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Chapter 14: Q14-2TYU. (page 292)

A man with type A blood marries a woman with type B blood. Their child has type O blood. What are the genotypes of these three individuals? What genotypes, and in what frequencies would you expect in future offspring from this marriage?

Short Answer

Expert verified

The genotypes of three individuals are IAi(man), IBi(woman), and ii(child). The future children with genotypes and frequencies are 录 IAIB, 录 IAi, 录 IBi, and 录 ii.

Step by step solution

01

Description of predictions of crossings

A man with type A blood group married a woman with type B. The child gets the blood group of O. It is due to the result of two recessive alleles.

The parents are heterozygous, so that that child will receive one recessive allele from the parents. The two blood group alleles in the man are IA and i., and that in the woman are IB and i.

02

Description of Punnet square for the given conditions

IA

i

IB

IAIB

IBi

i

IAi

ii

03

Predictions of frequencies for future children

The Punnet square crossing results in the formation of four genotypic frequencies. The genotypic combinations of the different blood groups are IAIB, IBi, IAi, and ii.

Each of the genotypic combinations is one out of four varieties. The final frequencies of each genetic combination are 录.

Hence, the man with blood group A and women with blood group B can have a child with blood group O with probability 录.

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Most popular questions from this chapter

You are handed a mystery pea plant with tall stems and axial flowers and asked to determine its genotype as quickly as possible. You know that the allele for tall stems (T) is dominant to that for dwarf stems (t) and that the allele for axial flowers (A) is dominant to that for terminal flowers (a).

(a) Identify all the possible genotypes for your mystery plant.

(b) Describe the one cross you would do, out in your garden, to determine the exact genotype of your mystery plant.

(c) While waiting for the results of your cross, you predict the results for each possible genotype listed in part a. Explain how you do this and why this is not called 鈥減erforming a cross.鈥�

(d) Explain how the results of your cross and your predictions will help you learn the genotype of your mystery plant.

In maize (corn) plants, a dominant allele I inhibit kernel color, while recessive allele i permits color when homozygous. At a different locus, the dominant allele P causes purple kernel color, while the homozygous recessive genotype pp causes red kernels. If plants heterozygous at both loci are crossed, what will be the phenotypic ratio of the offspring?

Pea plants heterozygous for flower position and stem length (AaTt) are allowed to self-pollinate, and 400 of the resulting seeds are planted. Draw a Punnett square for this cross. How many offspring would be predicted to have terminal flowers and be a dwarf? (See Table 14.1.)

A pea plant heterozygous for inflated pods (Ii) is crossed with a plant homozygous for constricted pods (ii). Draw a punnet square for this cross to predict genotypic and phenotypic ratios. Assume that pollen comes from the ii plants.

A man has six fingers on each hand and six toes on each foot. His wife and their daughter have the normal number of digits. Remember that extra digits are a dominant trait. What fraction of this couple's children would be expected to have extra digits?
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