/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 6 Consider two alleles \(A\) and \... [FREE SOLUTION] | 91Ó°ÊÓ

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Consider two alleles \(A\) and \(a\) at a locus of a random mating population and the fractions of \(A A, A a\) and aa zygotes that reach maturity and mate are in the ratio \(1+s_{1}: 1: 1+s_{2}\) where \(s_{1}\) and \(s_{2}\) can be positive, negative, or zero, but \(s_{1} \geq-1\) and \(s_{2} \geq-1 .\) The balance function is $$ \begin{aligned} F(p)=\left(1+s_{1}\right) p^{2}+2 p q+\left(1+s_{2}\right) q^{2} &=\left(1+s_{1}\right) p^{2}+2 p(1-p)+\left(1+s_{2}\right)(1-p)^{2} \\ &=1+s_{1} p^{2}+s_{2}(1-p)^{2} \end{aligned} $$ where \(p\) and \(q\) are the frequencies of \(A\) and \(a\) among the zygotes. a. Sketch the graphs of \(F\) and find the values \(\hat{p}\) of \(p\) in [0,1] for which \(F(p)\) is a maximum for 1\. \(s_{1}=0.2\) and \(s_{2}=-0.3\). 2\. \(s_{1}=0\) and \(s_{2}=-0.2\) 3\. \(s_{1}=-0.2\) and \(s_{2}=-0.3\). 4\. \(s_{1}=0.2\) and \(s_{2}=0.3\) b. Suppose that \(s_{1}+s_{2} \neq 0\) and \(0 \leq s_{2} /\left(s_{1}+s_{2}\right) \leq 1 .\) Is it true that \(\hat{p} s_{2} /\left(s_{1}+s_{2}\right)\) is the value of \(p\) in [0,1] for which \(F(p)\) is a maximum?

Short Answer

Expert verified
Only condition 3 gives a valid \(\hat{p} = 0.6\). The statement in part b is true when conditions are met.

Step by step solution

01

Understanding the Problem

The problem involves analyzing the behavior of the function \(F(p)\) which represents the probability distribution of alleles in a population under given selection pressures \(s_1\) and \(s_2\). We need to investigate the conditions for which \(F(p)\) attains its maximum typically by finding the derivative and equating to zero to find the critical points.
02

Formulate the Function

Given: \[ F(p) = 1 + s_1p^2 + s_2(1-p)^2 \]Expand this: \[ F(p) = 1 + s_1p^2 + s_2(1-2p+p^2) \] Simplify to: \[ F(p) = 1 + (s_1 + s_2)p^2 - 2s_2p + s_2 \]Combine like terms to get:\[ F(p) = (s_1 + s_2)p^2 - 2s_2p + (1 + s_2) \]
03

Calculate Derivative

To find maxima, we set the derivative of \(F\) with respect to \(p\) to zero: \[ \frac{dF}{dp} = 2(s_1 + s_2)p - 2s_2 \]Set \( \frac{dF}{dp} = 0 \) and solve for \(p\):\[ 2(s_1 + s_2)p = 2s_2 \]\[ p = \frac{s_2}{s_1 + s_2} \]
04

Determine Maximum Points for Given Conditions

For different values of \(s_1\) and \(s_2\):1. \(s_1=0.2, s_2=-0.3\) yields \(p = \frac{-0.3}{0.2 - 0.3} = 3\) (not feasible as \(p\) must be in \([0,1]\))2. \(s_1=0, s_2=-0.2\) yields \(p = \frac{-0.2}{0 - 0.2} = 1\)3. \(s_1=-0.2, s_2=-0.3\) yields \(p = \frac{-0.3}{-0.5} = 0.6\)4. \(s_1=0.2, s_2=0.3\) yields \(p = \frac{0.3}{0.5} = 0.6\)
05

Analyze the Condition and Verify It

Given: \(0 \leq \frac{s_2}{s_1 + s_2} \leq 1\), this implies that \(p\) lies within feasible range \([0,1]\).If \(s_1 + s_2 eq 0\), indeed \(\hat{p} = \frac{s_2}{s_1 + s_2} \) correctly represents the maximum based on our derived formula since we ensured the derivative equals zero at that point, thus it's a sufficient condition for maximization within given limits.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Allele Frequency
Allele frequency is the proportion of a specific allele of a gene in a population. In population genetics, allele frequencies help us understand the genetic variation within the population. For example, considering alleles \(A\) and \(a\), if \(p\) is the frequency of allele \(A\), then \(q = 1 - p\) is the frequency of allele \(a\).

These frequencies are crucial in predicting the genetic makeup of future generations. In our exercise, we use the function \(F(p)\) to analyze allele distribution among \(AA, Aa,\) and \(aa\) zygotes. Varying selection pressures on these genotypes, represented by parameters \(s_1\) for \(AA\) and \(s_2\) for \(aa\), influence allele frequency changes over time. In particular, understanding their impact through calculations of critical values supports insights into evolutionary processes.
Natural Selection
Natural selection is a fundamental concept of evolutionary biology that explains how traits become more or less common in a population over generations. It results from differential survival and reproduction of individuals due to variations in phenotype. In our scenario, natural selection is represented by the parameters \(s_1\) and \(s_2\), influencing the fitness of different zygotes.

Fitness, in this context, reflects the ability of zygotes carrying specific allele combinations to mature and reproduce. If \(s_1\) and \(s_2\) are both positive, alleles \(A\) and \(a\) are beneficial. If negative, they're deleterious, affecting the prevalence of these alleles over time. Hence, understanding these selection coefficients helps in forecasting how natural selection will shape allele frequencies via the balance function, \(F(p)\).
Critical Points Analysis
Critical points analysis is a method to determine specific values within a function where maximum or minimum values occur. In population genetics, this is crucial for predicting stable allele frequencies. To find these points, we differentiate the balance function \(F(p)\) in terms of \(p\), leading us to critical points when the derivative equals zero.

By solving \[ \frac{dF}{dp} = 2(s_1 + s_2)p - 2s_2 = 0 \],
we locate the point \(p = \frac{s_2}{s_1 + s_2}\). This value tells us where the function \(F(p)\) might have a maximum. Substituting values for \(s_1\) and \(s_2\) from our different conditions, we determine feasible \(p\) values that reflect potential equilibria in allele frequencies under specific selection pressures.
Mathematical Modeling
Mathematical modeling in population genetics involves using mathematical equations to represent biological processes influencing allele frequencies. The balance function \(F(p)\) is a model incorporating selection coefficients \(s_1\) and \(s_2\) to explore genetic variations under natural selection.

This model illustrates how different levels of selection pressure alter allele distribution in a population. By expanding and differentiating this function, we study the equilibrium conditions—reflecting how populations might stabilize genetically over time. Such models allow scientists and students to predict real-world genetic dynamics, providing valuable insights into the evolutionary fate of alleles based on mathematical principles.

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Exercise 8.3 .3 Some small song birds intermittently flap their wings and glide with wings folded between flapping sessions. Why? R. M. Alexander \(^{3}\) suggests the following analysis. The power required to propel an airplane at a speed \(u\) is $$ P=A u^{3}+B L^{2} / u $$ where \(A\) and \(B\) are constants specific to the airplane and \(L\) is the upward force that lifts the plane. \(A u^{3}\) represents the drag on the airplane due largely to the air striking the front of the craft. a. For what speed is the required power the smallest? b. The energy required to propel the airplane is \(E=P / u\). For what speed is the energy required to propel the plane the smallest. c. How does the speed of minimum energy compare with the speed of minimum power? d. Suppose a bird has drag coefficient \(A_{b}\) with wings folded and \(A_{b}+A_{w}\) with wings extended and flapping, and let \(x\) be the fraction of time the bird spends flapping its wings. Suppose that the speed of the bird while flapping its wings is the same as the speed when the wings are folded and that all of the lift is provided when the wings are flapping. The lift over one complete cycle should be $$(1-x) L_{\text {folded }}+x L_{\text {flapping }}=x L_{\text {flapping }}=m g$$ where \(m\) is the mass of the bird. Then the power required while flapping is $$ P_{\text {flapping }}=\left(A_{b}+A_{w}\right) u^{3}+B\left(\frac{m g}{x}\right)^{2} \frac{1}{u} $$ Write an expression for \(P_{\text {folded }}\). e. The average power over a whole cycle should be $$ \bar{P}=(1-x) P_{\text {folded }}+x P_{\text {flapping }}=A_{b} u^{3}+x A_{w} u^{3}+B \frac{m^{2} g^{2}}{x u} $$ Find the value of \(x\) for which the average power over the whole cycle is minimum. f. The average energy over a whole cycle is \(\bar{E}=\bar{P} / u\). For what value of \(x\) is the average energy a minimum? This problem is continued in Exercise 13.2 .12 Alexander further notes that it may be necessary to consider also the efficiency of muscle contraction at different flapping rates.

A dog kennel with four pens each of area 7 square meters is to be constructed. An exterior fence surrounding a rectangular area is to be built of fence costing $$\$ 20$$ per meter. That rectangular area is then to be partitioned by three fences that are all parallel to a single side of the original rectangle and using fence that costs $$\$ 10$$ per meter. What dimensions of pens will minimize the cost of fence used?

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