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Chapter 14: Q14.4-4CC. (page 290)

In table 14.1, note the phenotypic ratio of the dominant to recessive traits in the F2 generation for the monohybrid cross involving flower color. Then determine the phenotypic ratio for the offspring of the second generation couple in Figure 14.15b. What accounts for the difference in the two ratios?

Short Answer

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The flower appears in the ratio of 3.15:1 for the purple and white colors, which occurs in monohybrid crossing. In humans, the phenotypic ratio seen in the third generation is 1:1 ratio. The condition is that one can taste the PTC, and one cannot taste PTC. The difference is due to the different sample sizes.

Step by step solution

01

Description of monohybrid crossing

The crossing made between the parents with differences present in only one character is known as monohybrid crossing. The genotypes of the monohybrid crosses are homogenous in condition.

02

Ratio of flower color in monohybrid crossing

The plants with the purple flower and the white flower are crossed to obtain the F2 generation. The phenotypic ratio of the flower color is in the ratio of 3.15 for purple color flower: 1 white.

03

Reason for the difference in two ratios

PTC is abbreviated as phenylthiocarbamide. The family pedigree tree denotes the condition of PTC, such as the presence of taste reception of PTC and does not have taste reception to PTC.

The differences in the two ratios are due to the small sample size. Compared to the first and second generations, the sample sizes are lesser in the third generation of the human family.

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Most popular questions from this chapter

A man has six fingers on each hand and six toes on each foot. His wife and their daughter have the normal number of digits. Remember that extra digits are a dominant trait. What fraction of this couple's children would be expected to have extra digits?

List all gametes that could be made by a pea plant heterozygous for seed color, seed shape, and pod shape (YyRrIi; see Table 14.1). How large a Punnett square would you need to draw to predict the offspring of a self-pollination of this 鈥渢rihybrid鈥�?

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Beth and Tom eachhave a sibling with cystic fibrosis, but neither Beth nor Tom nor any of their parents have the disease. Calculate the probability that if this couple has a child, the child will have cystic fibrosis. What would be the probability of a test revealing that Tom is a carrier, but Beth is not? Explain your answers.

Flower position, stem length, and seed shape are three characters that Mendel studied. Each is controlled by an independently assorting gene and has a dominant and recessive expression, as indicated in Table 14.1. If a plant that is heterozygous for all three characters is allowed to self fertilize, what proportion of the offspring would you expect to be each of the following? (Note: Use the rules of probability instead of a huge Punnett square)

(a) homozygous for the three dominant traits

(b) homozygous for the three recessive traits

(c) heterozygous for all three characters

(d) homozygous for axial and tall, heterozygous for seed shape
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