Chapter 0: Problem 2
Find a number \(\omega\) so that the proposed solution satisfies the derivative equation. Solution \(\quad\) Derivative equation a. \(y(t)=3 \cos 5 t\) \(y^{\prime \prime}+\omega^{2} y=0\) b. \(y(t)=2 \sin 3 t+5 \cos 3 t\) \(y^{\prime \prime}+\omega^{2} y=0\) c. \(y(t)=-4 \cos \pi t\) \(y^{\prime \prime}+\omega^{2} y=0\) d. \(y(t)=3 e^{-t} \cos 5 t \quad y^{\prime \prime}+2 y^{\prime}+\omega^{2} y=0\) e. \(y(t)=-4 e^{-2 t} \sin 3 t \quad y^{\prime \prime}+4 y^{\prime}+\omega^{2} y=0\)
Short Answer
Step by step solution
Differentiate Part (a) twice
Substitute and solve for \(\omega^2\) in equation (a)
Differentiate Part (b) twice
Substitute and solve for \(\omega^2\) in equation (b)
Differentiate Part (c) twice
Substitute and solve for \(\omega^2\) in equation (c)
Differentiate Part (d) twice
Substitute and solve for \(\omega^2\) in equation (d)
Differentiate Part (e) twice
Substitute and solve for \(\omega^2\) in equation (e)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Second Derivative
- Increasing vs Decreasing: If \( y''(t) > 0 \), the function \( y(t) \) is concave up, suggesting that the function could be at a minimum or is part of an upward parabola structure.
- Concave Up vs Concave Down: Conversely, if \( y''(t) < 0 \), the function is concave down, indicating a possible maximum or a downward-facing parabola.
Trigonometric Functions
- Cosine and Sine Basics: Both \( \sin t \) and \( \cos t \) are periodic with a fundamental period of \( 2\pi \). This means that they repeat their values after an interval, integral to modeling cycles such as waves or repetitive movements.
- Derivatives of Trigonometric Functions: In calculus, the derivative of \( \cos(t) \) is \(-\sin(t)\), and the derivative of \( \sin(t) \) is \( \cos(t) \). These derivatives frequently show up in differential equations and form the cycle of periodicity in calculus operations.
Product Rule
- Application: This rule becomes crucial in problems where exponential and trigonometric functions are combined, as seen in \( y(t) = 3 e^{-t} \cos 5t \). Applying the product rule helps in calculating derivatives like \( y'(t) = -3 e^{-t} \cos 5t - 15 e^{-t} \sin 5t \).
- Simplification: After finding the first derivative, applying the product rule again if necessary for the second derivative yields the results needed to solve differential equations involving products of functions.