91影视

Inheritance is the transfer of genes from the parents to the offspring. The inheritance occurs via sexual reproduction, and the offspring generated from the parents are known as F1 offspring.

F2 offspring are obtained by crossing the F1 hybrid.

In general, the probability of occurrence of a homozygous trait 鈥淴X or xx鈥� is 录, and the probability of occurrence of a heterozygous trait 鈥淴x鈥� is 陆.

The given offspring is aabbccdd. All the traits are homozygous for the four recessive traits. Thus, the probability of the F2 offspring is as follows:

$\text{Probability}=\frac{1}{4}脳\frac{1}{4}脳\frac{1}{4}脳\frac{1}{4}=\frac{1}{256}$

The given F2 offspring is AaBbCcDd. All the given traits are heterozygous for each trait. Thus, the probability of the F2 offspring is as follows:

$\text{Probability}=\frac{1}{2}脳\frac{1}{2}脳\frac{1}{2}脳\frac{1}{2}=\frac{1}{16}$

F2 offspring given in the question is AABBCCDD. The genotypic combination provided is homozygous for four dominant traits. Thus, the probability of the F2 offspring is as follows:

$\text{Probability}=\frac{1}{4}脳\frac{1}{4}脳\frac{1}{4}脳\frac{1}{4}=\frac{1}{256}$

F2 offspring given in the question is AaBBccDd. Aa and Dd are heterozygous for the traits, so they have a probability of 陆 each. BB and cc are homozygous for dominant and recessive traits, respectively, so they have a probability of 录 each.

Thus, the overall probability of the F2 offspring is as follows:

$\text{Probability}=\frac{1}{2}脳\frac{1}{2}脳\frac{1}{4}脳\frac{1}{4}=\frac{1}{64}$

F₂given in the question isAaBBCCdd. In this genotype, Aa is heterozygous for a trait with a probability is 1/2. BB, CC, and dd are homozygous for the traits, each with the probability of 录.

Thus, the overall probability of the F₂ offspring is as follows:

$\text{Probability}=\frac{1}{2}脳\frac{1}{4}脳\frac{1}{4}脳\frac{1}{4}=\frac{1}{128}$