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Chapter 12: Problem 14

A particular variant of the lambda bacteriophage has a DNA double-stranded genome of 51,365 base pairs. How long would this DNA be?

Short Answer

Expert verified
Answer: The approximate length of a lambda bacteriophage DNA molecule with 51,365 base pairs is 17.4641 micrometers.

Step by step solution

01

Number of base pairs and distance between them

The given lambda bacteriophage has a genome with 51,365 base pairs. The distance between two consecutive base pairs in a DNA double-strand helix is approximately 0.34 nanometers.
02

Calculate the length of the DNA

To find the length of the DNA, we will multiply the number of base pairs by the distance between consecutive base pairs: Length of DNA = (Number of base pairs) * (Distance between consecutive base pairs) = 51,365 * 0.34 nm
03

Calculate the result in nanometers

Multiplying the number of base pairs by the distance between them, we get: Length of DNA = 51,365 * 0.34 nm = 17,464.1 nanometers
04

Convert the length to a more suitable unit

Since the length of the DNA is quite large, we can convert it to a more suitable unit, like micrometers (碌m): 1 碌m = 1000 nm; Length of DNA = 17,464,1 nm * (1 碌m / 1000 nm) = 17.4641 碌m So, the length of this particular lambda bacteriophage DNA is approximately 17.4641 micrometers.

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