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Chapter 13: Problem 1

Approximate the volume of the region between the graph of \(F\) and the \(x, y\) -plane using six or more subregions of its domain and a point selected in each subregion. a. \(\quad F(x, y)=x \times y \quad 0 \leq x \leq 3 \quad 0 \leq y \leq 2\) b. \(\quad F(x, y)=x+y \quad 1 \leq x \leq 3 \quad 2 \leq y \leq 5\) c. \(\quad F(x, y)=x \times \ln y \quad 0 \leq x \leq 3 \quad 1 \leq y \leq 3\) d. \(\quad F(x, y)=e^{-x-y} \quad 0 \leq x \leq 1 \quad 0 \leq y \leq 1\)

Short Answer

Expert verified
Volumes approximate to 18, 27, 2.079, and 0.36 respectively.

Step by step solution

01

Understanding the Problem

We need to find the approximate volume above the xy-plane under the surface defined by the given functions over specified regions with at least six subregions.
02

Define the Subregions for Part a

For the function \( F(x, y) = x \times y \) within the domain \(0 \leq x \leq 3\) and \(0 \leq y \leq 2\), divide this region into smaller rectangles. Choose subregion divisions like \([0, 1), [1, 2), [2, 3)\) for x and \([0, 1), [1, 2)\) for y. This gives us 6 subregions.
03

Select Points and Calculate Subregion Volumes for Part a

Choose a point within each subregion, like the top-right corner or center. For each point in the subregions: (1,1), (2,1), (3,1), (1,2), (2,2), (3,2), compute \( F(x_i, y_i) \times \Delta x \times \Delta y\), where \( \Delta x = 1\) and \( \Delta y = 1\). Sum these products in each subregion to approximate the volume.
04

Calculate for Part a

For example, at (1,1), \( F(1,1) = 1\times1 = 1 \). The volume contributed is \(1 \times 1 \times 1 = 1\). Doing analogously for each subregion, the sum = 1 + 2 + 3 + 2 + 4 + 6 = 18.
05

Define Subregions for Part b

For \( F(x, y) = x + y\), in domain \(1 \leq x \leq 3\) and \(2 \leq y \leq 5\), divide the range of x as \([1, 2), [2, 3)\) and y as \([2, 3), [3, 4), [4, 5)\). This creates 6 subregions.
06

Select Points and Calculate Volumes for Part b

Select points like (1.5, 2.5), (2.5, 2.5), and the others accordingly. For each subregion, calculate \( F(x_i, y_i) = x_i + y_i \) and multiply by \( \Delta x = 1\) and \( \Delta y = 1\). Sum these volumes to approximate.
07

Calculate for Part b

Points such as (1.5,2.5) give \(F = 4\). Total sum for all subregions yields a volume of 27.
08

Define Subregions for Part c

Consider \( F(x, y) = x \ln y \) in \(0 \leq x \leq 3\) and \(1 \leq y \leq 3\). Split x as \([0, 1), [1, 2), [2, 3)\) and y as \([1, 2), [2, 3)\), thus forming 6 subregions.
09

Select Points and Calculate Volumes for Part c

Choose center points in each subregion, such as (0.5, 1.5). Find \( F(x,y) = x \ln y \). Calculate \( F(x_i, y_i) \Delta x \Delta y \), where \( \Delta x = 1 \) and \( \Delta y = 1\). Sum these for total volume.
10

Calculate for Part c

Example computation gives \(0.5 \ln (1.5)\) per correct choice and similarly sum for all. The total approximate volume is around 2.079.
11

Define Subregions for Part d

In the case \( F(x, y) = e^{-x-y} \) with \(0 \leq x \leq 1\) and \(0 \leq y \leq 1\), split as \([0, 0.5), [0.5, 1)\) for both x and y, yielding 4 subregions.
12

Select Points and Calculate Volumes for Part d

Choose midpoints like (0.25, 0.25), compute \( F(x_i, y_i) = e^{-x_i-y_i} \). Then calculate \( F(x_i, y_i) \times \Delta x \times \Delta y\), \( \Delta x = 0.5, \Delta y = 0.5 \). Sum these values across all subregions.
13

Calculate for Part d

Evaluating at each midpoint, e.g., \(e^{-0.25-0.25} = e^{-0.5}\), sum up gives a total approximate volume of around 0.36.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Subregions in Volume Approximation
To approximate the volume of a region in multivariable calculus, we first need to divide the domain into smaller, manageable parts called subregions. Each subregion acts like a small rectangle or box in the two-dimensional space of the function's domain.
By breaking complex shapes into these simpler elements, we achieve a more accurate approximation of the total volume.
When dividing the domain:
  • Define intervals for each variable (like x and y) within the given limits.
  • Ensure that your subdivisions cover the entire range specified in the problem.
  • The number of subregions chosen affects the accuracy: more subregions give a better approximation.
This method allows for a step-by-step approach, focusing on smaller areas that are easier to calculate.
Understanding Surface Integrals
Surface integrals extend the concept of integration from two dimensions to three by considering the surface area within a region. Unlike simple area integrals, surface integrals account for changes across a surface in three-dimensional space.
They involve integrating over both the x and y directions, and the resultant volume approximation represents the 'weight' or total influence of these combined areas.
When approaching surface integrals:
  • Each piece of the surface contributes a small volume element, similar to a tiny box extending upwards.
  • Total volume is the sum of these small volumes over the entire region.
Surface integrals are essential in fields like physics and engineering where they are used to calculate fluxes and other cumulative properties of fields and surfaces.
Numerical Methods for Volume Calculation
Numerical methods provide practical techniques to approximate complex problems, such as calculating volumes under irregular surfaces. These methods are essential when exact solutions are difficult or impossible to find analytically.
Some common numerical methods include:
  • Rectangle (or midpoint) rule: Divides the area into rectangles and estimates the area with midpoints' values.
  • Trapezoidal rule: Uses trapezoids instead of rectangles to get a more accurate fit.
  • Simpson's rule: Applies parabolic segments for even more precision.
For exact steps, using a combination like you see in rectangle rules can provide a simple yet effective approach to estimating volumes of regions defined by functions of more than one variable.
Delving Into Multivariable Calculus
Multivariable calculus extends single-variable calculus into higher dimensions, making it possible to handle functions of several variables simultaneously. This branch of calculus provides tools like partial derivatives and multiple integrals that help in analyzing functions with more complexity.
In the context of volume approximation, multivariable calculus is essential for:
  • Identifying how changes in one variable affect the whole region.
  • Allowing integration over complex, multi-dimensional surfaces.
  • Applying techniques to find volumes, centers of mass, and other geometric properties in two or three dimensions.
Understanding these principles is crucial as they form the basis for many applied problems in engineering, physics, and economics, where multi-faceted interactions between variables occur.

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Most popular questions from this chapter

Find the point of the sphere \(x^{2}+y^{2}+z^{2}=25\) that is closest to (3,4,5) .

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