (-OH) comes from one oxygen on the phosphate group. The other ester bond to the 3' carbon atom (-OH) of the next nucleotide comes from another.
05

Check the structure

Now, make sure that your sketch contains every important part and accurately portrays a phosphodiester linkage. The phosphate group in the middle. Two ester bonds on either side attaching to the rest of the molecule (the adjacent nucleotides). Determination of the 5' and 3' ends by which part of the phosphate they are attached to.

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