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Consider a population in which the frequency of allele \(A\) is \(p=0.7\) and the frequency of allele \(a\) is \(q=0.3,\) and where the alleles are codominant. What will be the allele frequencies after one generation if the following occurs? (a) \(w_{A A}=1, w_{A a}=0.9,\) and \(w_{a a}=0.8\) (b) \(w_{A A}=1, w_{A a}=0.95,\) and \(w_{a a}=0.9\) (c) \(w_{A A}=1, w_{A a}=0.99, w_{a a}=0.98\) (d) \(w_{A A}=0.8, w_{A a}=1, w_{a a}=0.8\)

Short Answer

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Question: In a population of individuals with the following genotype frequencies: A A = 49%, A a = 42%, and a a = 9%, consider the four given scenarios of fitness values for each genotype (A A, A a, and a a): (a) 1, 0.9, 0.8, (b) 1, 0.95, 0.9, (c) 1, 0.99, 0.98, and (d) 0.8, 1, 0.8. Calculate the allele frequencies after one generation for each scenario. Answer: The allele frequencies after one generation for each scenario are: (a) A: 0.737, a: 0.263 (b) A: 0.719, a: 0.281 (c) A: 0.707, a: 0.293 (d) A: 0.692, a: 0.308

Step by step solution

01

Calculate genotype frequencies

We will use the Hardy-Weinberg equation to find the genotype frequencies in the initial generation: $$p^2 + 2pq + q^2 = 1$$ $$A A: (0.7)^2 = 0.49$$ $$A a: 2(0.7)(0.3) = 0.42$$ $$a a: (0.3)^2 = 0.09$$ Step 2: Calculate average fitness for each scenario
02

Calculate average fitness

We will use the following formula to compute average fitness for each scenario: $$w = (f_{A A} \times w_{A A}) + (f_{A a} \times w_{A a}) + (f_{a a} \times w_{a a})$$ We will now calculate this for each scenario. - (a): $$w = (0.49 \times 1) + (0.42 \times 0.9) + (0.09 \times 0.8)$$ $$w = 0.913$$ - (b): $$w = (0.49 \times 1) + (0.42 \times 0.95) + (0.09 \times 0.9)$$ $$w = 0.958$$ - (c): $$w = (0.49 \times 1) + (0.42 \times 0.99) + (0.09 \times 0.98)$$ $$w = 0.985$$ - (d): $$w = (0.49 \times 0.8) + (0.42 \times 1) + (0.09 \times 0.8)$$ $$w = 0.864$$ Step 3: Calculate allele frequencies in the next generation
03

Calculate next-generation allele frequencies

For the next-generation allele frequencies, we can use the following formula: $$p'=\frac{p^2w_{A A}+pqw_{A a}}{w}$$ $$q'=\frac{pqw_{A a}+q^2w_{a a}}{w}$$ - (a): $$p'=\frac{(0.49 \times 1)+(0.42 \times 0.9)}{0.913}=0.737$$ $$q'=1-p'=0.263$$ - (b): $$p'=\frac{(0.49 \times 1)+(0.42 \times 0.95)}{0.958}=0.719$$ $$q'=1-p'=0.281$$ - (c): $$p'=\frac{(0.49 \times 1)+(0.42 \times 0.99)}{0.985}=0.707$$ $$q'=1-p'=0.293$$ - (d): $$p'=\frac{(0.49 \times 0.8)+(0.42 \times 1)}{0.864}=0.692$$ $$q'=1-p'=0.308$$ So, the allele frequencies for each scenario after one generation are (rounded to the nearest thousandth): (a): \(A: 0.737,\) \(a: 0.263\) (b): \(A: 0.719,\) \(a: 0.281\) (c): \(A: 0.707,\) \(a: 0.293\) (d): \(A: 0.692,\) \(a: 0.308\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Genotype Frequencies
Understanding genotype frequencies is foundational in studying population genetics and the Hardy-Weinberg equilibrium. These frequencies describe the proportion of the various genotypes within a population. In the context of the given exercise, genotype frequencies pertain to the combinations of alleles for a genetic locus: AA, Aa, and aa.

Using the Hardy-Weinberg principle, we expect the genotype frequencies to be represented by the terms of the binomial expansion of \( (p + q)^2 \) for a population in equilibrium. However, as fitness values are introduced, which represent the reproductive success of each genotype, these frequencies can shift, reflecting natural selection. Through calculations such as the ones in the exercise, students can observe how selective pressures can alter genotype frequencies and thus change genetic structure over generations.
Allele Frequencies
On the other hand, allele frequencies refer to how common an allele is in the population, typically denoted as ‘p’ for the dominant allele and ‘q’ for the recessive allele. These two frequencies must always add up to 1, as they represent all the possible variants of a gene in the population. During the exercise, allele frequencies were recalculated after applying fitness values to account for differential survival and reproduction, demonstrating how allele frequencies can change from one generation to the next due to selection. Thus, the concept of allele frequencies is crucial in understanding the genetic variation within a population and predicting its future genetic composition.
Average Fitness
Average fitness of a population—denoted as ‘w’ in genetic equations—is a measure that encompasses the reproductive success of all genotypes weighted by their respective frequencies. This measure, fundamentally entwined with the concept of natural selection, gives insight into the adaptive landscape of a population. In the context of the exercise, calculating the average fitness under different scenarios showed how different survival and reproduction rates among the genotypes influence the overall adaptive capacity of the population. Furthermore, it illuminates how more fit genotypes can increase in frequency over time, thereby driving evolutionary change. The computation of average fitness thus merges genotype frequencies and individual fitness into a composite metric reflecting the evolutionary vitality of the population.

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Most popular questions from this chapter

In a recent study of cichlid fish inhabiting Lake Victoria in Africa, Nagl et al. (1998. Proc. Natl. Acad. Sci. IUSA/ 95: \(14,238-14,243\) ) examined suspected neutral sequence polymorphisms in noncoding genomic loci in 12 species and their putative river-living ancestors. At all loci, the same polymorphism was found in nearly all of the tested species from Lake Victoria, both lacustrine and riverine. Different polymorphisms at these loci were found in cichlids at other African lakes. (a) Why would you suspect neutral sequences to be located in noncoding genomic regions? (b) What conclusions can be drawn from these polymorphism data in terms of cichlid ancestry in these lakes?

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Calculate the frequencies of the \(A A, A a,\) and \(a a\) genotypes after one generation if the initial population consists of \(0.2 \mathrm{AA}, 0.6\) \(A a,\) and 0.2 aa genotypes and meets the requirements of the Hardy-Weinberg relationship. What genotype frequencies will occur after a second generation?

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