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Tay-Sachs disease is an autosomal recessive disorder. Among Ashkenazi Jews, the frequency of Tay-Sachs disease is 1 in \(3600 .\) If the Ashkenazi population is mating randomly with respect to the Tay-Sachs gene, what proportion of the population consists of heterozygous carriers of the Tay- Sachs allele?

Short Answer

Expert verified
About 0.033 or 3.3% of the population are carriers of the Tay-Sachs allele.

Step by step solution

01

Define the Terms

Tay-Sachs disease is autosomal recessive, meaning a person must inherit two copies of the mutant allele to express the disease. Let "p" be the frequency of the normal allele and "q" be the frequency of the Tay-Sachs allele. The frequency of the disease can then be represented by the equation \( q^2 = \frac{1}{3600} \).
02

Calculate q

We have \( q^2 = \frac{1}{3600} \). Taking the square root of both sides to solve for "q," we get \( q = \sqrt{\frac{1}{3600}} \). Calculate \( q \) to find its approximate value.
03

Calculate p

Since \( p + q = 1 \), we can find \( p \) by rearranging the equation to \( p = 1 - q \). Substitute the value of \( q \) found in Step 2 to calculate \( p \).
04

Calculate Carrier Frequency

The frequency of heterozygous carriers is given by the equation \( 2pq \). Use the values of "p" and "q" from Steps 2 and 3 to determine the proportion of the population that is heterozygous for the Tay-Sachs allele.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Autosomal Recessive Disorders
Tay-Sachs disease is a prime example of an autosomal recessive disorder. In such conditions, a person needs to inherit two copies of the mutant allele, one from each parent, to actually develop the disease. This means that each parent must at least carry one copy of the mutant gene. Autosomal recessive implies that the gene causing the trait or disorder is located on one of the autosomes. Autosomes are the first 22 pairs of chromosomes that do not determine an individual's sex. The term recessive means that both copies of the gene in each cell must have mutations for a person to exhibit symptoms. Therefore, someone with just one mutant copy—carrying it alongside a normal copy—is often asymptomatic but can still pass the gene to their offspring.
Gene Frequency Calculation
Determining the frequency of a gene in a population is a critical step in understanding genetic disorders. For Tay-Sachs, the Hardy-Weinberg principle is used, which mathematically defines how alleles distribute themselves in a population. To find the frequency of the Tay-Sachs allele, denoted as "q," we use the equation \( q^2 = \frac{1}{3600} \), since the disease frequency among Ashkenazi Jews is 1 in 3600. Solving this by taking the square root helps us identify \( q \),the frequency of the Tay-Sachs allele. Once we have \( q \), calculating the frequency of the normal allele,\( p \),becomes easy: simply use \( p + q = 1 \) leading to \( p = 1 - q \). With these calculations, steps towards understanding the genetic makeup of the population become clearer.
Heterozygous Carriers
An individual is a heterozygous carrier if they possess one copy of the normal allele and one copy of the mutant allele related to a recessive disorder. They do not have the disease symptoms but can pass the disease allele to the next generation. In the context of Tay-Sachs, the frequency of such carriers in a population is given by the equation \( 2pq \). This formula is derived from the principles of genetic equilibrium, where \( p \)is the frequency of the normal allele and \( q \)is the frequency of the mutant allele. When both are multiplied by 2, it calculates all possible combinations of individuals who are carriers. Being a heterozygous carrier is crucial because it keeps the mutant allele in the population, creating potential for disease in future generations if two carriers mate.
Ashkenazi Jewish Population
The Ashkenazi Jewish population is notably significant in genetic studies due to their historical background and genetic drift factors, which have led to a higher prevalence of certain genetic disorders, including Tay-Sachs. This group, originally from Eastern Europe, has remained relatively isolated, which, combined with historical events, has allowed certain genetic traits to proliferate. Researchers focus on this population to better understand the dynamics of genetic disorders and how allele frequencies might differ compared to broader populations. The specific risks faced by Ashkenazi Jews have led to the development of targeted screening programs designed to identify carriers of various recessive genetic disorders before they have children, potentially reducing the incidence of such disorders.
Genetic Disorders
Genetic disorders like Tay-Sachs result from anomalies in genes or chromosomes, usually inherited from one or both parents. They range from causing mild symptoms to being life-threatening. Depending on how the genetic material is inherited, disorders can be classified as autosomal dominant, recessive, or linked to sex chromosomes.
  • Autosomal Recessive: Requires two copies of a mutant gene to express the disorder (e.g., Tay-Sachs).
  • Autosomal Dominant: Just one copy of a mutant gene is sufficient to cause the disorder.
  • Sex-Linked: Disorder arises from mutations on the sex chromosomes, commonly the X chromosome.
Understanding these classifications helps in predicting inheritance patterns, planning family genetics counseling, and developing possible interventions. While environmental factors and lifestyle can influence the expression of genetic disorders, their core cause is rooted in one's genetic makeup. Advanced genetic testing continues to evolve, aiding in early detection and potentially mitigating the impacts of such disorders.

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Most popular questions from this chapter

Color blindness in humans is an X-linked recessive trait. Approximately \(10 \%\) of the men in a particular population are color blind. a. If mating is random with respect to the color-blindness locus, what is the frequency of the color-blindness allele in this population? b. What proportion of the women in this population are expected to be color blind? c. What proportion of the women in this population are expected to be heterozygous carriers of the color-blindness allele?

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