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Next, use the Hardy-Weinberg equation (p2 + 2pq + q2 = 1) to calculate the day seven expected frequencies of genotypes CGCG, CGCY, and CYCY for a population in Hardy-Weinberg equilibrium.

Short Answer

Expert verified

The expected frequencies of the genotypes \({C^G}{C^G}\),\({C^G}{C^Y}\), and \({C^Y}{C^Y}\)calculated from the day seven data are 0.23, 0.50, and 0.26, respectively.

Step by step solution

01

Hardy-Weinberg equilibrium

The mathematical equation for Hardy-Weinberg equilibrium is-

\({p^2} + 2pq + {q^2} = 1\), where \({p^2}\) is the genotype frequency for the homozygous dominant character, \({q^2}\) is the genotype frequency for the homozygous recessive character, and \(2pq\) is the genotype frequency for heterozygous individuals.

And \(p + q = 1\) , where \(p\)is the frequency of the dominant allele, and\(q\)is the frequency of the recessive allele.

A Hardy-Weinberg population is large where random mating occurs and is devoid of natural selection, mutation, and migration influences. In short, the population is not undergoing evolution.

02

Expected genotype frequency

Expected genotype frequency for homozygous dominant genotype and homozygous recessive genotype are the squares of dominant allele frequency and recessive allele frequency, respectively.

For heterozygous dominant genotype, the expected genotype frequency is two times the frequency of dominant and recessive alleles. It provides a measure of the number of a particular genotype that is predicted after a cross.

03

Expected frequencies of genotypes CGCG, CGCY, and CYCY

From the observed frequencies from Day 7, it is given that:

Number of homozygous dominant or green seedlings (\({C^G}{C^G}\))= 49

Total number of seedlings= 216

The genotypic frequency of \({C^G}{C^G}\) (\({p^2}\)) is:

\({p^2} = \frac{{Number{\rm{ }}of{\rm{ }}homozygous{\rm{ }}dominant{\rm{ }}or{\rm{ }}green{\rm{ }}seedlings{\rm{ }}\left( {{C^G}{C^G}} \right)}}{{Total{\rm{ }}number{\rm{ }}of{\rm{ }}seedlings}}\)


The allele frequency for\({C^G}\)allele (\(p\)) is:

\(p = \sqrt {\frac{{Number{\rm{ }}of{\rm{ }}homozygous{\rm{ }}dominant{\rm{ }}or{\rm{ }}green{\rm{ }}seedlings{\rm{ }}\left( {{C^G}{C^G}} \right)}}{{Total{\rm{ }}number{\rm{ }}of{\rm{ }}seedlings}}} \)

\(\begin{aligned}{c}p &= \sqrt {\frac{{49}}{{216}}} \\ &= 0.476\\ \simeq 0.48\end{aligned}\)

The expected genotypic frequencyof \({C^G}{C^G}\) (\({p^2}\)) is:

\(\begin{aligned}{l}{p^2} &= 0.48 \times 0.48\\{p^2} &= 0.23\end{aligned}\)

From the observed frequencies from Day 7, it is given that:

Number of homozygous dominant or yellow seedlings (\({C^Y}{C^Y}\))= 56

Total number of seedlings= 216

The genotypic frequency of \({C^Y}{C^Y}\) (\({q^2}\)) is:

\({q^2} = \frac{{Number{\rm{ }}of{\rm{ }}homozygous{\rm{ }}recessive{\rm{ }}or{\rm{ }}yellow{\rm{ }}seedlings{\rm{ }}\left( {{C^Y}{C^Y}} \right)}}{{Total{\rm{ }}number{\rm{ }}of{\rm{ }}seedlings}}\)

The allele frequency for\({C^Y}\)allele (\(q\)) is:

\(q = \sqrt {\frac{{Number{\rm{ }}of{\rm{ }}homozygous{\rm{ }}recessive{\rm{ }}or{\rm{ }}yellow{\rm{ }}seedlings{\rm{ }}\left( {{C^Y}{C^Y}} \right)}}{{Total{\rm{ }}number{\rm{ }}of{\rm{ }}seedlings}}} \)

\(\begin{aligned}{c}q &= \sqrt {\frac{{56}}{{216}}} \\ &= 0.509\\ \simeq 0.51\end{aligned}\)

The expected genotypic frequencyof \({C^Y}{C^Y}\) (\({q^2}\)) is:

\(\begin{aligned}{l}{q^2} &= 0.51 \times 0.51\\{q^2} &= 0.26\end{aligned}\)

We have:

\(p = 0.48\)and\(q = 0.51\)

The expected frequency for\({C^G}{C^Y}\)(\(2pq\)) is:

\(\begin{aligned}{l}2pq &= 2 \times 0.48 \times 0.51\\2pq &= 0.489\\2pq &= 0.49\end{aligned}\)

\(2pq = 0.5\)

Thus, the expected frequencies of the genotypes such as\({C^G}{C^G}\),\({C^G}{C^Y}\), and\({C^Y}{C^Y}\)are 0.23, 0.50, and 0.26, respectively.

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Most popular questions from this chapter

Explain why natural selection is the only evolutionary mechanism that consistently leads to adaptive evolution in a population.

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Using at least two examples, explain how the process of evolution is revealed by the imperfections of living organisms.

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