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Compound \(\mathrm{Y}\) has been determined to have a molar absorptivity (extinction coefficient) of 1000 liters/ mole \(\cdot \mathrm{cm}\) at \(390 \mathrm{~nm}\). An unknown solution of this compound has an absorption of \(0.750\) when placed in a cell with a light path of \(1 \mathrm{~cm}\). The concentration of this compound is: a. \(375 \mathrm{~mole} / \mathrm{L}\) b. \(750 \mathrm{~mole} / \mathrm{L}\) c. \(750 \mu \mathrm{mole} / \mathrm{L}\) d. \(0.375 \mathrm{mmole} / \mathrm{L}\) e. \(750 \mathrm{mmole} / \mathrm{L}\)

Short Answer

Expert verified
Option (e): 750 mmol/L

Step by step solution

01

Understand the Beer-Lambert Law

The Beer-Lambert Law relates the absorption of light to the properties of the material through which the light is traveling. The law is given by the formula: \[ A = \rho l c \] where: - \( A \) is the absorbance (unitless) - \( \rho \) (epsilon) is the molar absorptivity or extinction coefficient (L/(mol \,cm)) - \( l \) is the path length that the light travels through the solution (cm) - \( c \) is the concentration of the solution (mol/L)
02

Identify Given Values

From the problem, the given values are: - Absorbance, \( A = 0.750 \) - Molar absorptivity, \( \rho = 1000 \; L \, / \, mole \, \cdot \mathrm{cm} \) - Path length, \( l = 1 \; \mathrm{cm} \)
03

Rearrange the Beer-Lambert Law to Solve for Concentration

Rearrange the formula to solve for concentration \( c \): \[ c = \frac{A}{\rho l} \]
04

Substitute the Given Values into the Equation

Substitute the given values into the equation: \[ c = \frac{0.750}{1000 \, \times \, 1} \]
05

Perform the Calculation

Calculate the concentration: \[ c = 0.00075 \, mol/L \]
06

Convert Molarity to Correct Units

Since the answer choices involve different unit conversions (e.g., millimoles and micromoles), convert \( 0.00075 \, mol/L \) to suitable units. \[ 0.00075 \, mol/L = 0.750 \, mmol/L \]
07

Match with the Correct Answer Choice

The value \( 0.750 \, mmol/L \) matches option (e). Thus, the concentration of the compound is: \( 0.750 \, mmol/L \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

molar absorptivity
Molar absorptivity, also known as the extinction coefficient, is a measure of how strongly a chemical species absorbs light at a given wavelength. It is denoted by the symbol \( \epsilon \) and has units of liters per mole per centimeter \( L/(mol \cdot cm) \). Molar absorptivity is an intrinsic property of the substance and can help identify or quantify the substance based on how much light it absorbs at a specific wavelength. In the provided exercise, compound Y has a molar absorptivity of 1000 L/(mol \cdot cm) at 390 nm, which means every mole of Y absorbs 1000 liters of light per centimeter of path length at that wavelength.
light absorption
Light absorption is the process by which a substance captures and assimilates energy from light. This process follows the Beer-Lambert Law, which states that the amount of light absorbed by a substance is directly proportional to its concentration and the path length the light travels through. The formula representing this relationship is: \[ A = \epsilon l c \], where A is the absorbance (no units), \( \epsilon \) is the molar absorptivity, l is the path length (in cm), and c is the concentration (in mol/L). In our example, an unknown solution of compound Y has an absorbance of 0.750, indicating that the light's intensity has been significantly reduced while passing through the substance.
concentration calculation
In the Beer-Lambert Law, concentration calculation involves rearranging the formula to solve for c. The formula is: \[ c = \frac{A}{\epsilon l} \]. Given the values from the exercise, absorbance A = 0.750, molar absorptivity \( \epsilon \) = 1000 L/(mol \( \cdot \) cm), and the path length l = 1 cm, we substitute these:

\[ c = \frac{0.750}{1000 \times 1} = 0.00075 \ mol/L \]. This calculation shows that the concentration of compound Y in the solution is 0.00075 mol/L.
unit conversion
Unit conversion is a crucial step in scientific calculations as it ensures consistency and understanding of data. Frequently, concentrations can be expressed in different units such as moles per liter (mol/L), millimoles per liter (mmol/L), or micromoles per liter (μmol/L). In our exercise, the calculated concentration is 0.00075 mol/L. To convert this into millimoles per liter, we multiply by 1000:\[ 0.00075 \ mol/L = 0.750 \ mmol/L \]. Hence, the solution concentration is 0.750 mmol/L, which matches option (e) in the problem statement. Always ensure units are consistent throughout your calculations to avoid errors.

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