Chapter 12: Problem 4
Show that the following functions are invertible.
a. \(\quad F(t)=e^{t}\)
b. \(\quad F(t)=\tan t, \quad-\frac{\pi}{2}
Short Answer
Expert verified
All functions are invertible, with respective inverses: \(F^{-1}(y) = \ln y, \tan^{-1}(y), e^y,\) and \(5-y^2\).
Step by step solution
01
Verify that \( F(t) = e^t \) is one-to-one
To show that \( F(t) = e^t \) is invertible, we need to verify that it's a one-to-one function. A function is one-to-one if, for all \( a, b \) in its domain, \( F(a) = F(b) \) implies \( a = b \). Consider \( F(a) = e^a \) and \( F(b) = e^b \). If \( e^a = e^b \), then by taking the natural logarithm of both sides, we get \( a = b \). Hence, \( F(t) = e^t \) is one-to-one.
02
Find inverse of \( F(t) = e^t \)
Since \( F(t) = e^t \) is one-to-one, it is invertible. Its inverse can be found by solving \( y = e^t \) for \( t \), which yields \( t = \ln y \). Therefore, the inverse function is \( F^{-1}(y) = \ln y \).
03
Verify that \( F(t) = \tan t \) is one-to-one in \( -\frac{\pi}{2} < t < \frac{\pi}{2} \)
For \( F(t) = \tan t \) to be invertible, it must be one-to-one in the specified interval. The tan function is strictly increasing in \( -\frac{\pi}{2} < t < \frac{\pi}{2} \). Therefore, if \( \tan(a) = \tan(b) \), and \( a, b \) are within the interval, then \( a = b \). Thus, \( F(t) = \tan t \) is one-to-one and hence invertible.
04
Find inverse of \( F(t) = \tan t \)
Since \( F(t) = \tan t \) is one-to-one, its inverse can be found by solving \( y = \tan t \) for \( t \). This leads to \( t = \tan^{-1}(y) \). Therefore, the inverse function is \( F^{-1}(y) = \tan^{-1}(y) \).
05
Verify that \( F(t) = \ln t \) is one-to-one in \( t > 0 \)
To show that \( F(t) = \ln t \) is invertible, we check if it's one-to-one over \( t > 0 \). Since \( \ln t \) is strictly increasing for \( t > 0 \), it is one-to-one. This means that if \( \ln(a) = \ln(b) \), then \( a = b \). Hence \( F(t) = \ln t \) is invertible.
06
Find inverse of \( F(t) = \ln t \)
Because \( F(t) = \ln t \) is one-to-one, it is invertible. This inverse is obtained by solving \( y = \ln t \) for \( t \), resulting in \( t = e^y \). Thus, the inverse function is \( F^{-1}(y) = e^y \).
07
Verify that \( F(t) = \sqrt{5-t} \) is one-to-one in \( t \leq 5 \)
To prove that \( F(t) = \sqrt{5-t} \) is invertible, we need to demonstrate it is one-to-one over \( t \leq 5 \). As \( t \) increases, \( 5 - t \) decreases, and consequently \( \sqrt{5-t} \) decreases, making it a decreasing function in this interval, thus one-to-one.
08
Find inverse of \( F(t) = \sqrt{5-t} \)
Since \( F(t) = \sqrt{5-t} \) is one-to-one, we find its inverse by solving \( y = \sqrt{5-t} \) for \( t \). Squaring both sides gives \( y^2 = 5 - t \), leading to \( t = 5 - y^2 \). The inverse function is \( F^{-1}(y) = 5 - y^2 \).
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
One-to-One Functions
The concept of a one-to-one function is crucial in determining if a function is invertible. A function is classified as one-to-one if, whenever two inputs produce the same output, those inputs must be identical. In mathematical terms, for a function \( F \), if \( F(a) = F(b) \) implies \( a = b \), then \( F \) is one-to-one.
Consider the exponential function \( F(t) = e^t \). For this function, if \( e^a = e^b \), applying the natural logarithm to both sides leads to \( a = b \). Thus, \( e^t \) is one-to-one. Similarly, the natural logarithm function \( F(t) = \ln t \) is strictly increasing for \( t > 0 \), meaning it cannot take the same value for two different inputs, proving it is one-to-one as well.
Trigonometric functions like \( F(t) = \tan t \) are one-to-one in restricted intervals, e.g., \(-\frac{\pi}{2} < t < \frac{\pi}{2}\), where \( \tan t \) is strictly increasing. Functions such as \( F(t) = \sqrt{5-t} \) decrease over certain domains (\( t \leq 5 \)) and are thus one-to-one.
Consider the exponential function \( F(t) = e^t \). For this function, if \( e^a = e^b \), applying the natural logarithm to both sides leads to \( a = b \). Thus, \( e^t \) is one-to-one. Similarly, the natural logarithm function \( F(t) = \ln t \) is strictly increasing for \( t > 0 \), meaning it cannot take the same value for two different inputs, proving it is one-to-one as well.
Trigonometric functions like \( F(t) = \tan t \) are one-to-one in restricted intervals, e.g., \(-\frac{\pi}{2} < t < \frac{\pi}{2}\), where \( \tan t \) is strictly increasing. Functions such as \( F(t) = \sqrt{5-t} \) decrease over certain domains (\( t \leq 5 \)) and are thus one-to-one.
Inverse Functions
An inverse function essentially undoes the work of the original function. For a function to have an inverse, it must first be one-to-one. The inverse function, notationally expressed as \( F^{-1} \), takes output values of \( F \) and returns them to their original inputs.
To find the inverse of \( F(t) = e^t \), you solve \( y = e^t \) for \( t \), which results in \( t = \ln y \). Hence, the inverse function is \( F^{-1}(y) = \ln y \). For \( F(t) = \tan t \), solving \( y = \tan t \) gives \( t = \tan^{-1}(y) \), so \( F^{-1}(y) = \tan^{-1}(y) \).
Similarly, the inverse of the function \( F(t) = \ln t \) is found by solving \( y = \ln t \), resulting in \( t = e^y \). Therefore, \( F^{-1}(y) = e^y \). For \( F(t) = \sqrt{5-t} \), by squaring \( y = \sqrt{5-t} \), solving for \( t \) results in \( t = 5 - y^2 \). Thus, \( F^{-1}(y) = 5 - y^2 \).
To find the inverse of \( F(t) = e^t \), you solve \( y = e^t \) for \( t \), which results in \( t = \ln y \). Hence, the inverse function is \( F^{-1}(y) = \ln y \). For \( F(t) = \tan t \), solving \( y = \tan t \) gives \( t = \tan^{-1}(y) \), so \( F^{-1}(y) = \tan^{-1}(y) \).
Similarly, the inverse of the function \( F(t) = \ln t \) is found by solving \( y = \ln t \), resulting in \( t = e^y \). Therefore, \( F^{-1}(y) = e^y \). For \( F(t) = \sqrt{5-t} \), by squaring \( y = \sqrt{5-t} \), solving for \( t \) results in \( t = 5 - y^2 \). Thus, \( F^{-1}(y) = 5 - y^2 \).
Exponential Functions
Exponential functions have the form \( F(t) = a^t \), where \( a \) is a positive constant. They exhibit rapid growth and are one-to-one across their entire domain of \( t \). The particular case \( e^t \), where \( e \) is Euler's number (approximately 2.718), is frequently encountered in mathematics and exhibits all the properties of general exponential functions.
Exponential functions are strictly increasing, ensuring their one-to-one nature. This strict monotonicity is what makes functions like \( F(t) = e^t \) invertible, as no two different input values will produce the same output.
The inverse of the exponential function \( e^t \) is \( \, \ln x \), where \( \ln \) denotes the natural logarithm, which returns the power to which \( e \) must be raised to obtain a given number. Exponential functions are widely used in various fields such as finance, natural sciences, and statistics due to their properties.
Exponential functions are strictly increasing, ensuring their one-to-one nature. This strict monotonicity is what makes functions like \( F(t) = e^t \) invertible, as no two different input values will produce the same output.
The inverse of the exponential function \( e^t \) is \( \, \ln x \), where \( \ln \) denotes the natural logarithm, which returns the power to which \( e \) must be raised to obtain a given number. Exponential functions are widely used in various fields such as finance, natural sciences, and statistics due to their properties.
Trigonometric Functions
Trigonometric functions relate the angles of a triangle to the lengths of its sides. They include functions like sine, cosine, and tangent. For our exploration of invertible functions, focus on the tangent function \( F(t) = \tan t \).
The tangent function is periodic and generally not one-to-one over its entire domain. However, when restricted to the interval \( -\frac{\pi}{2} < t < \frac{\pi}{2} \), \( \tan t \) is strictly increasing, making it one-to-one and hence invertible over this interval.
The inverse of \( \tan t \) is known as the arctangent function, denoted \( \tan^{-1}(x) \) or \( \text{atan}(x) \). Finding the inverse involves solving \( y = \tan t \) for \( t \), yielding \( t = \tan^{-1}(y) \). Understanding these concepts is vital in fields like physics and engineering, where trigonometric functions model cyclical phenomena.
The tangent function is periodic and generally not one-to-one over its entire domain. However, when restricted to the interval \( -\frac{\pi}{2} < t < \frac{\pi}{2} \), \( \tan t \) is strictly increasing, making it one-to-one and hence invertible over this interval.
The inverse of \( \tan t \) is known as the arctangent function, denoted \( \tan^{-1}(x) \) or \( \text{atan}(x) \). Finding the inverse involves solving \( y = \tan t \) for \( t \), yielding \( t = \tan^{-1}(y) \). Understanding these concepts is vital in fields like physics and engineering, where trigonometric functions model cyclical phenomena.