/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 41 Predict the genotypic and phenot... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Predict the genotypic and phenotypic results from each of the following crosses in garden peas: (a) a tall (homozygous dominant) plant crossed with a dwarf plant; (b) the progeny of (a) when self-pollinated; (c) the progeny of (a) crossed with a homozygous tall plant; (d) the progeny of (a) crossed with a dwarf plant.

Short Answer

Expert verified
(a) Genotypes: 100% Tt; Phenotypes: 100% Tall. (b) Genotypes: 25% TT, 50% Tt, 25% tt; Phenotypes: 75% Tall, 25% Dwarf. (c) Genotypes: 50% TT, 50% Tt; Phenotypes: 100% Tall. (d) Genotypes: 50% Tt, 50% tt; Phenotypes: 50% Tall, 50% Dwarf.

Step by step solution

01

Cross (a) - Tall homozygous dominant x Dwarf

In this cross, we have a tall homozygous dominant plant (TT) and a dwarf plant (tt). The Punnett square for this cross will look like this: T T .------------- t | Tt | Tt | .------------- t | Tt | Tt | .------------- The genotypic and phenotypic results will be as follows: Genotypes: 100% Tt (heterozygous tall) Phenotypes: 100% Tall
02

Cross (b) - Progeny of (a) when self-pollinated

Now, let's self-pollinate the progeny from cross (a), which are all heterozygous tall plants (Tt). We will do a Punnett square to determine the genotypes and phenotypes. T t .------------- T | TT | Tt | .------------- t | Tt | tt | .------------- The genotypic and phenotypic results will be as follows: Genotypes: 25% TT (homozygous tall) 50% Tt (heterozygous tall) 25% tt (homozygous dwarf) Phenotypes: 75% Tall 25% Dwarf
03

Cross (c) - Progeny of (a) crossed with a homozygous tall plant

In this cross, we are crossing the progeny from (a) (Tt) with a homozygous tall plant (TT). We will do a Punnett square to determine the genotypes and phenotypes. T T .------------- T | TT | TT | .------------- t | Tt | Tt | .------------- The genotypic and phenotypic results will be as follows: Genotypes: 50% TT (homozygous tall) 50% Tt (heterozygous tall) Phenotypes: 100% Tall
04

Cross (d) - Progeny of (a) crossed with a dwarf plant

Finally, we will cross the progeny from (a) (Tt) with a dwarf plant (tt). We will do a Punnett square to determine the genotypes and phenotypes. t t .------------- T | Tt | Tt | .------------- t | tt | tt | .------------- The genotypic and phenotypic results will be as follows: Genotypes: 50% Tt (heterozygous tall) 50% tt (homozygous dwarf) Phenotypes: 50% Tall 50% Dwarf

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Genotype and Phenotype Prediction
Understanding how to predict genotypes and phenotypes using a Punnett square can help us understand the possible outcomes when crossing different genetic traits. - **Genotype** refers to the genetic makeup of an organism, represented by allele pairs like "TT," "Tt," or "tt" for tall and dwarf plants, respectively. - **Phenotype** is the observable characteristic or trait, like the plant being tall or dwarf, depending on the genotype. Punnett squares are handy tools for visualizing these possible genetic outcomes. Consider a homozygous tall plant ("TT") crossed with a dwarf plant ("tt"). This cross results in 100% heterozygous tall plants ("Tt") both in genotype and phenotype. When predicting outcomes: - **Step 1**: Determine the alleles contributed by each parent. - **Step 2**: Set up the Punnett square grid. - **Step 3**: Map out possible allele combinations and deduce the percentage of each genotype and corresponding phenotype. This method allows for clear predictions of both the genetic and visible traits of offspring, aiding in comprehending broader genetic trends.
Homozygous and Heterozygous
The concepts of homozygous and heterozygous relate directly to the pairs of alleles (genes) an organism possesses for a trait. - **Homozygous** means having two identical alleles for a trait, such as "TT" (homozygous tall) or "tt" (homozygous dwarf) in garden peas. - **Heterozygous** refers to having two different alleles, like "Tt" for a tall pea plant. These terms are crucial for predicting genetic outcomes, as they influence the genotype results in genetic crosses: - In a cross between a homozygous tall plant ("TT") and a dwarf ("tt"), all offspring are heterozygous ("Tt"). - If two heterozygous plants ("Tt") are crossed, the offspring can be homozygous tall ("TT"), heterozygous tall ("Tt"), or homozygous dwarf ("tt"). Recognizing whether the alleles involved in a genetic cross are homozygous or heterozygous helps in understanding inheritance patterns and predicting outcomes with a greater degree of accuracy, using tools like Punnett squares.
Garden Pea Genetics
Garden peas are a classic model used in genetics due to their distinct traits and ease of controlled pollination. Gregor Mendel, the "Father of Genetics," utilized these plants over a century ago to lay down the foundational principles of heredity. In garden peas, several traits exhibit simple Mendelian inheritance, such as plant height (tall vs. dwarf), seed color, and flower color. These traits are usually controlled by single genes with two alleles each, making peas ideal for studying basic genetic principles: - **Dominant Traits**: In peas, the tall height is dominant, which means it will appear in the phenotype if one or both alleles are tall ("T"). - **Recessive Traits**: Dwarf height ("t") only appears when both alleles are recessive ("tt"). When performing genetic crosses, such as those between tall and dwarf plants, we've seen how Punnett squares help predict the genetic and phenotypic outcomes. Understanding these basic principles utilized by Mendel helps to clarify more intricate genetic concepts and highlights the power of controlled experimentation in revealing life's hereditary rules.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

If two fruit flies, heterozygous for genes of one allelic pair, were bred together and had 200 offspring ... (a) about how many would have the dominant phenotype? (b) of these offspring, some will be homozygous dominant and some heterozygous. How is it possible to establish which is which?

Normal-length fur in rabbits is controlled by the dominant allele \(\mathrm{R}\), and a short type of fur, called "rex," is determined by the recessive allele \(\mathrm{r}\). The dominant allele B controls black fur color; the recessive allele b controls brown. (a) Diagram a dihybrid cross between a homozygous rabbit with normal-length black fur and a rex rabbit with brown fur. What are the phenotypic ratios resulting from this cross? (b) What proportion of the normal, black rabbits in the \(\mathrm{F}_{2}\) generation of this cross can be expected to be homozygous for both pairs of genes? (c) What would be the expected phenotypic and genotypic results of a backcross between a member of the \(\mathrm{F}_{1}\) generation and a fully recessive rex, brown parent?

The checkered pattern of pigeons is controlled by a dominant gene \(C\); plain color is determined by the recessive allele c. Red color is controlled by a dominant gene \(\mathrm{B}\), and brown color by the recessive allele b. Complete a Punnett square for a dihybrid cross involving a homozygous checkered red bird and a plain brown bird. For this cross, show the expected phenotypes, genotypes, genotypic frequencies and phenotypic ratios for the \(\mathrm{F}_{2}\) generation.

What are the possible gametes that can be formed from the following genotypes, assuming all the gene pairs segregate independently? What are the gamete frequencies? (a) \(\mathrm{A} \mathrm{aBBCc}\) (b) DdEEffGg (c) \(\mathrm{MmNnOo}\)

A man and a woman are heterozygous for tongue rolling, and have three sons. The three sons marry women who are not tongue rollers. Assuming that each of the three sons has a different genotype, show by diagram what proportion of their children might have the ability to roll their tongues.

See all solutions

Recommended explanations on Biology Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.