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A slice of pizza has 500 kcal. If we could burn the pizza and use all the heat to warm a 50-L container of cold water, what would be the approximate increase in the temperature of the water? (Note: A liter of cold-water weighs about 1 kg.)

(A) The option, 鈥50掳C is false.

(B) The option, 鈥5掳Cis false.

(C) The option, 鈥100掳C鈥, is false.

(D) The option, 鈥10掳C鈥, is true.

Short Answer

Expert verified

(A) The option, 鈥50掳C is false.

(B) The option, 鈥5掳Cis false.

(C) The option, 鈥100掳C鈥, is false.

(D) The option, 鈥10掳C鈥, is true.

Step by step solution

01

Specific Heat of Water

The heat amount needed for raising the temperature of water for 1 degree Celsius for one gram is specific heat capacity. It is higher with respect to common substances when compared, due to which there is a major role of water in the regulation of temperature.

02

Explanation for option ‘(A)’

There will be a temperature change of 50 degrees Celsius for a 10 L water container for a 50 kcal pizza slice.

The formula for heat is\(Q = mc\Delta T\).

\(\begin{aligned}Q &= mc\Delta T\\500000 &= 10000 \times 1 \times \Delta T\\\Delta T &= \frac{{500000}}{{10000}}\end{aligned}\)

\(\Delta T = 50^\circ {\rm{C}}\)

Thus, the heat change will be\(50^\circ {\rm{C}}\),in the given case.

Therefore, the given statement is false.

03

Explanation for option ‘(B)’

If there is a change of temperature of 10 degrees Celsius for a 100 L water container for a 50 kcal pizza slice, then 5 degrees Celsius will not be the change.

The formula for heat is\(Q = mc\Delta T\).

\(\begin{aligned}Q &= mc\Delta T\\500000 &= 100000 \times 1 \times \Delta T\\\Delta T &= \frac{{500000}}{{100000}}\end{aligned}\)

\(\Delta T = 5^\circ {\rm{C}}\)

Thus, the heat change will be\(5^\circ {\rm{C}}\), in the given case.

Therefore, the given statement is false.

04

Explanation for option‘(C)’

The temperature change of 100 degrees Celsius will occur if a 5L of the water container is heated by 50 kcal from pizza.

The formula for heat is\(Q = mc\Delta T\).

\(\begin{aligned}Q &= mc\Delta T\\500000 &= 5000 \times 1 \times \Delta T\\\Delta T &= \frac{{500000}}{{5000}}\end{aligned}\)

\(\Delta T = 100^\circ {\rm{C}}\)

Thus, the heat change will be\(100^\circ {\rm{C}}\), in the given case.

Therefore, the given statement is false.

05

Explanation for option‘(D)’ 

The heat produced Q is given 500,000 calories from the pizza slice. It generates a change of temperature\(\Delta T\)in \(50{\rm{ kilograms}}\) of water container.

The formula for heat is\(Q = mc\Delta T\).

\(\begin{aligned}Q &= mc\Delta T\\500000 &= 50000 \times 1 \times \Delta T\\\Delta T &= \frac{{500000}}{{50000}}\end{aligned}\)

\(\Delta T = 10^\circ {\rm{C}}\)

Thus, the heat change will be\(10^\circ {\rm{C}}\), in the given case.

Therefore, the given statement is true.

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