/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 13 Duchenne muscular dystrophy (DMD... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Duchenne muscular dystrophy (DMD), marked by muscular degeneration, results from an \(\mathrm{X}\) - linked recessive gene. Thus, a female who is heterozygous for this gene and does not have the disease can be a carrier. What kind of offspring can you expect from a DMD-affected male and a carrier female? Can there be a carrier male?

Short Answer

Expert verified
Explain your answer. Answer: No, there cannot be a carrier male in this situation. A carrier male would have the genotype X_dY, meaning they would also be affected by DMD since they only have one X chromosome, which contains the defective gene. In this scenario, males either have the affected genotype (X_dY) or the unaffected genotype (XY).

Step by step solution

01

Understand the genotypes of the parents

A DMD-affected male has the genotype X_dY, where X_d is the defective X chromosome. A carrier female has the genotype X_dX, where X is the normal X chromosome.
02

Set up a Punnett square

A Punnett square is a diagram that is used to predict the possible genotypes and outcomes of offspring from the cross of two genetic parents. To create our Punnett square, draw a 2x2 grid and write the possible gametes (reproductive cells) of the parents along the top and side of the grid. For the DMD-affected male, the gametes will be X_d and Y. For the carrier female, the gametes will be X_d and X.
03

Fill the Punnett square

Fill the boxes of the Punnett square by combining the gametes from each parent. This will give us the following combinations: - X_dX_d: affected female - X_dX: carrier female - X_dY: affected male - XY: unaffected male
04

Identify the offspring outcomes

Looking at the Punnett square, the following outcomes for the offspring are: 1. 50% chance of being an affected female (X_dX_d) 2. 50% chance of being a carrier female (X_dX) 3. 50% chance of being an affected male (X_dY) 4. 50% chance of being an unaffected male (XY) Keep in mind that this is a probability, so individual offspring may not follow these exact ratios, but with a large enough sample size, these ratios would be observed.
05

Analyze whether there can be a carrier male

A carrier male would have the genotype X_dY, meaning they would also be affected by DMD since they only have one X chromosome, which contains the defective gene. Therefore, there cannot be a carrier male in this situation.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Punnett square
A Punnett square is a simple graphical tool geneticists use to predict the possible genotypes of offspring from two parents. It's a 2x2 grid that helps visualize genetic combinations.
When setting up a Punnett square, you'll list one parent's alleles (variations of a gene) along one side and the other parent's alleles along the adjacent side. Each box within the grid represents a potential combination of alleles from the parents.
Here's how it works step-by-step:
  • Draw a square and divide it into four smaller squares, creating a 2x2 grid.
  • Write the two types of alleles from one parent across the top (one per column).
  • Write the two types of alleles from the other parent along the side (one per row).
  • Fill in the boxes by combining the alleles from the top and the side of each box.
This technique not only illustrates the potential outcomes of a genetic cross but also helps determine the probability of each genotype occurring in the offspring.
Duchenne muscular dystrophy
Duchenne muscular dystrophy (DMD) is a genetic disorder characterized by progressive muscle degeneration and weakness. It results from mutations in the DMD gene, which is responsible for producing dystrophin. Dystrophin is a protein that helps keep muscle cells intact.
DMD follows an X-linked recessive inheritance pattern, meaning the gene responsible for DMD is located on the X chromosome. Since males (XY) have only one X chromosome, they are more likely to exhibit symptoms if they inherit the defective gene. Females (XX), having two X chromosomes, are usually carriers and often do not express symptoms if they inherit a normal copy of the gene in addition to the defective one.
To understand the implications:
  • Males with the defective gene (XdY) will have DMD.
  • A female with one defective gene (XdX) typically does not show symptoms.
DMD affects approximately 1 in 3,500 male births worldwide and currently has no cure, although treatments can help manage symptoms and improve quality of life.
Genetic carrier
A genetic carrier is an individual who has one copy of a mutated gene that can lead to a genetic disorder, but does not typically show symptoms of the disorder themselves. This is especially applicable in X-linked recessive conditions like Duchenne muscular dystrophy.
In the context of DMD:
  • A carrier female has one normal X chromosome and one X chromosome with the defective DMD gene (XdX).
  • These women do not manifest the disease because the normal gene compensates for the defective one.
When a carrier female and an unaffected male have children, the genetic results can vary. Sons are more likely to be affected because they inherit one X chromosome—if it’s the defective one, they will express the disorder.
It's important to note that carrier males in an X-linked recessive condition do not exist because males will express the disorder due to the absence of a second X chromosome. Understanding carrier status is crucial in genetic counseling, especially for diseases that follow this inheritance pattern.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A geneticist from an alien planet that prohibits genetic research brought with him two true-breeding lines of frogs. One frog line croaks by uttering "rib-it rib-it" and has purple eyes. The other frog line croaks by muttering "knee- deep knee-deep" and has green eyes. He mated the two frog lines, producing \(\mathrm{P}_{1}\) frogs that were all utterers with blue eyes. A large \(\mathrm{F}_{2}\) generation then yielded the following ratios: \(27 / 64\) blue, utterer \(12 / 64\) green, utterer \(9 / 64\) blue, mutterer \(9 / 64\) purple, utterer \(4 / 64\) green, mutterer \(3 / 64\) purple, mutterer (a) How many total gene pairs are involved in the inheritance of both eye color and croaking? (b) Of these, how many control eye color, and how many control croaking? (c) Assign gene symbols for all phenotypes, and indicate the genotypes of the \(P_{1}, F_{1},\) and \(F_{2}\) frogs. (d) After many years, the frog geneticist isolated true-breeding lines of all six \(\mathrm{F}_{2}\) phenotypes. Indicate the \(\mathrm{F}_{1}\) and \(\mathrm{P}_{2}\) phenotypic ratios of a cross between a blue, mutterer and a purple, utterer.

What genetic criteria distinguish a case of extranuclear inheritance from (a) a case of Mendelian autosomal inheritance; (b) a case of \(\mathrm{X}\) -linked inheritance?

Three gene pairs located on separate autosomes determine flower color and shape as well as plant height. The first pair exhibits incomplete dominance, where color can be red, pink (the heterozygote), or white, The second pair leads to the dominant personate or recessive peloric flower shape, while the third gene pair produces either the dominant tall trait or the recessive dwarf trait. Homozygous plants that are red, personate, and tall are crossed with those that are white, peloric, and dwarf. Determine the \(P_{1}\) genotype(s) and phenotype(s). If the \(F_{1}\) plants are interbred, what proportion of the offspring will exhibit the same phenotype as the \(F_{1}\) plants?

The trait of medium-sized leaves in iris is determined by the genetic condition \(P P^{\prime}\). Plants with large leaves are \(P P\), whereas plants with small leaves are \(P^{\prime} P^{\prime} .\) A cross is made between two plants each with medium-sized leaves. If they produce 80 seedlings, what would be the expected phenotypes, and in what numbers would they be expected? What is the term for this allelic relationship?

A husband and wife have normal vision, although both of their fathers are red- green color-blind, inherited as an X-linked recessive condition. What is the probability that their first child will be (a) a normal son, (b) a normal daughter, (c) a color-blind \(\operatorname{son},(d)\) a color-blind daughter?

See all solutions

Recommended explanations on Biology Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.