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Solve the initial-value problem. $$ y^{\prime}=x \sin x, y(0)=3 $$

Short Answer

Expert verified
The particular solution is \[y = -x \cos x + \sin x + 3 \]

Step by step solution

01

Identify the type of differential equation

Recognize that the given differential equation is a first-order ordinary differential equation in the form \(y' = f(x)\), where \(f(x) = x \sin(x)\).
02

Integrate both sides

To solve for \(y\), integrate both sides of the equation with respect to \(x\). This gives:\[ y = \int x \sin x \ dx \]
03

Use integration by parts

To find the integral of \(x \sin x\), apply the integration by parts formula: \[ \int u \ dv = uv - \int v \ du \] where \(u = x\) and \(dv = \sin x \ dx\). Consequently, \(du = dx\) and \(v = -\cos x\). Therefore,\[ \int x \sin x \ dx = -x \cos x - \int -\cos x \ dx \]
04

Simplify the integral

Simplify and solve the integral:\[ \int x \sin x \ dx = -x \cos x + \int \cos x \ dx \]\[ = -x \cos x + \sin x + C \]
05

Incorporate the initial condition

Use the initial condition \(y(0) = 3\) to determine the constant of integration \(C\). Substitute \(x = 0\) and \(y = 3\) into the general solution:\[ 3 = -0 \cos 0 + \sin 0 + C \]\[ 3 = 0 + 0 + C \]\[ C = 3 \]
06

Write the particular solution

Incorporate the constant \(C\) into the general solution to obtain the particular solution:\[ y = -x \cos x + \sin x + 3 \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

initial-value problem
An initial-value problem (IVP) in differential equations is one where we have not only the differential equation but also an initial condition that specifies the value of the unknown function at a particular point. For example, in our problem, we need to solve the differential equation given by: \( y^{\text{prime}}=x \text{sin} x \) with the initial condition \( y(0)=3 \). The initial condition ensures a unique solution to the differential equation. This unique solution is found by first solving the differential equation generally and then applying the specific initial value to find the particular constant of integration.
Integration by parts
Integration by parts is a useful technique for solving integrals where the standard methods (like substitution) don't easily apply. The formula for integration by parts is: \ \( \ {\int} u \, dv = uv - \int v \, du \). Let's apply this to our integral \( \int x \text{sin} x dx \). In our case, we set: \ \(u = x \)\t, then \( du = dx \)\t, \(dv = \text{sin} x \, dx \)\t, and \(v = -\text{cos} x \).\ Substituting these into our formula, we get: \ \( \int x \text{sin} x \, dx = -x \text{cos} x - \int -\text{cos} x \, dx \). This simplifies further to: \ \( -x \text{cos} x + \text{sin} x + C \), where \( C \) is the constant of integration. This is how we integrate a product of functions, which is often useful in solving differential equations.
Ordinary differential equations
Ordinary differential equations (ODEs) involve functions of a single variable and their derivatives. These are distinct from partial differential equations, which involve multiple variables. ODEs can be either 'ordinary' or 'partial' – in this case, we are dealing with an ordinary differential equation, specifically a first-order ODE. The form of the equation we are solving here is \( y^{\text{prime}} = f(x) \), where \( f(x) = x \text{sin} x \). First-order indicates that the highest derivative is the first derivative (\( y^{\text{prime}} \)). Solving first-order ODEs often involves: identifying the type of ODE, performing an integration, and applying initial conditions as given.

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Most popular questions from this chapter

A certain harvested population satisfies the differential equation $$y^{\prime}=2 y\left(1-\frac{y}{20}\right)\left(\frac{y}{5}-1\right)-\frac{7 y}{25}.$$ a) Explain how the numbers \(2,20,5\), and \(7 / 25\) affect the size of the population. b) Find the equilibrium values of the differential equation, and assess the stability of each. c) Is the asymptotically stable equilibrium value less than or greater than \(20 ?\) Explain this result biologically. d) Is the unstable equilibrium value less than or greater than'5? Explain this result biologically.

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In psychology, the WeberFechner model of stimulus-response asserts that the rate of change \(d R / d S\) of the reaction \(R\) with respect to a stimulus \(S\) is inversely proportional to the stimulus. That is, $$ \frac{d R}{d S}=\frac{k}{S}, $$ where \(k\) is some positive constant. We also assume that \(S>0\). Let \(S_{0}\) be the detection threshold value, so that \(R\left(S_{0}\right)=0 .\) Solve for \(R\) as a function of \(S\). Your answer will involve \(k\) and \(S_{0}\).

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